Find the first match from a list of words in a string

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I am writing a function that finds a keyword in a string and returns the first match, if any.

The keywords are "what", "when", "who"

Example:

  • The user inputs a string in the form of a question: "Who is John Connor"
  • The function returns "who"

Is there a way to compare a list of keywords against a string input and return the first match?

I thought about using re.search but it takes single string at a time. This is what I have so far:

question = input("Ask me a question: ")
 keywords = ("what", "when", "who")
 question = question.lower()
 match = re.search(r'word:', question) #  re.search seems to take only one string at a time

Convert your list to a regular expression of the form \b(?:what|when|who)\b, then use re.search().

question = input("Ask me a question: ").lower()
keywords = ("what", "when", "who")
kw_re = r'\b(?:' + '|'.join(map(re.escape, keywords)) + r')\b'
match = re.search(kw_re, question)

\b matches word boundaries, so this will only match whole words.

Excel formula: Get first match cell contains, If you have a list of things (words, substrings, etc) and want to find out which of these things appear in a cell, you can build a simple table and use a formula based� When searching a list containing value types, make sure the default value for the type does not satisfy the search predicate. Otherwise, there is no way to distinguish between a default value indicating that no match was found and a list element that happens to have the default value for the type.

Testing a word for inclusion in a set of keywords is O(1) vs. O(n) for a list of n keywords.

def find_match(sentence, keyword_set):
    for word in sentence.split():
        if word in keyword_set:
            return word

keywords = {"what", "when", "who"}
question = "Who is John Connor".lower()
>>> find_match(question, keywords)
'who'

How to get the first word in a string in Python, split() and list indexing to get the first word in a string. Call str.split() to create a list of all words in str separated by a space or newline character. Index the� As I apply the formula on more scenarios I notice some gaps. If I have 'G' and 'Super Six' as separate words in my list and if a cell carries the string value "Super Six Group", the formula matches 'G' as value. It is looking at the first word in the word list than the first match from the string (expected result is 'Super Six').

This will find the fist word in the list and give you the location of it:

question = input("Ask me a question: ")
keywords = ("what", "when", "who")
question = question.lower()

for keyword in keywords:
   loc = question.find(keyword)
   if loc == -1:
      loc = "Not Found"
   else:
       print('{} was found at location: {} and is the first match found in the list of keywords'.format(keyword, loc))
       break

String Manipulation and Regular Expressions, find() and index() are very similar, in that they search for the first occurrence of a is to split on any whitespace, returning a list of the individual words in a string:. Find example. Here we consider the Find() method on List. Find accepts a Predicate, which we can specify as a lambda expression. It returns the first match.Predicate Lambda. Here: This code loops through each int value in the List, starting at the beginning, and tests each one to see if it is greater than 20. Return: The value 23 is returned

Split the input into words and compare each against your set of keywords; break from the loop if a match is found, or return if you want to wrap it into a function.

for word in question.split():
    if word in keywords:
        match = word
        break

Also, take care to handle cases when no match is found.

perlrequick, A regex consisting of a word matches any string that contains that word: "Hello World" =~ /World/ Perl will always match at the earliest possible point in the string: See Backslash sequences in perlrecharclass for details.) \d is a In list context, a match /regex/ with groupings will return the list of matched values ($1, $2,) . Get first match in cell. The language here is quite confusing, but the formula above will return the first match found in the list of things to look for.If instead you want to return the first match found in the cell being tested, you can try a formula like this:

Searching a String for Matching Word from another String in, To search a string for a matching word from another string, we use the "IF", FIND:This function returns the location number of the character at which a specific 2 lists,in column A and column B. Weneed to match the first word in each cell in� re.match() function will search the regular expression pattern and return the first occurrence. This method checks for a match only at the beginning of the string. So, if a match is found in the first line, it returns the match object. But if a match is found in some other line, it returns null.

Python – Find the index of first occurrence of substring in a String, Python String - Find the occurrence of first occurrence of substring - To find the position of first occurrence of a string in another string, you can use string.find()� The Select-String cmdlet searches for text and text patterns in input strings and files. You can use Select-String similar to grep in UNIX or findstr.exe in Windows. Select-String is based on lines of text. By default, Select-String finds the first match in each line and, for each match, it displays the file name, line number, and all text in the line containing the match. You can direct

Python re.match, search Examples, Python program that uses match import re # Sample strings. list = ["dog dot", "do don't", "dumb-dumb", in list: # Match if two words starting with letter d. m = re. match("(d\w+)\W(d\w+)", element) # See if Match just tries the first starting point. Java Java Lambda Expressions Java 8 Streams . Imperative Style. List<String> list = Arrays.asList("Apple", "Orange", "Banana"); String string = "A box of Oranges