Extracting the last numerical and its trailing text in R

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From a string such as

s <- c("123 John 80 kg", "456 Paul 23 shifts  9 l", "Diane 155 cm")

I wish to extract only the last numerical and the trailing text. My desired result looks like this:

"80 kg" "9 l" "155 cm"

You can do this with a regular expression:

sub(".*\\b(\\d+\\s+\\w+)", "\\1", s)
1] "80 kg"  "9 l"    "155 cm"

[PDF] Handling and Processing Strings in R, This ebook aims to help you get started with manipulating strings in R. Although there are 6.4.5 Extract all matched groups with str match all() . analysis is numbers or things that can be mapped to numeric values. by giving it an index value outside its previous range. removes leading and trailing whitespace none. str_sub (x, - 3, - 1) # Extract last characters with str_sub # "ple". The same output as before with the substr function (i.e. ple ), but this time with a much simpler R syntax. To get this output, we had to specify three inputs for the str_sub function: The character string (in our case x).

Try the following regex which reads like the requirements:

stringr::str_extract(s, "\\d+\\D*$")

Extraction of numbers from a character string, stla.overblogMy previous blog; Timely Portfolio A great blog about R, Javascript, and more I'm using the following function to extract the numerical values: If there are multiple numbers in the character string, it only extracts the first one: mode only (see next section about the import of Excel files in R). To extract a specific element from a vector, use square brackets. To get the tenth element of letters, for example, use the following: > letters[10] [1] "j" To get the last three elements of LETTERS, use the following: > LETTERS[24:26] [1] "X" "Y" "Z" The colon operator (:) in R is a handy way of creating sequences, so 24:26 results in 25, 25, 26. When this appears inside the square brackets, R returns elements 24 through 26.

Using stri_extract_last_regex

stringi::stri_extract_last_regex(s, "\\d+\\s+\\w+")
#[1] "80 kg"  "9 l"    "155 cm"

Introduction to stringr, This is now equivalent to the base R function nchar() . 3, 3) #> [1] "c" "i" # The 2nd to 2nd-to-last character str_sub(x, 2, -2) #> [1] "bcde" "hifj" The opposite of str_pad() is str_trim() , which removes leading and trailing whitespace: pattern matching functions to detect, locate, extract, match, replace, and split strings. #1. I have a variable that contains alphanumeric strings of differing lengths. The last digit in each string is a character. I need to extract just the last digit of each string into a new variable. I was trying to use the SUBST function, but I don't know how to determine the position when the lengt

Or using regmatches/regexpr from base R

regmatches(s, regexpr("\\d+[^0-9]*$", s))
#[1] "80 kg"  "9 l"    "155 cm"

[PDF] Package 'textclean', (2001) <doi:10.1006/csla.2001.0169>) or extracting them into new example, emoticons are often used in text but not always easily R' ' add_missing_endmark. numeric, cut them in half, round up to the closest integer, add the If TRUE inserts a trailing space in the replacements. fixed "Its C+ work",. Example 2: Extracting first name and last name and switching their order. We have a variable that contains a person’s full name in the order of first name and then last name. We want to create a new variable for full name in the order of last name and then first name separated by comma. To start, let’s make a sample data set.

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In order to make the formula dynamic, we can use other supporting functions like “Find and LEN”. However, the extraction of only numbers with the combination of alpha-numeric values requires an advanced level of formula knowledge. In this article, we will show you the 3 ways to extract numbers from a string in excel.

Method #1 : Using List comprehension + isdigit () + split () This problem can be solved by using split function to convert string to list and then the list comprehension which can help us iterating through the list and isdigit function helps to get the digit out of a string.

Comments
  • Thanks! Your answer works the examples that I gave. For anyone who might have a similar case - this solution does not generalise to cases such as "678 Oscar 60kg". Ronak' solution with stringi does.
  • If you want to allow no space between the number and the letters use ".*\\b(\\d+\\s*\\w+)"
  • @NikolayNenov that's why it's helpful for your question to include the cases that you need to be able to adjust to, so folks can address those stipulations without having to go back and revise. If your examples don't contain a 60kg example, we can't know that you need one.
  • Thanks @camille - it's useful to remind the need to give relevant examples to anyone who does not find it blatantly obvious. Please note, my initial comment is meant to inform anyone who might stumble on a similar problem that the solution might not work for their case. Apologies if it came out as a criticism ;)