Using sed, insert a space at the 3rd last index of each line

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I would like to insert a space, before the 3rd last character of each line, to turn this:




Into this:

CC287999 221


CH654AZ0987XX 277

So far I've tried:

sed -i 's/.*\(...\)/ \1/' file

However this remove the preceding text also.

Thank you

One way:

sed 's/\(...$\)/ \1/' file

Just match the last 3 characters, while substituting put a space and then the matched pattern(\1)

How do I insert a space every four characters in a long line?, echo "foobarbazblargblurg" | sed 's/. edited Feb 3 '16 at 12:35 With any POSIX shell only (also avoiding the trailing space if the input length is a multiple of 4): ex # no spaces added at the end of the first line (while loop to add to the end of so only output starting from index 1; use printf -v myvar instead to store to a� 14. Delete all spaces at end of the line of text. Using [:blank:] class can be used to remove spaces and tabs from the text or the content of any file. The following command will remove the spaces at the end of each line of the file, os.txt. $

With awk could you please try following.

awk '{print substr($0,1,length($0)-3),substr($0,length($0)-2)}' Input_file

insert character in particular position., I want to insert space in 7th position of all the lines usign vi editor or sed command Input file 12345689010 abcdefghijk . 1.> Open input file in Vi Editor. 2.> Go to first line, first character using ":1" 3. The last reply was by MadeInGermany. SED - insert space at the beginning of line and multi replace command hi I am trying to use SED to replace the line matching a pattern using the command sed 'pattern c\ new line ' <file1 >file 2 I got two questions 1. how do I insert a blank space at the beginning of new line?

tried on gnu sed:

sed -E 's/\S{3}\s*$/ &/' file

sed, a stream editor, Previous: Overview, Up: Invoking sed [Contents][Index] sed may be invoked with the following command-line sed prints out the pattern space at the end of each cycle SED PROGRAM: /1/ s/1/3/ INPUT: 'STDIN' line 1 Add the commands contained in the file script-file to the� tr -d \r <infile >outfile # GNU tr version 1.22 or higher # delete leading whitespace (spaces, tabs) from front of each line # aligns all text flush left sed 's/^[ \t]*//' # see note on '\t' at end of file # delete trailing whitespace (spaces, tabs) from end of each line sed 's/[ \t]*$//' # see note on '\t' at end of file # delete BOTH leading

Another awk proposal:

awk '{sub(/.{3}$/," &")}1' file 
CC287999 221


CH654AZ0987XX 277

Other Commands (sed, a stream editor), Transliterate any characters in the pattern space which match any of the Example: Add ' hello ' after the second line (-| indicates printed output lines): The a command queues the lines of text which follow this command (each but the last ending with a \ seq 3 | sed -e '2a\' -e hello 1 2 hello 3 $ sed -e '2a\' -e "$ VAR". For example to add # in front of each line we can use sed command with following syntax: $ sed 's/^/#/' file.txt #add #character #at the #beginning of #each line replace # with ' ' ( space ) to add space in front of each line: $ sed 's/^/ /' file.txt add character at the beginning of each line Redirect the output produced by sed command to save

Sed by Example, Part 3, Insert a carriage return before a line feed, and presto, a CR/LF ends each line. If you use this script and notice that the last character of every line of the output has This command tells sed to copy the contents of the pattern space (the buffer that Retrieved from " Sed_by_Example� sed 's/./&,/4' <in >out That will append a comma on output to the 4th character of all input lines with at least that many characters. And, if you'll take my advice, you should generally not use the -i switch to any sed which offers one.

$ sed '$ i #Next line will be last line' sedtest.txt This is line #1 This is line #2 This is line #3 This is line #4 This is line #5 This is line #6 This is line #7 This is line #8 This is line #9 #Next line will be last line This is line #10 2. Insert lines using Regular expression This will insert the line before every line where pattern

  • Looking at your question history I think you should read this: