Printing a list on a new line
I have a list that i call a function on to make it print out the list in lexicographic order. Lexicographic is basically a sort() which isn't important but I want this list sorted in a new line with every entry. Right now it just prints like
['(011)', '(022)', '(040)', '(04344)', '(044)', '(04546)', '(0471)', '(080)', '(0821)']
when i want
011 022 etc
I tried using a
for loop but that made it worse. I tried
print (lexicographic(uniquelist), sep = '\n')
but that didn't change anything. I even tried making a new empty list and appending but that didn't go anywhere the new line feature works without the function "lexicographic" call.
print(lexicographic(uniquelist), sep = '\n') (04344) (080) (044) (011) (0821) (022) (040) (0471) (04546)
expected this but sorted lexicographically and on a new line
There are two ways you can do what you like:
uniques = ['(04344)', '(080)', '(044)', '(011)', '(0821)', '(022)', '(040)', '(0471)', '(04546)'] # Join with new lines and print print('\n'.join(sorted(uniques))) # A classic loop, nothing wrong with this for item in sorted(uniques): print(item)
(011) (022) (040) (04344) (044) (04546) (0471) (080) (0821)
If you do not want the parens,
for item in sorted(uniques): print(item[1:-1])
Printing list elements on separated lines in Python, print("\n".join(sys.path)). (The outer parentheses are included for Python 3 compatibility and are usually omitted in Python 2.). Teams. Q&A for Work. Stack Overflow for Teams is a private, secure spot for you and your coworkers to find and share information.
Within your lexographic function, try doing
for l in lexographically_sorted_list: print (l)
Printing Lists Using Python, The sep argument tells how to separate each of the printed outputs, relying on a newline character in this case. Click Run Cell. Python outputs the list one item at � My search through the previous posts yields methods to print all the values of the list on a single line, but that's not what I want. I feel like there is an easy, pretty way to do this. I think it's possible to hack it up using while loops and some ugly slicing, but hopefully I'm missing something I don't see why you think that's an ugly hack.
If you just want to print each element of your list on one line, you can use:
[print(elt) for elt in list]
Here one example which also remove brackets:
list = ['(0821)', '(011)', '(080)', '(022)', '(04344)', '(040)', '(044)', '(04546)', '(0471)', ] # sort list.sort() # Print each element per line [print(elt[1:-1]) for elt in list] # 011 # 022 # 040 # 04344 # 044 # 04546 # 0471 # 080 # 0821
Hope that help !
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- Are you saying that when you call
print(lexicographic(uniquelist), sep = '\n')you do not get the list items, one per line, in sorted order?
- yes I get the lexicographic order but not in new line ['(011)', '(022)', '(040)', '(04344)', '(044)', '(04546)', '(0471)', '(080)', '(0821)'] this what i get
- Somehow, using just a sort fixed and matches with the lexicographic order so I guess i don't need the function at all. Thanks tho :)