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select firstname, lastname, birth_date from project.faculty where TO_CHAR(birth_date,'Sun') = 'Jan'
I need help and everything I try does not work.
Assuming birth_date is a DATE data type:
TO_CHAR function: TO_CHAR(datetime, format)
select firstname, lastname, birth_date from project.faculty where TO_CHAR(birth_date,'DY') = 'Sun'
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Why do you store dates into a varchar2 column ("size of day is 9 characters long")? Bad, bad idea.
SQL> with faculty (first_name, last_name, birth_date) as 2 (select 'Little', 'Foot', '23-07-2013' from dual union all 3 select 'Big' , 'Foot', '01-12-2019' from dual 4 ) 5 select first_name, last_name, birth_date, 6 to_char(to_date(birth_date, 'dd-mm-yyyy'), 'dy') day 7 from faculty 8 where to_char(to_date(birth_date, 'dd-mm-yyyy'), 'dy') = 'sun'; FIRST_ LAST BIRTH_DATE DAY ------ ---- ---------- ------------ Big Foot 01-12-2019 sun SQL>
If birth date was a date (as it should be), then it gets somewhat simpler:
<snip> 5 select first_name, last_name, birth_date, 6 to_char(birth_date, 'dy') day 7 from faculty 8 where to_char(birth_date, 'dy') = 'sun'; FIRST_ LAST BIRTH_DATE DAY ------ ---- ---------- ------------ Big Foot 2019-12-01 sun SQL>
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CREATE TABLE faculty ( firstname, lastname, birth_date ) AS SELECT 'Alice', 'Adams', DATE '2019-01-01' FROM DUAL UNION ALL SELECT 'Betty', 'Burns', DATE '2019-01-02' FROM DUAL UNION ALL SELECT 'Carol', 'Charles', DATE '2019-01-03' FROM DUAL UNION ALL SELECT 'Denise', 'Daniels', DATE '2019-01-04' FROM DUAL UNION ALL SELECT 'Erin', 'Edwards', DATE '2019-01-05' FROM DUAL UNION ALL SELECT 'Frances', 'Firth', DATE '2019-01-06' FROM DUAL UNION ALL SELECT 'Gabriella', 'Gambon', DATE '2019-01-07' FROM DUAL;
Query 1 -
DAY format model:
If you use
TO_DATE( birth_date, 'DAY' ) then the result will be a fixed-length string.
WEDNESDAY is 9 characters and any other day will be right-padded with space characters to be the same length. So you want:
select firstname, lastname, birth_date from /*project.*/faculty where TO_CHAR( birth_date, 'DAY' ) = 'SUNDAY ';
Query 2 -
fmDAY format model:
To get rid of the trailing spaces you can use the
fm format modifier:
select firstname, lastname, birth_date from /*project.*/faculty where TO_CHAR( birth_date, 'fmDAY' ) = 'SUNDAY';
Query 3 -
DY format model:
You can compare on the abbreviated day that is the first 3 characters using the
DY format model:
select firstname, lastname, birth_date from /*project.*/faculty where TO_CHAR( birth_date, 'DY' ) = 'SUN';
Query 4 - Specify the language you are using:
All the above queries will fail if the user changes the
NLS settings (which all users can do in their own session any time they want) using something like:
ALTER SESSION SET NLS_DATE_LANGUAGE = 'FRENCH';
To combat this, you can use the 3rd argument of
TO_DATE to specify the
NLS settings that you are expecting:
select firstname, lastname, birth_date from /*project.*/faculty where TO_CHAR( birth_date, 'DY', 'NLS_DATE_LANGUAGE=ENGLISH' ) = 'SUN';
Query 5 -
TRUNC( date_value, 'IW' ) is independent of the NLS settings:
If you want a query that is entirely independent of any NLS settings then you can find the number of full days since the start of the iso-week:
select firstname, lastname, birth_date from /*project.*/faculty where TRUNC( birth_date ) - TRUNC( birth_date, 'IW' ) = 6;
All the above queries output:
FIRSTNAME | LASTNAME | BIRTH_DATE :-------- | :------- | :--------- Frances | Firth | 06-JAN-19
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- Hi Cam456, welcome to StackOverflow. "Everything I try does not work" could mean a number of things. Can you be more specific, and include any error message(s) you are getting?
- All your dates are 10 characters long.
- I have no idea what those "9 caracters" represent, @MT0. Could be anything. The idea is here, shouldn't be too difficult to apply desired format mask. At least, I hope so.