While loop that asks for input and breaks once time is up

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I want to create a while loop that is able to keep on receiving inputs but will break once a timer countdown to 0. How am I able to do it?

while True: x = raw_input("Enter Stuff here:")

This loop will end once timer reaches zero, regardless if the user has anything inputted or not. However, i do not know how to implement such timer

I've done something similar previously, where I use signal to trigger an error when the time I've allotted has run out, basically a TimeOutError. I have it as a function wrapper which I can conveniently use it as @timeout(seconds=<number_of_seconds>). See the code below:

import signal
from functools import wraps

class TimeOutError(Exception):

def timeout(seconds):
    def decorator(func):
        def _handle_timeout(signum, frame):
            raise TimeOutError()

        def wrapper(*args, **kwargs):
            signal.signal(signal.SIGALRM, _handle_timeout)
                result = func(*args, **kwargs)
            return result

        return wraps(func)(wrapper)

    return decorator

# Using it as a function wrapper    
def run():
    while True: x = raw_input("Enter Stuff here:")

# Then calling it as such
except TimeOutError:
    print("You have exceeded the allotted time!")

Incremental Java break and continue, Loops are a way to repeat the same code multiple times. The loop below runs alert(i) for i from 0 up to (but not including) 3 : let sum = 0 ; while ( true ) { let value = + prompt ( "Enter a number" , '' ) ; if ( ! value ) break ; // (*) sum += value The ordinary break after input would only break the inner loop. 1. The while loop . 2. The do-while loop . 3. The for loop While Loop. A while loop is the most straightforward looping structure. The basic format of while loop is as follows: while (condition) { statements; } It is an entry-controlled loop. In while loop, a condition is evaluated before processing a body of the loop.

import sys
import threading
import time
import queue

def add_input(input_queue):
    while True:

def timed_input():
    s = ""
    input_queue = queue.Queue()
    input_thread = threading.Thread(target=add_input, args=(input_queue,))
    input_thread.daemon = True

    last_update = time.time()

    print("Enter stuff here and confirm with enter:")

    while True:
        # Do while countdown of 5 seconds
        if time.time()-last_update > 5:
            print("\nTime is up")
            s = s.replace("\n", "")
            if s != "":
                print(s, " entered.")

        if not input_queue.empty():
            s += input_queue.get()


Break, The break statement lets your code immediately exit a while loop. Let's look at this concept! One way to use break statements is to put them in an if statement nested in the The following code continually asks for user input until they type "​exit": while Each time the loop repeats, it asks for the user to enter a command v. In the while loop there is an if statement that states that if i equals ten the while loop must stop (break). With “continue;” it is possible to skip the rest of the commands in the current loop and start from the top again. (the loop variable must still be incremented). Take a look at the example below:

You can do it by using multiprocessing.Process

from time import sleep
from os.path import isfile
from os import remove

def timeout():
    t_start = time()
    while True:
        if time() - t_start > 3:
            with open('spy', 'w') as source:
p1 = Process(target=timeout, daemon=True)

while True:
    if not isfile('spy'):
        a = input('input something:')

However, as you can see from the script, one problem is this script won't exit unless a user types something to invoke if not isfile('spy').

Loops: while and for, If the try block is executed successfully, the next statement after the except However, we would like to give the user the opportunity to enter a correct input. We want to keep asking until the time is entered correctly. We end up with the following program: In : done = False while not done : try: time = int(input("What time is it  The loop must ask for a number until either the visitor enters a number greater than 100 or cancels the input/enters an empty line. Here we can assume that the visitor only inputs numbers. There’s no need to implement a special handling for a non-numeric input in this task.

Learn to Program with Minecraft: Transform Your World with the , Since the inner while loop contains the break it is the one exited when the char input = ' '; 1 6.19 switch inside of while(true){ 2 while loop 3 cout<<"Enter a  while loop: I recently wrote if statement with break: Now it’s time to ask the user for input. We’ll use the input() function, which by definition returns a string. We’re also going

Conceptual Programming with Python, while loop repeats the sequence of actions many times until some condition Once the condition becomes False, the loop terminates and control is passed to the next If during the execution of the loop Python interpreter encounters break , it The input sequence ends with 0 for the program to be able to stop even if the  Hi Maybellinelim,. Once you get into your while loop, you asking for input that overwrites the first user_input. my answer is similar, but it only shows the grand total sum when a non-digit is entered.

C++ for Artists: The Art, Philosophy, and Science of , For example if the following code asks a use input a integer number x. If x is divisible by 5, the break statement is executed and this causes the exit from the loop. #include If one divisor is found then we could conclude that x is not a prime. While Loop. In Python, while loops are constructed like so: while [a condition is True]: [do something] The something that is being done will continue to be executed until the condition that is being assessed is no longer true. Let’s create a small program that executes a while loop. In this program, we’ll ask for the user to input a password.

  • what do you mean by timer?
  • timer for the loop to last e.g. 10 seconds
  • Hey thanks, is the signal module available in windows, python 2.7?
  • @Mashumaro Python 2.7 will retire in 3 months!
  • @Mashumaro yes, should be useable in python2.7 but I agree that you're better off with starting to use python 3.x instead
  • Hmm apparently signal does not work with windows tho? :\
  • Umm i guess the phrasing for my question was bad, I meant the while loop will last 10 seconds before breaking.
  • sorry, I have updated my answer, hope this helps