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Trying to display * once if required is true in that ingredientgroups but displaying twice

ingredientGroups: Array(2)
[ {isRequired: true,  in: "E", sort: 10}, {isRequired: true, in: "y", sort:1}]
<div>
    {this.props.ingredientGroups.map((ingredientGroup) => {
     return (
       <div id={ 'ff' + ingredientGroup.ingredientGroupId }
         key={ ingredientGroup.ingredientGroupId }
       >     
         {
          (ingredientGroup.isRequired === true) ?
            '*': ''
          }
       </div>  
     );
    })}
</div>
expected: *  

actual :  *  
          *

The reason why 2 * are being printed is because of this condition:

(ingredientGroup.isRequired === true)

Within your ingredientGroups array, both objects have isRequired as true, which is why both are returning true when you iterate through this.props.ingredientGroups using Array.map(), and when the values of isRequired are passed through the above if statement. Hence, 2 *s are being rendered.

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If you're asking why you get two '*' on runtime as a result of the code you have, it's because you're mapping through the ingredientGroups array using map() function and printing either a * or nothing for each element in the array. The array has two elements.

That will result in the code inside the map() function being run for each element and the array and you will end up with two '*' being printed.

Please refer to map().

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My initial thought was that you are mapping through the array. and if its set to true it gives a dot. As there are two items in the array evaluating to true it gives you two *. To test i ran the code

class Application extends React.Component {

  render() {
    return <div>
    {this.props.ingredientGroups.map((ingredientGroup) => {
     return (
       <div id={ 'ff' + ingredientGroup.ingredientGroupId }
         key={ ingredientGroup.ingredientGroupId }
       >     
         {
          (ingredientGroup.isRequired === true) ?
            '*': 'd'
          }
       </div>  
     );
    })}
</div>;
  }
}

/*
 * Render the above component into the div#app
 */
React.render(<Application  ingredientGroups = {[ {isRequired: true,  in: "E", sort: 10}, {isRequired: true, in: "y", sort:1}]} />, document.getElementById('app'));

This got the same issue as you, but the code below works.

class Application extends React.Component {

  render() {
    return <div>
    {this.props.ingredientGroups.map((ingredientGroup) => {
     return (
       <div id={ 'ff' + ingredientGroup.ingredientGroupId }
         key={ ingredientGroup.ingredientGroupId }
       >     
         {
          (ingredientGroup.isRequired === true) ?
            '*': 'd'
          }
       </div>  
     );
    })}
</div>;
  }
}

/*
 * Render the above component into the div#app
 */
React.render(<Application  ingredientGroups = {[ {isRequired: true,  in: "E", sort: 10}]} />, document.getElementById('app'));

If you would like to keep two items in the array I suggest doing one of the following:

ingredientGroups: Array(2)
[ {isRequired: false,  in: "E", sort: 10}, {isRequired: true, in: "y", sort:1}]

OR

<div>
    {this.props.ingredientGroups.map((ingredientGroup) => {
     return (
       <div id={ 'ff' + ingredientGroup.ingredientGroupId }
         key={ ingredientGroup.ingredientGroupId }
       >     
         {
          (ingredientGroup.in === "E") ?
            '*': ''
          }
       </div>  
     );
    })}
</div>

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Comments
  • In the code that works you have used only one object as input.But using two object need to print only one *
  • What do you mean not working? Because the code above should cause only one * to show up. If by not working you mean there is only one object then yes there is only one object if you would like a second object didn’t set one of the items to false. The array looks through both items checks to see if isRequired is true and then does something accordingly.