Match elements in nested list with values from dictionary

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I have a list

l = [['a', 's', 'l'], ['a', 'g', 'l'], ['a', 's', 'l'], ['g', 's', 'l'], ['a', 'l', 'g']]

I also have a dictionary

d = [{'a': 1, 'v': 6, 'c': 7}, {'g': 3, 's': 4, 'l': 9}]

I need to create another list in the shape of l but with the values matched from d:

d = [[1, 4 ,9], [1, 3 , 9], [1, 4 , 9], [3, 4 , 9], [1, 9 , 3]]

I have tried using for loops to do this but the nested list is giving me trouble.

Any help would be appreciated.

Your d really is a list of dicts, so you should merge the list of dicts into one dict first, and then use a list comprehension to map the items in the sub-lists to their dict values:

d = dict(i for s in d for i in s.items())
print([list(map(d.get, s)) for s in l])

so that given:

l = [['a', 's' ,'l'], ['a', 'g' , 'l'], ['a', 's' , 'l'], ['g', 's' , 'l'], ['a', 'l' , 'g']]
d = [{'a': 1, 'v': 6, 'c': 7}, {'g': 3, 's': 4, 'l': 9}]

This outputs:

[[1, 4, 9], [1, 3, 9], [1, 4, 9], [3, 4, 9], [1, 9, 3]]

Compare dictionary key, values with nested list elements, I would group the sublists in a dict by the first element which is the letter then iterate over your original dict and check if each key is in the grouping dict and do � Return matches as a nested dictionary.''' #Match on Chr value #Where Start value from database_variant is between St and End values in search_variants. #return as nested dictionary The problem I am having is working out how to get to the values in the nested dictionaries (Chr, St, End, etc) for the comparison.

Simple comprehensions will work:

combined_mapping = {k: v for subdict in d for k, v in subdict.items()}
mapped = [[combined_mapping[element] for element in sublist] for sublist in l]


[[1, 4, 9], [1, 3, 9], [1, 4, 9], [3, 4, 9], [1, 9, 3]]

Get value from dictionary given a list of nested keys, Unless I'm missing something you'd like to implement, I would go for a simple loop instead of using recursion: def nested_get(input_dict, nested_key):� Here’s some sample data that includes nested lists, dictionaries, and values. When calling our flatten() function using the above data, here is the result using pprint() to cleanly format the

I don't get why your d variable is actually a list of dictionaries. It it was an actual dictionary this would be very straightforward:

l = [['a', 's', 'l'], ['a', 'g', 'l'], ['a', 's', 'l'], ['g', 's', 'l'], ['a', 'l', 'g']]
d = {'a': 1, 'v': 6, 'c': 7, 'g': 3, 's': 4, 'l': 9}

r = [ [d[v] for v in lv] for lv in l ]
print(r) # [[1, 4, 9], [1, 3, 9], [1, 4, 9], [3, 4, 9], [1, 9, 3]]

5. Data Structures — Python 3.8.5 documentation, Return zero-based index in the list of the first item whose value is equal to x. List comprehensions can contain complex expressions and nested functions: Another useful data type built into Python is the dictionary (see Mapping Types The operators is and is not compare whether two objects are really the same object� I am trying to get a list which has the values that match with list_A and dict i.e. as in the values of list a ( the second elements in the nested lists) should lie between the value list pair of the dict. match_list = [['a', '4'], ['b', '17'], ['c', '7'], ['f', '11'], ['f', '12']] I am trying to first match the keys of dict with list_A_no_reps

Find all occurences of a key in nested python dictionaries and lists , for item in iterator: yield item can be replaced with yield from iterator . Hey, can you give the code for deleting all the entries in dict matching the key we send. Method #1 : Using loop This is the brute force method by which this task can be performed. For this, we just use naive check and compare and return the result once we find the suitable match and break for rest of dictionaries.

[PDF] Nested Lists and Dictionaries, Its elements are (the names of) 1D lists. • b[i] holds the Each row, col has a value. 10/22/19. Nested Lists and Dictionaries. 9 dict. 'jrs2'. 'jrs1'. Key-Value order in folder is not important id8 d. 10/22/19 Sizes must match up. If you were to solve it with a third-party package, like jsonpath-rw, the solution would be as simple as constructing the path by joining the keys with a dot and parsing the dictionary: from jsonpath_rw import parse def nested_get(d, path): result = parse(".".join(path)).find(d) return result[0].value if result else None

3. Lists - Q for Mortals - Q and kdb+, All data structures in q are ultimately built from lists: a dictionary is a pair of lists; The notation for a general list encloses its items within matching parentheses Retrieving an item in a nested list via a single index retrieves a top-most item. Sometimes, while working with Python dictionaries, we can have a problem in which we need to extract selective keys’ values. This problem has been solved earlier, but sometimes, we can have multiple nestings and certain keys may be present in inner records.

  • What is your expected output? Some more information about what exactly you are trying to accomplish would be helpful.
  • Can all the dictionaries in d be combined? (presumably so, otherwise the answer would be ambiguous)
  • Also, l and d are poorly formatted.