Replacing multiple placeholders in a string

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I have a string with 2 placeholders, that I want to replace on runtime based on value calculations. what is the best way to do this. I have used the code below for single placeholder replacement,

   String posttData = @"data = google.visualization.arrayToDataTable([
                                ['Label', 'Value'],
                                ['Result', {0}]                           
    var options = {
        width: 1200, height: 500, redFrom: 90, redTo: 100, yellowFrom: 75, yellowTo: 90, minorTicks: 5

....result calculation

var x = posttData.Replace("{0}", result.ToString());
ScriptManager.RegisterStartupScript(this, this.GetType(), "test", x, true);

How do I do the same for multiple replacements? if I need to add another option,

var options = {
                   width: 1200, height: 500, redFrom: 90, redTo: 100, yellowFrom: 75, yellowTo: 90, minorTicks: 5, max: {1}

How about the String.Format?

String str = String.Format(@"Some value {0} and some value {1}", 1, 2);

Should yield:

Some value 1 and some value 2

You can replace 1 and 2 with whatever results you might need.

String Replacement With Named String Placeholders, Format method to help when concatenating strings. This is great for simple string replacement but the "anonymous" nature of the placeholders� I have a string which looks like this: 'I want a {Crust} crust {Type} pizza' {Crust} and {Type} are placeholders in the string and I would like to replace the {Crust} and {Type} value with their actual values which are of type string array.

I a;ways create an extension method for easier usage.

 public static class StringExtensions
        public static string FormatWith(this string source, params object[] args)
            return string.Format(source, args);

and call

"Some value {0} and some value {1}".FormatWith(1,2);

JavaScript, This method searches a string for a defined value, or a regular expression, and returns a new string with the replaced defined value. Syntax:. I am sure that we have all used the String.Format method to help when concatenating strings. This is great for simple string replacement but the "anonymous" nature of the placeholders can make it confusing with larger operations. I have developed a string helper that lets you used named string placeholders that you pass into a string method.

var result = string.Format(postData,data1.ToString(), data2.ToString());

How to modify string contents, Replace text. The following code creates a new string by replacing existing text with a substitute. C# Copy. Replace a portion of a string of text with another string. Description. The Replace function identifies the text to replace by starting position and length. The Substitute function identifies the text to replace by matching a string. If more than one match is found, you can replace all of them or specify one to replace. If you pass a single

I would suggest to use string interpolation:

$"Some value {1} and some value {2}"

where "1" and "2" can be whatever result/expression you need.

replace - Documentation - Twig, replace �. The replace filter formats a given string by replacing the placeholders ( placeholders are free-form):. 1 2 3 4 5 6 7 8 9 10. {{ "I like %this% and %that%. This is just a more concise recap of F.J and MiniQuark great answers. All you need to achieve multiple simultaneous string replacements is the following function:. def multiple_replace(string, rep_dict): pattern = re.compile("|".join([re.escape(k) for k in sorted(rep_dict,key=len,reverse=True)]), flags=re.DOTALL) return pattern.sub(lambda x: rep_dict[], string)

Find and replace one or more substrings, with new . If old contains multiple substrings, then new either must be the same size as old , or must be a single substring. Replace placeholder text in a list of file names. Replace <ROOT_DIR> with a string that is the name of a file path. If your replacement values contain user-input, a safer solution is to use the strtr function instead of str_replace to avoid re-replacing any placeholders that may show up in your values.

That is, when str and old both contain the empty character vector ('') or the empty string(""), strrep does not replace empty character vectors or strings with the contents of new. Before replacing text, strrep finds all instances of old in str, like the strfind function. For overlapping patterns, strrep performs multiple replacements.

The replace() method returns a new string with some or all matches of a pattern replaced by a replacement. The pattern can be a string or a RegExp, and the replacement can be a string or a function to be called for each match. If pattern is a string, only the first occurrence will be replaced.