Check if a circle is contained in another circle

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I'm trying to check if a circle is contained within another circle. I'm not sure if the math behind it is the problem or if its my if statement because I keep getting True for anything I pass.

#Get_center returns (x,y)
#Get_radius returns radius length
def contains(self,circle):
    distance = round(math.sqrt((circle.get_center()[0]-self.get_center()[0])**2 + (circle.get_center()[1] - self.get_center()[1])**2))
    distance_2 = distance + circle.get_radius()
    if distance_2 > distance:
        return True        #Circle 2 is contained within circle 1

I don't know about python but the math is simple. See the below picture

To check if circle 2 inside circle 1,

compute d 
    d = sqrt( (x2-x1)^2 + (y2-y1)^2 );
get c2 and c1
if c1 > ( d + c2 ) 
   circle 2 inside circle 1
   circle 2 not inside circle 1

Check if a circle lies inside another circle or not, I don't know about python but the math is simple. See the below picture. enter image description here. To check if circle 2 inside circle 1, Given two circles with radii and centres given. The task is to check whether the smaller circle lies inside the bigger circle or not. Examples: Input: x1 = 10, y1 = 8, x2 = 1, y2 = 2, r1 = 30, r2 = 10 Output: The smaller circle lies completely inside the bigger circle without touching each other at a point of circumference.

You have distance_2 = distance + circle.get_radius(), so distance_2 will always be higher than distance and distance_2 > distance will always be true.

Check if a circle is contained in another circle, The distance between ⟨xc,yc⟩ and ⟨xp,yp⟩ is given by the Pythagorean theorem as d=√(xp−xc)2+(yp−yc)2. The point ⟨xp,yp⟩ is inside the circle if d<r, on the� A circle is completely within another circle if the center is within the circle and the center + the radius is also within the circle. Let us call (hl, kl) the center of the larger circle that has

If you want strict containment, that means that the absolute value of the difference of radii will be less than the distance between centers. You can exploit that in order to avoid taking square root (because squares of two positive numbers will have the same order as the numbers themselves):

def contains(self,circle):
    distance_squared = (circle.get_center()[0]-self.get_center()[0])**2 + (circle.get_center()[1] - self.get_center()[1])**2
    difference_squared = (self.get_radius() - circle.get_radius())**2
    return (difference_squared < distance_squared) and (self.get_radius() > circle.get_radius())

Btw, just as a style note, there is no need to write getters and setters in Python. You can just have fields and if you need to modify how they are accessed, you can override it later on (without effecting any of the classes which access them).

Making this easy from the earliest versions (maybe even from the start) was one of the reasons Python was so appealing and managed to take off. Python code tends to be very short because of this. So you don't lose sight of the forest for the trees.

How to know if a point is inside a circle?, A circle can be tangent to another circle and be either completely inside that circle, or completely outside of it. When Do Two Circles Intersect? There are three � Check if two given circles touch or intersect each other There are two circle A and B with their centers C1 (x1, y1) and C2 (x2, y2) and radius R1 and R2. Task is to check both circles A and B touch each other or not.

CODE ACCORDING TO THE IMAGE IN THE ACCEPTED ANSWER (without getters, as it's more readable):

import math
def contains(self, circle):
  d = math.sqrt(
        ([0] -[0]) ** 2 +
        ([1] -[1]) ** 2)
  return self.radius  > (d + circle.radius)

I used it, and it works. In the following plot, you can see how the circles completely contained in the red big one are painted in green, and the others in black:

Tangent Circles, That is, to find whether two circles, with known centres and radii, lie completely outside one another, touch each other, intersect at two points, or are such that one lies inside the other. For all these One circle lying inside another. Now let's � code. # Python3 program to check if. # a point lies inside a circle. # or not. def isInside (circle_x, circle_y, rad, x, y): # Compare radius of circle. # with distance of its center. # from given point. if ( (x - circle_x) * (x - circle_x) +.

Relative position of two circles, determine whether the point (-6,-6) is inside, outside, or on the circle centered circle(x Duration: 3:53 Posted: Sep 29, 2016 Imagine a circle. Imagine a pie. Imagine trying to return a bool that determines whether the provided parameters of X, Y are contained within one of those pie pieces. What I know about the arc: I have the CenterX, CenterY, Radius, StartingAngle, EndingAngle, StartingPoint (point on circumference), EndingPoint (point on circumference).

Points inside/outside/on a circle (video), Learn how to find the equation of a circle and use the discriminant to prove for tangency in The equation of a circle can be found using the centre and radius. The discriminant can determine the nature of intersections between two circles or a� Implement the _ contains _ (self, anotherCircle) method that returns True if anotherCircle is contained in this circle. The _ contains _ (self, item) special method is used to implement the membership test operator in. It should return true if item is in self, and false otherwise.

Intersection of two circles - Circles and graphs - Higher Maths , If we find out this, we can check whether the given point is inside the circle. A circular path has N Circles with radii R on it and another circle of unknown radii S � So say we know point1 with coordinates lat1,lng1 is the center of the circle and point2 with coordinates lat2,lng2 is the point we are trying to decide is in the circle or not. We form a right angled triangle using a point determined by point1 and point2. This, point3 would have coordinates lat1,lng2 or lat2,lng1 (it doesn't matter which).

  • Do you mean thoroughly contained ? Or partially?
  • @CroCo The entire circle would have to be contained
  • dont you think self radius should enter the calculation?
  • Any assumptions regarding the circles??
  • @CroCo what do you mean by assumptions?
  • Nice picture, makes answer obvious.
  • Good answer, just going to say you can do it without sqrt: ( (x2-x1)^2 + (y2-y1)^2 ) > ( d + c2 )^2