Replace Random Characters in a Variable

cmake string(regex replace example)
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cmake_match_1
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I want to replace value of a variable (can contain a number, a character, a string of characters).

$ echo $VAR
http://some-random-string.watch.film.tv/nfvsere/watch/skrz1j8exe/chunks.m3u8?nimblesessionid=30931574352........

So far, I've tried this command, however it's not working, so I'm thinking some of these might need a regex.

$ echo $VAR | sed -e "s/\(http[^^]*\).*\(.watch\)/\1"mystring"\2/g"
$ echo $VAR | sed -e "s/\(https\?:\/\/\).*\(.watch\)/\1"mystring"\2/g"
$ echo $VAR | sed -e "s/\(http[s]\?:\/\/\).*\(.watch\)/\1"mystring"\2/g"

I'm aware that there are questions that answer similar queries, but they have not been of help.

echo $VAR | sed 's|\(http[x]*://\)[^.]*\(.*\)|\1mystring\2|'

explanation

s|                 # substitute
\(http[x]*://\)    # save first part in arg1 (\1)
[^.]*              # all without '.'
\(.*\)             # save the rest in arg2 (\2)
|\1                # print arg1
mystring           # print your replacement
\2                 # print arg2
|

javascript replace random letters with underscore, You might try something like this :) var a = "Text i want to replace text from"; var splitted = a.split(''); var count = 0; // variable where i keep trace of� Use the syntax below to edit and replace the characters assigned to a string variable. Syntax % variable : StrToFind = NewStr % %~[ param_ext ]$ variable : Param Key StrToFind : The characters we are looking for NewStr : The chars to replace with (if any) variable : The environment variable param_ext : Any filename Parameter Extension Param : A

In sed you have to escape any control characters like forward slash before matching:

echo $VAR | sed 's/http.\/\/.*\.watch\.film\.tv/http:\/\/mystring.watch.film.tv/'

string — CMake 3.12.4 Documentation, string(REPLACE <match_string> <replace_string> <output variable> <input> Return a random string of given length consisting of characters from the given� We then create the variable, randomstring, which will be the variable that represents the 6-character random string in the end. We then create a for loop that has 6 iterations, from 0 to 5; thus, a 6-character output will be the result. If you want a 10-character random string, then you change 6 to 10. If you want a 12-character random string

You don't need sed. This task can be done in just shell:

$ var='http://some-random-string.watch.film.tv/nfvsere/watch/skrz1j8exe/chunks.m3u8?nimblesessionid=30931574352'
$ echo "${var%%//*}//mystring.watch${var#*.watch}"
http://mystring.watch.film.tv/nfvsere/watch/skrz1j8exe/chunks.m3u8?nimblesessionid=30931574352

How it works:

  1. ${var%%//*} returns the value of $var with the first // and everything after it removed.

  2. //mystring.watch adds the string that we want.

  3. ${var#*.watch}" returns the value of $var with everything up to and including the first occurrence of .watch removed.

Because this approach does not require pipelines or subshells, it will be more efficient.

str_shuffle - Manual, Change language: str_shuffle — Randomly shuffles a string It then will run str_shuffle on the universe of characters a random number of times, using� Replace() Replace characters within a string. Syntax . Replace(strOldChar, strNewChar) Key strOldChar The characters to find.strNewChar The characters to replace them with.

gnu sed

$ echo $VAR | sed -E 's/^(http:\/\/)\S+(\.watch\.film\.tv\/)/\1"mystring"\2/i'

Python : How to replace single or multiple characters in a string , str.replace(old, new , count) It returns a new string object that is a copy of existing string with replaced content. Also,. If count is not provides� replace replaces the values in x with indices given in list by those given in values . If necessary, the values in <code>values</code> are recycled.</p>

Java String replace(), replaceFirst() & replaceAll() Method EXAMPLE, This method allows the replacement of a sequence of character values. Syntax: public Str replace(char oldC, char newC). Parameters: oldCh −� Re: Replace a string inside a macro variable value Posted 04-05-2016 05:57 PM (6811 views) | In reply to AhmedAl_Attar It has to be done on the fly because the macro variable value actually comes from an Oracle table that stores the string.

How to generate a random string?, You can optimize it by replacing the "fold", with other string processing tools. go with bash's (also zsh and ksh , possibly others) builtin $RANDOM variable: Description. Replaces occurrences of substring1 in a string with an object in a specified scope.The search is case sensitive. This function can take either string or callback function as an argument instead of the argument to replace the string.

Java: Generating a random char (a-z), int randomNumber = 97 + rnd.nextInt(26);. We can replace 97 with 'a'… int randomNumber� Similar to the Left function in VB a batch script can return a specified number of characters from the left side of a string by specifying a substring for an expansion given a position of 0 and a length using :~ while expanding a variable content. The example shows how to return the first 4 characters of a string.

Comments
  • The problem with using terms like some-random-string and mystring in a question is that as far as we know they can contain absolutely any characters which makes writing a regexp or a way to handle replacement text challenging. Can you be more specific on what it can/can't contain and show some truly representative examples in your question? Make sure to include the expected output as well as the sample input.
  • You're right. Thank you.
  • You're welcome. In case it's not obvious, your selected answer will fail given various character in mystring, e.g. & or | or \1 or ...