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A JSON File is loaded with:

with open("samples.json", "r") as read_file:
    data = json.load(read_file)

Now I replace the key "22981" with "Automat" in the JSON-String:

d = json.loads(json.dumps(data).replace('"22981"','"Automat"'))

This works fine. But when I try to do it with variables, it does not work, for example:

d = json.loads(json.dumps(data).replace('"{0}"'.format(key1), '"Automat"'))

Any help? Thank you!

d = json.loads(json.dumps(data).replace("{0}".format(key1), "Automat"))

You had a single quote together with a double quote.

Edit: You should also probably know about f-strings

d = json.loads(json.dumps(data).replace(f"{key1}", "Automat"))

see PEP 498.

Solved: Convert string (string of JSON) to JSON object?, I'm fetching a .js file from my local network and setting a variable to the result of; So my question is this. how do i turn the above string of JSON into: var roster = [ a replacer function to replace those with JSON values. The list of tutorials related to oXygen XML Editor. Subject: Re: [xsl] JSON-encoding strings in XSLT 2.0 From: Wendell Piez <wapiez@xxxxxxxxxxxxxxx> Date: Wed, 20 Nov 2013 09:47:46 -0500

you can also do it with python

with open("samples.json", "r") as read_file:
    data = json.load(read_file)
    if data.get(key,None):

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I solved the problem with a workaround. I did the replacement before the json.loads

import json
import csv

with open("sensors.json", "r") as read_file:
    sensors = json.load(read_file)
with open ("samples.json", "r") as myfile:

for key1 in sensors:
    data = data.replace(key1, sensors[key1]['name'])

data = json.loads(data)

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The below code will replace '22981' key with 'Automat':

import json
outfile = open('outfile.json', 'w')
with open("samples.json", "r") as read_file:
for data in  read_file: #To iterate on multiple records in the file(here data is one json record), 
    data = json.loads(data)
    data["Automat"] = data.pop('22981', '')

Binding JSON Format variable as String, Use binding variable for a valid JSON format variable as string. create table TEST(VAR_JSON VARIANT); create or replace procedure public. Step 1: Create a JSON variable using Build String action, but replace the first and last bracket with [ and ]. Step 2: Then use "Replace Sub-string in String" to Replace [ with {. Step 3: Use the Output of variable from Step 3 in another "Replace Sub-string in String" action to Replace ] with }.

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Reference guide for functions in expressions, replace, Replace a substring with the specified string, and return the updated string. variables, Return the value for a specified variable. You can transform the string value into a JSON object using the Parse JSON action. Online based tool to convert json to string variable value string, created json object to include escape characters for the string creation.

  • thank you, but this is not working with complex nested JSON-Structures...