## Finding number of elements that are greater than their neighbors in a list

write a program to find the numbers which are greater than the given number from an array.

count the number of elements which are greater than any of element on right side of an array

7.6. lists: number of distinct elements

find all peaks in an array

convert array into zig-zag fashion

greatest smaller on left of every element in the array

find peak element in array in c

**Closed.**This question is not reproducible or was caused by typos. It is not currently accepting answers.

**Print all integers that are greater than their left neighbor,** Given a list of numbers, find and print all its elements that are greater than their left neighbor. Example input 1 5 2 4 3. (Using python 3) Here is the task I have been given: Given a list of numbers, find and print all its elements that are greater than their left neighbor. Example input 1 5 2 4 3 Example output

The second part of your if condition is wrong.

It should read: `if a[x] > a[x + 1] and a[x] > a[x - 1]`

instead of `if a[x] > a[x + 1] and a[x] < a[x - 1]`

**Find the element before which all the elements are smaller than it ,** Find maximum difference between nearest left and right smaller elements · Count the number of elements which are greater than any of element on right side of an Output: The elements greater than all elements to its right are 10, 6, 5 Naive solution would be to use two loops. For each element, we check if any greater element exists to its right of it or not. If all elements to its right are less than it, then we print the element. The time complexity of above solution is O(n 2). Better solution is to

Here is a possible solution

data = [-9, 29, -100, 64, 26, 73, -96, 28, -92, 11, -14, -86, -54, -67] data2 = [data[i] for i in range(1, len(data)-1) if data[i-1] < data[i] > data[i+1]] print(data2)

Output:

[29, 64, 73, 28, 11, -54]

Now you can get the length of the generated array `len(data2)`

. Another option
is using a function like you did, you can use `a < b < c`

expressions to save some typing

def greater_neighbors(a): acc = 0 for x in range(1, len(a) - 1): if(a[x + 1] < a[x] > a[x - 1]): acc += 1 return acc print(greater_neighbors(data))

**Find a peak element,** An array element is a peak if it is NOT smaller than its neighbours. If in the array, the first element is greater than the second or the last element is greater than the second last, print Where n is the number of elements in the input array. first_page Swap Kth node from beginning with Kth node from end in a Linked List. Given an array of numbers, print all those elements that are greater than average. Examples: Input : 5, 4, 6, 9, 10 Output : 9 10 Explanation: avg = 5 + 4 + 6 + 9 + 10 / 5; avg = 34 / 5 avg = 6.8 Elements greater than 6.8 are 9 and 10 Input : 1, 2, 4, 0, 5 Output : 4 5

**100-days-code/7.5. Lists: Greater than neighbors.md at master ,** Given a list of numbers, determine and print the number of elements that are greater than both of their neighbors. The first and the last items of the list shouldn't Given an sorted array of size n. Find number of elements which are less than or equal to given element. Examples: Input : arr[] = {1, 2, 4, 5, 8, 10} key = 9 Output : 5 Elements less than or equal to 9 are 1, 2, 4, 5, 8 therefore result will be 5.

**100-days-code/7.3. Lists: Greater than left neighbor.md at master ,** Given a list of numbers, find and print all its elements that are greater than their left neighbor. Example input 1 5 2 4 3 Example output 5 4. Python Code: a = [int Select elements from Numpy Array which are greater than 5 and less than 20: Here we need to check two conditions i.e. element > 5 and element < 20. But python keywords and, or doesn’t works with bool Numpy Arrays. Instead of it we should use &, | operators i.e.

**Find all elements in an array that are greater than all elements ,** Output: The elements greater than all elements to its right are 10, 6, 5. Naive solution would be to use two loops. For each element, we check if any greater First, use the logical and operator, denoted &, to specify two conditions: the elements must be less than 9 and greater than 2. Specify the conditions as a logical index to view the elements that satisfy both conditions. A (A<9 & A>2) ans = 5×1 5 3 8 3 7

##### Comments

- try
`if a[x - 1] < a[x] and a[x] > a[x + 1]:`

- @Ruzihm that worked! I feel so stupid now, thanks so much!
- Voting to close this question as off-topic due to being caused by a typographical error.