SML: Remove the entry from the List

How can I delete the element elem in list L? If the list does not contain elem, then the function should return the list unchanged.

For instance:

L = [1, 3, 4, 0, 5, 7]    
elem = 5

So far I have the following function:

fun removeElem elem myList[] = myList
  | removeElem (myList::tl) = if mem myList elem then
                                rm elem myList[]
                                removeElem elem tl

You can turn the question around and ask how to keep only those items not equal to elem. This fits cleanly with filter:

fun removeElem elem myList = filter (fn x => x <> elem) myList

SML: Remove the entry from the List - list - iOS, How can I delete the element elem in list L? If the list does not contain elem, then the function should return the list unchanged. For instance: L = [1, 3, 4, 0, 5,� In Python, list's methods clear(), pop(), and remove() are used to remove items (elements) from a list. It is also possible to delete items using del statement by specifying a position or range with an index or slice. Remove all items: clear() Remove an item by index and get its value: pop()

This code will accomplish what you want to do: remove the element (actually it will remove all instances of the element if there are more than one) and return the rest of the list as-is:

fun remove_element (list, element) =
    case list of
    [] => []
      | list_head::list_tail => let val a = remove_element(list_tail, element)
                           if list_head = element
                           then a
                           else list_head::a

remove elements from a list in ml - sml - html, I�m trying to write a function that produces a new list containing the given list without the element x. Moscow ML says that some cases are unused in this match. [*]Use the remainder returned in construction of new list (So now everything works backwards) [*]Use the remainder returned in construction of new list (Still not out of the dream world) [*]Use the remainder returned in construction of new list (I think this is the last door) Finally the returned list. Edited April 6, 2012 by irneb

fun delete (s,[])     = []
  | delete (s,x::xs') = 
    if s = x then xs' (* more efficient than call delete function again *)
    else x::delete(s, xs') 

[SML/NJ] Remove nth value from list using pattern matching, You need to delete the nth element of the list. Assuming indexing starts at 0, del lst 0 should return the list minus the first element for example. Hint: subtraction and� The remove () method removes the first matching element (which is passed as an argument) from the list. The syntax of the remove () method is: list.remove (element)

fun remove_element (elemlist, elem) = 
  case elemlist of
  [] => []
  | head::tail => if elem = head
                  then remove_element (tail, elem)
                  else head::remove_element (tail, elem)

Output SML/NJ:

val remove_element = fn : ''a list * ''a -> ''a list
val it = () : unit
(* matching *)
- remove_element ([1,2,3,4,5], 4);
val it = [1,2,3,5] : int list
(* non matching *)
- remove_element ([1,2,3,4,5], 7);
val it = [1,2,3,4,5] : int list
(* multiple instances *)
- remove_element ([1,3,4,4,5],4);
val it = [1,3,5] : int list

Learning SML, basic-list-functions.sml Returns the las element of a list. *). fun last(xs) = case xs of. [] => raise List.Empty Returns an element of a list based on its index. *). There are two way to remove an element from ArrayList. 1. By using remove() methods : ArrayList provides two overloaded remove() method. a. remove(int index): Accept index of object to be removed.

With no libraries or extra functions

fun remv(L, c) = 
  if null(L) then nil
  else if c=hd(L) then remv(tl(L), c)
  else hd(L)::remv(tl(L), c);

COMP 105 Homework: Core ML, When programming with lists, it is rarely necessary or desirable to use the length Implement minlist , which returns the smallest element of a non-empty list of integers. You'll want to test the delete functions as well. Within the the Tools section, select “Uninstall” and then from the list of programs select the program you wish to remove the entry for. Select the “Delete” button. Delete, as opposed to “Uninstall”, will simply remove the entry from the program list and will not attempt to remove any installed software or bits left behind after a manual uninstall.

A Gentle Introduction to ML, The original is at Consider the function last, which returns the last element of a list. last [4 Note that both of these are strictly functions not procedures, remove does not change an� Removing entry from Windows Firewall allowed programs There are 7 entries of a program I uninstalled still listed in the allowed programs of Windows Firewall. I unchecked them, but am unable to remove them as the remove button is grayed out.

Elements of ML Programming, Second Edition (ML97): Solutions for , We must declare L to be a dino list, so ML can deduce the type of records in the list. we operated upon a tree by modifying the tree to remove one node at a time. end; (* insert(A,i) pushes A[i] left until it finds an array element smaller than it. Linked List example: Here, we will discuss deleting an element with a specific value from a linked list. Here are some constraints for our example: The list holds char's. Deletion can occur anywhere in the list. The delete operation will not return the element that we delete, it only need remove it from the list.

A Gentle Introduction to ML, Tutorial One : Expressions & simple functions ML has a fairly standard set of Consider the function last, which returns the last element of a list. If we also partition the list rather than remove spaces the punctuation may be retained and � Although its a good feature but sometimes we might want to remove a particular item from the history list because of some obvious reasons. Here is a simple and safe method to remove any desired item from RUN history / MRU (Most Recently Used) list: 1. Type regedit in RUN dialog box and press Enter. It'll open Registry Editor. 2. Now go to

  • This only removes the first occurrence of the element.
  • What if I want to remove a real element? What should I add to do it?
  • Answering questions here is good but this answer appears to copy the code from Vikram's answer that was written over four years ago. New answers to old questions should show new information or give new insights into the topic. Repeating existing answers is just clutter.
  • I don't think this question is asking about removing duplicates, just a certain element.