How can I know if a SwiftUI Button is enabled/disabled?

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There is no isEnabled property for a SwiftUI button. How can i tell if it is enabled?

In regular UIKit, i would simply do

if button.isEnabeld == true {
} else {

but there is no SwiftUI equivalent.

The whole idea of SwiftUI, is to avoid duplication of the source of truth. You need to think differently, and consider where the source of truth is. This is where you need to go to find out the button's state. Not from the button itself.

In "Data Flow Through SwiftUI", at minute 30:50, they explain that every piece of data has a single source of truth. If your button gets its state from some @Binding, @State, @EnvironmentObject, etc, your if statement should get that information from the same place too, not from the button.

Enabling and disabling elements in forms, SwiftUI lets us disable any part of its forms or even the whole form, and one containing a button that is enabled only when the toggle is on: As you can see, the button is disabled just by adding disabled(!agreedToTerms) to� I used to Hybrid_App WKWebview Swift 5.1 SwiftUI. I want to create floating button can move anywhere over WKWebview.

Inside a view, if you wish to react to the state set by .disabled(true), you can use: @Environment(\.isEnabled) var isEnabled

Since the environment can be used from within a View or a ViewModifier, this can be used to change layout properties of a view based on the state set from outside.

Unfortunately, ButtonStyle cannot directly use @Environment, but you can use a ViewModifier to inject environment values into a ButtonStyle in order to use the value from within a ButtonStyle:

// First create a button style that gets the isEnabled value injected
struct MyButtonStyle: ButtonStyle {
    private let isEnabled: Bool
    init(isEnabled: Bool = true) {
        self.isEnabled = isEnabled
    func makeBody(configuration: Configuration) -> some View {
        return configuration
            .background(isEnabled ? .green : .gray)
            .foregroundColor(isEnabled ? .black : .white)

// Then make a ViewModifier to inject the state
struct MyButtonModifier: ViewModifier {
    @Environment(\.isEnabled) var isEnabled
    func body(content: Content) -> some View {
        return content.buttonStyle(MyButtonStyle(isEnabled: isEnabled))

// Then create a convenience function to apply the modifier
extension Button {
    func styled() -> some View {
        ModifiedContent(content: self, modifier: MyButtonModifier())

// Finally, try out the button and watch it respond to it's state
struct ContentView: View {
    var body: some View {
        Button("Test", {}).styled().disabled(true)

You can use this method to inject other things into a ButtonStyle, like size category and theme.

I use it with a custom style enum that contains all the flavours of button styles found in our design system.

disable button in swiftui Code Example, Xcode / iOS: How to determine whether code is running in DEBUG / RELEASE build? xcode macosx have view resize when window size� I think that the View.disabled(_:) modifier changes the .foregroundColor of a View (besides enabling / disabling interactions with it). Could the color change be animated? I know it's pretty easy to

From outside a view you should know if you used .disabled(true) modifier.

From inside a view you can use @Environment(\.isEnabled) to get that information:

struct MyButton: View {
    let action: () -> Void
    @Environment(\.isEnabled) private var isEnabled

    var body: some View {
        Button(action: action) {
        .foregroundColor(isEnabled ? .green : .gray)

struct MyButton_Previews: PreviewProvider {
    static var previews: some View {
        VStack {
            MyButton(action: {})
            MyButton(action: {}).disabled(true)

disabled(_:), Adds a condition that controls whether users can interact with this view. the button isn't interactive because the outer disabled(_:) modifier overrides the inner � If a button is pushed and then one variety of other buttons is pushed then certain options on the program will become "greyed out". Ie they can no longer be selected. I assume i need to create an event from the first button being pushed and then do if statements depending which button is pushed next (IE. First Button is pushed, If Button 2 is

isEnabled, Setting this property to false adds the disabled flag to the control's state bitmask; enabling the control again removes that flag. The default value of this property is � The only thing I can see is some quazi-name in the Name Box: for instance, for the first option button in one of the groups the Name Box shows me "Option Button 222". You can see the name of your option box by right clicking the sheet and selecting view code.

SwiftUI: Button Styles | Will Townsend, I've recently been diving into SwiftUI in a new project. Overall Button("System Button") { print("tapped") return } .disabled(true) And you can also see the behaviour that the Button view provides while pressing and dragging around the view. isEnabled) var isEnabled let configuration: ScaleButtonStyle. Custom trait collections. 9. Live Preview. Live preview provided by SwiftUI (available only since macOS Catalina). The only problem we have is that since names of views are the same in UIKitPlus and SwiftUI we should use aliases like UButton for Button or UView for View, so everything with U prefix.

How to check a button is disabled using Cypress, and this will allow me to check if buttons are disabled or not. Didn't even shows examples how you can use should() to verify elements are enabled/disabled:� The current UISwitch in iOS 13 looks like this and I want to give the UISwitch an inner shadow (using SwiftUI NOT UIKit) so it looks like this but I have no idea how I would go about doing so.

  • are you using any library ? share details code .
  • I am using SwiftUI released by Apple Xcode 11 Beta (no external library). There is a Button. I want to know how to tell if it enabled/disabled. There is no code to add. The question is literally this simple.
  • @MartinR i can use this if i am going to set the button’s state my self. But in this case, the button’s state is already set at some other point in my code. The button is now passed to functionX. Now Inside functionX, I wanted to know what is the state of the button?
  • The button state is generated from your app state. Check the app state, don't check state of UI.
  • I don't know a better way to say this, but it's only more complicated if you don't think in terms of "push" instead of "pull". It sounds like you're fighting a base concept of SwiftUI. As @sulthan said, why should you query the UI about something that is owned by the app?
  • based on the comments above, i think you are correct. Thanks, i will rethink my logic
  • You're welcome. If you haven't already, the 37 minutes of the WWDC session Data Flow Through SwiftUI is time well spent. You will probably save a lot of time down the road. Highly recommended! Cheers.
  • To be honest, this works in every type of UI, including Cocoa/CocoaTouch. It's not really a different type of thinking, it's about clear distinctions.
  • @Sulthan You're totally right, the difference is SwiftUI enforces it, as it does not make the disable status available.
  • Then how does the Apple provided PlainButtonStyle know the state of the button?
  • Nice answer, you can simplify the solution by creating MyButton which takes the configuration as an input. In the MyButtonStyle.makeBody return MyButton(configuration: configuration). Inside the button you can access use the Environment to check if it is enabled. So the MyButton has all the logic, MyButtonStyle is just a wrapper