How to print only 3 digits of a reversed number in java( Let's say the number has 4 digits)

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Let's say I have a number from user, for exemple: 456789. I know how to print in reverse the number, but I am not sure how I can stop the execution to print only 3 first reversed digits. What I mean is that I want to print only 987 from the given number

I have to stop somehow with break; but I am not sure how.

public static void main(String[] args) {

    int number= 0;
    int numberInReverse = 0;
    System.out.println("Input a number");
    Scanner sc=new Scanner(System.in);
    numar=sc.nextInt();

    while (number !=0){
        numberInReverse*=10;
        numberInReverse=numar%10;
        number/=10;
        System.out.print(numberInReverse);
    }
}

You could follow this algo:

  1. modulo the number by 1000
  2. reverse it
  3. print

Java program to reverse a number using for, while and recursion, There are three ways to reverse a number in Java. 1) Using while loop 2) Using for loop 3) Using recursion 4) Reverse the number Output: Input your number and press enter: 145689 Reverse of input number is: Let x=123, then ⌊log10x ⌋=2. first ArrayList takes only Strings , and second ArrayList takes only Integer. Relatively simple since you need to print one digit per line. You also state that you print its digits, which implies that leading zeros are still going to be displayed. Our test case . 123000 prints : 0. 0. 0. 3. 2. 1. here is the code, no while, no string, and no math library :

You can just convert to into a StringBuilder and use reverse() and substring():

String result = new StringBuilder()
        .append(numar)
        .reverse()
        .substring(0, 3);
System.out.print(result);

Write a program to reverse digits of a number, Write a program to reverse digits of a number Input : num = 12345 Output : 54321 Input : num = 876 Output : 678 rev_num*10 + num%10; (b) Divide num by 10 (3) Return rev_num C++; C; Java; Python; C#; PHP Count of numbers between range having only non-zero digits whose sum of digits is N� Let us say the number is 120 then the number is 3 digits long and contains the place value of units, tens and hundreds. Now when we apply the logic of reversing a number in java, then the units digit i.e. 0 will become our hundreds digit and 1 will become our units digit and 2 will remain as is.

    System.out.println("Input a number");
    Scanner sc = new Scanner(System.in);

    int num = sc.nextInt();
    int reversed = 0, counter = 0;

    while (counter++ < 3) {
        int digit = num % 10;
        reversed = reversed * 10 + digit;
        num /= 10;

    }

    System.out.println("Reversed Number: " + reversed);

Java Program to Reverse a Number, In this program, you'll learn to reverse a number using a while loop and a for loop in Java. When you run the program, the output will be: Reversed Number: 4321 num is then divided by 10 so that now it only contains first three digits: 123. Reverse A Number In Java – We have discussed the various methods to reverse a number in Java program. To each and every program, compiler is added to execute the program. Along with it, sample outputs are also given citing various examples. The methods are: Using While Loop Using Static Method Using Function Using Recursion

For the example of num = 456789 We have: a) A quotient of 45678 when we do an Integer division, i.e. 456789 / 10 b) A remainder of 9 when we use the Modulus operator, i.e. 456789 % 10

If we update the 'new' number to be the quotient and by iterating, the following table shows what it looks like:

digit number   quo   rem  Observations
----- ------ -----   ---  --------------------------------------------
  1   456789 45678    9
  2    45678  4567    8
  3     4567   456    7   STOP for 3 digits, i.e. number of iterations
  4      456    45    6
  5       45     4    5
  6        4     0    4   BREAK when variable 'quo' equals ZERO

For a first approach, consider calling the following method from your main():

static void firstApproach(){
    int num= 456789;
    int quo= num / 10;
    int rem= num % 10;

    System.out.println( num + " | " + quo + " | " + rem );
}

This is the output we get:

456789 | 45678 | 9

Now, consider a second iteration by calling this method from main():

static void secondIteration() {
    int num= 456789;
    int quo= num / 10;
    int rem= num % 10;
    System.out.println( num + " | " + quo + " | " + rem );

    num= quo;
    quo= num / 10;
    rem= num % 10;
    System.out.println( num + " | " + quo + " | " + rem );
}

