Why this code print before I put any value?

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Why this goto is printing before I put a value to the variable a? Should he call b after the cout, right?

#include <iostream>
using namespace std;
int main(){

  int a;
  b:cout << a << endl;
  cin >> a;
  goto b;
  return 0;
}

It outputs first because that is the way you coded it. You are calling cout << before calling cin >>.

A label doesn't change the flow of code, it simply marks a place where goto is allowed to jump to. In your case, after a is declared, cout >> is executed, then cin << is executed, then cout <<, and then cin >>, and so on endlessly.

You really should not be using goto at all. It is generally frowned upon by most developers as bad practice in code design. Use a regular loop instead, eg:

#include <iostream>
using namespace std;

int main(){
    int a;
    while (cin >> a) {
        cout << a << endl;
    }
    return 0;
}

What's the difference between the print and the return functions , All functions will return a value, and if there is no return statement (or yield but don't worry about that yet), When we printed f2 at the end of the code, we saw "I returned" as the print function is just for my eyes and not for the computer's use ? In the absence of any further information, C++ uses default values. For example, an integer number output with a d is preceded with a – if it is negative but not preceded with anything if it is positive. In addition, such a value takes only as many spaces as are needed to output the number. Output amplifier flags

Sure it works like that you should.

#include <iostream>
using namespace std;
int main(){

  int a;
  b:
    cin >> a;
    cout << a << endl;
  goto b;
  return 0;
}

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It executes the line and has a reference for goto later on during runtime. So it will still print before cout because that is how you defined it. The label does not remove the code, only control.

(Tutorial) Python Print() Function, Unlike Python2 , which did not require you to put a parenthesis, in Python3 this you can simply call the print() function without passing any argument in it. Let's look at the syntax of the print() function. print(value, , sep=' ', end='\n', is buffered, with text output at least until you print a newline (Source). First, because you've specified the main function to return an int. If you don't want that, then specify main to have a void return instead of int. Though take note - it's recommended to pass some integer value back to the environment instead of void.

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Comments
  • Because there's a cout before the cin?
  • But he is linked with b, so he sould treat b as a "function" or something like that, no?
  • No. That's not how labels work.
  • Best not to use goto at all. There so are many gotchas that it is hard to get right even if it doesn't turn your code into a plate of spaghetti. This usage is just a simple while (true) loop.
  • I got it, but has another way to do it? Because I have a problem very similar and this problem is the reason for this question
  • I would remove "you really should not ..." because the point of this is probably to find out how goto works, which you won't do without using goto.
  • Thank you very much, now I understood why it was my code was in trouble