How to match a substring in a string, ignoring case

I'm looking for ignore case string comparison in Python.

I tried with:

if line.find('mandy') >= 0:

but no success for ignore case. I need to find a set of words in a given text file. I am reading the file line by line. The word on a line can be mandy, Mandy, MANDY, etc. (I don't want to use toupper/tolower, etc.).

I'm looking for the Python equivalent of the Perl code below.

if ($line=~/^Mandy Pande:/i)

If you don't want to use str.lower(), you can use a regular expression:

import re

if'mandy', 'Mandy Pande', re.IGNORECASE):
    # Is True

How to match a substring in a string, ignoring case, There are many ways to check if a String contains a substring. In this article, we'll be looking for substrings within a String while focusing on case-� check if a string contains another substring; Match exact substring inside string; case-insensitive match "in" and "not in" operators. The operators in and not in test for membership in Python. This is the best and most used method to check if Python string contains another string.

There's another post here. Try looking at this.

BTW, you're looking for the .lower() method:

string1 = "hi"
string2 = "HI"
if string1.lower() == string2.lower():
    print "Equals!"
    print "Different!"

Case-Insensitive String Matching in Java, Ignore case. If you want to create a case-insensitive script, you can use the lower function. It will cast all characters in a string to lowercase. The toLoweCase() method of the String class converts all the characters in the current String into lower case and returns. To find whether a String contains a particular sub string irrespective of case − Get the String. Get the Sub String. Convert the string value into lower case letters using the toLowerCase() method, store it as fileContents.

a = "MandY"
alow = a.lower()
if "mandy" in alow:
    print "true"

work around

String contains a substring in Python, const str = 'arya stark'; // The most concise way to check substrings ignoring case is using // `String#match()` and a case-insensitive regular� In this tutorial, we looked at a few different ways to check a String for a substring, while ignoring the case in Java.. We looked at using String.toLowerCase() and toUpperCase(), String.matches(), String.regionMatches(), Apache Commons StringUtils.containsIgnoreCase(), and Pattern.matcher().find().


if haystackstr.lower().find(needlestr.lower()) != -1:
  # True

Check if a String Contains a Substring in JavaScript, If str and expression are string arrays or cell arrays, they must have the same dimensions. Data Types: string | char | cell. 4.Using string.match() method: To check if a string contains substring or not, use the Javascript match method. Javascript match method accepts a regular expression as a parameter and if the string contains the given substring it will return an object with details of index, substring, input, and groups.

import re
if'(?i)Mandy Pande:', line):

Match regular expression (case insensitive), Idiom #133 Case-insensitive string contains. Set boolean ok to true if string word is contained in string s as a substring, even if the case doesn't match, or to false� How to check if a String contains another String in a case insensitive manner in Java? Java 8 Object Oriented Programming Programming One way to do it to convert both strings to lower or upper case using toLowerCase() or toUpperCase() methods and test.

Case-insensitive string contains, in Go, If str and expression are string arrays or cell arrays, they must have the same dimensions. Data Types: string | char | cell. The string.Contains() method in C# is case sensitive. And there is not StringComparison parameter available similar to Equals() method, which helps to compare case insensitive. If you run the following tests, TestStringContains2() will fail. [TestMethod] public void TestStringContains {var text = "This is a sample string"; Assert. IsTrue (text.

Match regular expression (case insensitive), is an element of the list of strings that matches the string character for character . Case insensitive string comparison ignores capitalization of characters. Use the in operator with the str.lower() function and a generator expression to check if a� Compare strings by ignoring case using Python. Suppose we have two strings i.e. firstStr = "SAMple" secStr = "sample" As both the strings has similar characters but in different case. So to match these strings by ignoring case we need to convert both strings to lower case and then match using operator == i.e.

How to check if a string is in a list of strings, ignoring case, in Python, Ignore case of match. This function specifies that a pattern should ignore the case of matches. Keywords: character. Usage. Arguments. To check if a given string or a character exists in an another string or not in case insensitive manner i.e. by ignoring case, we need to first convert both the strings to lower case then use “ïn” or “not ïn” operator to check the membership of sub string.For example,

  •, string, flags=0) Scan through string looking for the first location where the regular expression pattern produces a match, and return a corresponding match object. Return None if no position in the string matches the pattern; note that this is different from finding a zero-length match at some point in the string.
  • No he's not. " [i don't want to use toupper/tolower etc.]"
  • i know, i read, but the re.match and solutions don't check for special characters used in regex such as () or []
  • what have () or [] to do with the question?
  • This is not a more general answer, because tolower/toupper solutions are inappropriate for Unicode.
  • if you don't really need to avoid it (for some reason like unicode), maching with lower() can be much more efficient than regex match.
  • this doesn't check / match for control characters in for regexp like [] or () if i'm not wrong...
  • OP said "I don't want to use toupper/tolower, etc."