Product code looks like abcd2343, what to split by letters and numbers

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I have a list of product codes in a text file, on each like is the product code that looks like:

abcd2343 abw34324 abc3243-23A

So it is letters followed by numbers and other characters.

I want to split on the first occurrence of a number.

🧑 🤝🧑 🦃 Product code looks like abcd2343, which is divided into , re.split(pat, s) will split the string s , using pat as the delimiter. Thus, if s ends with a number, you can not end the empty string using re.findall('\d+|\D+', This covers your angular case abc3243-23A and displays abc for a group of letters and� There are two types of barcodes: linear - or 1D, and 2D. The most visually recognizable, the UPC (Universal Product Code) is a linear 1D barcode made up of two parts: the barcode and the 12-digit UPC number. The first six numbers of the barcode is the manufacturer’s identification number. The next five digits represent the item’s number.

import re

m = re.match(r"(?P<letters>[a-zA-Z]+)(?P<the_rest>.+)$",input)

m.group('letters')
m.group('the_rest')

This covers your corner case of abc3243-23A and will output abc for the letters group and 3243-23A for the_rest

Since you said they are all on individual lines you'll obviously need to put a line at a time in input

Splitting strings into numbers (Python), Product code looks like abcd2343, what to split by letters and numbers, Consult the docs for more about Python's regex syntax. re.split(pat, s) will split the string s � UPC-C is a 12-digit code with a product code and a check digit; not in common use. UPC-D is a variable length code (12 digits or more) with the 12th digit being the check digit. These versions are not in common use. UPC-E is a 6-digit code, that has its equivalent in UPC-A 12-digit code with number system 0 or 1.

To partition on the first digit

parts = re.split('(\d.*)','abcd2343')      # => ['abcd', '2343', '']
parts = re.split('(\d.*)','abc3243-23A')   # => ['abc', '3243-23A', '']

So the two parts are always parts[0] and parts[1].

Of course, you can apply this to multiple codes:

>>> s = "abcd2343 abw34324 abc3243-23A"
>>> results = [re.split('(\d.*)', pcode) for pcode in s.split(' ')]
>>> results
[['abcd', '2343', ''], ['abw', '34324', ''], ['abc', '3243-23A', '']]

If each code is in an individual line then instead of s.split( ) use s.splitlines().

How to split a string of space separated numbers into integers?, Product code looks like abcd2343, what to split by letters and numbers, Consult the docs for more about Python's regex syntax. re.split(pat, s) will split the string s � How can I confirm the model and serial numbers for my cooling system? The model and serial number can be found on the rating plate of your air conditioner or heat pump. This is generally found slightly above the refrigerant valves on the back side of the unit.

def firstIntIndex(string):
    result = -1
    for k in range(0, len(string)):
        if (bool(re.match('\d', string[k]))):
            result = k
            break
    return result

Python, The slight modification of regex can provide the flexibility to reduce the number of regex functions required to perform this particular task. The findall function is� E.g., I would like to separate: OS234 to OS and 234 AA4230 to AA and 4230 I have used following trivial solution, but I am quite sure that there should be a more efficient and robust solution .

Try this code it will work fine

import re
text = "MARIA APARECIDA 99223-2000 / 98450-8026"
parts = re.split(r' (?=\d)',text, 1)
print(parts)

Output:

['MARIA APARECIDA', '99223-2000 / 98450-8026']

Split numeric, alphabetic and special symbols from a String , Given a string str, divide the string into three parts one containing a numeric part, one if (ch is a digit) then append it in res1 string. else if (ch is alphabet) append in string res2. If you like GeeksforGeeks and would like to contribute, you can also write an last_page Find count of digits in a number that divide the number. Sample activation code: AX6elp90grPo. Initial Fix. We plan to address the immediate issue by "guessing" which letters and numbers seem easy to confuse with each other and eliminating them, or always using one (e.g., anything that looks like a "1" is always a "1"). Question:

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Comments
  • If you use '(\d+)', and a digit is the last character of the string, the last entry in the list will be an empty string. How do we avoid that?
  • IIUC, you could use re.findall('(\d+|\D+)', 'abcd2343 abw34324 abc3243-23'), which returns ['abcd', '2343', ' abw', '34324', ' abc', '3243', '-', '23'].