Here's the output for two iterations:

456789 | 45678 | 9
 45678 |  4567 | 8

Carry on for yet a third iteration:

static void thirdIteration() {
        int num= 456789;
        int quo= num / 10;
        int rem= num % 10;
        System.out.println( num + " | " + quo + " | " + rem );

        num= quo;
        quo= num / 10;
        rem= num % 10;
        System.out.println( num + " | " + quo + " | " + rem );

        num= quo;
        quo= num / 10;
        rem= num % 10;
        System.out.println( num + " | " + quo + " | " + rem );

        // ... and so on ...
    }

And the output, after 3 iterations:

456789 | 45678 | 9
 45678 |  4567 | 8
  4567 |   456 | 7

Looking at the code for third iteration, observe the following repeating pattern that should go inside the body of a loop:

num= quo;
quo= num / 10;
rem= num % 10;

What if we try to specify some unreasonable amount of digits, say 10 for the same example of 456789?

This is why the loop needs two stoping conditions (whichever occurs first), namely: - when it reaches the specified number of digits (3 in the example); - when quotient gets to ZERO (hence the break;).

The following reverse() method shows a while() loop, where all variables are properly initialised to avoid any surprises. Tha variable digit is the one that controls the number of iterations for the loop and is incremented at the end:

static int reverse( int number, int numDigits ){
    int res= 0;
    int quo= number / 10;
    int rem= number % 10;

    int digit= 1;
    while( (digit <= numDigits) && (quo != 0) ){
        res= 10*res + rem;

        number= quo;
        quo= number / 10;
        rem= number % 10;

        digit= digit + 1;
    }

    return res;
}

The above reverse() method can be called from main():

public static void main( String args[] ){
    // firstApproach();
    // secondIteration();
    // thirdIteration();

    int result= reverse( 456789, 3 );  // reverses 456789, upto 3 digits
    System.out.println(  result );
}

How to Reverse digits of an Integer in Java without converting to , LeetCode has a problem to reverse digits of an integer number without using any Before approaching solution let's first read the problem statement : For example, you need to consider not just about positive integer but also about + input + " Output : " + output); } /* * Java method to reverse an integer value. there are� There are multiple solutions and approaches on how to reverse the digits of a number. But as always i would only be showing the shortest possible way. On this example we would be reversing the digits of a number arrays and for loops.

Java Program To Reverse A Number | Java Programming, Numbers can be reversed in Java using different methods, let us take a Output: Reversed Number : 1234. Explanation: An integer number is The number is then divided by 10, such that it contains the first three digits: 432. LeetCode has a problem to reverse digits of an integer number without using any library method like reverse() method of StringBuffer.In LeetCode, you can solve this problem with many different languages like Java, C, C++, C#, Python, Ruby, and even JavaScript.

Reverse Number in Java, Here we discuss How to Find the Reverse Number in Java with the various examples Let us say the number is 120 then the number is 3 digits long and contains the len - 1)) + reverse(a, --len)); } } }. Output: Reverse Number in Java Output 3 kind of a looping construct just like the while loop which we studied above. Java Program to Print Number Pattern. In Java language you can easily print number pattern using for loop and also using while loop, here i will show you in simple way to print these all patterns.

Java Basics - Java Programming Tutorial, Below is a simple Java program that demonstrates the three basic For example , an int variable can hold only integer (such as 123 ), and NOT floating-point number 6-7 significant decimal digits, in the range of �[1.4x10-45, 3.4028235 x1038] ) Scanner; /** * Prompt user for a string; and print the input string in reverse� There are three ways to reverse a number in Java. 1) Using while loop 2) Using for loop 3) Using recursion 4) Reverse the number without user interaction. Program 1: Reverse a number using while Loop. The program will prompt user to input the number and then it will reverse the same number using while loop.

Comments
  • First reverse the string then use string.substring function to split the first three digits of the reversed string. Numar =numar.reverse(); then numar.substring(0,3) will give you 987
  • If you could explain what the code does and why you are comparing counter++ to 3, that would be awesome. All-code answers/questions are not great.