## simple error "ORA-00979: not a GROUP BY expression"

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I am trying to List the full name and the total number of transactions handled by the full time employee and Rank the results in descending order on the total number of transactions.

This is what I have

select concat( e.efirst, e.elast ) ename, count(*) total_transactions from transactions t join employees e on t.employeeid = e.employeeid where e.etype = 'Fulltime' group by t.employeeid order by total_transactions desc;

Add `concat(e.efirst, e.elast)`

to group by:

select concat(e.efirst, e.elast) ename, count(*) total_transactions from transactions t join employees e on t.employeeid = e.employeeid where e.etype = 'Fulltime' group by t.employeeid, concat(e.efirst, e.elast) order by total_transactions desc;

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When computing aggregates when grouped by a foreign key you'll want to `JOIN`

the principal relation (in this case `employee`

) in an outer-query, as it's a separate concern from the aggregate.

SELECT CONCAT( CONCAT( employee.efirst, ' ' ), employee.elast ) AS employee_name, employee_id, total_transactions FROM ( SELECT employeeid AS employee_id, COUNT(*) AS total_transactions FROM transactions GROUP BY employeeid ) AS sq INNER JOIN employee ON sq.employee_id = employee.employeeid WHERE employee.etype = 'Fulltime' ORDER BY total_transactions desc;

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The `group by`

expressions should match the unaggregated expressions in the `select`

, so:

select ( e.efirst || ' ' || e.elast ) as ename, count(*) total_transactions from transactions t join employees e on t.employeeid = e.employeeid where e.etype = 'Fulltime' group by ( e.efirst || ' ' || e.elast ) order by total_transactions desc;

I added a space between the names as well and switched to using the concatenation operator.

This assumes that employee names are distinct. If this is not the case, then you should be including the employee id in the `select`

, s you can distinguish amongst those with the same name.

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##### Comments

- well, you need to group by the expression you are using for the employee name, not the employeeid
- I need to group by ename?
- you need to group by the same expression you are using for
`ename`

, you can't use that alias directly in the`GROUP BY`

. So, you have to use`GROUP BY concat( e.efirst, e.elast )`

, which will be kind of weird, since there are no spaces between the first and last name - I get error "ORA-00909: invalid number of arguments"
- @MikeGoedken I've corrected my answer. I forgot that Oracle's
`CONCAT`

isn't variadic. - This is the right answer, since not only fixes the error when grouping, it also gives the right results in case 2 or more employees have the same name
- it's the
`e.`

alias, needs to be`employee.efirst`

and`employee.elast`

- This won't work if multiple employees share the same name.