Regular expression for password (at least 2 digits and one special character and minimum length 8)

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I have been searching for regular expression which accepts at least two digits and one special character and minimum password length is 8. So far I have done the following: [0-9a-zA-Z!@#$%0-9]*[!@#$%0-9]+[0-9a-zA-Z!@#$%0-9]*

Something like this should do the trick.

^(?=(.*\d){2})(?=.*[a-zA-Z])(?=.*[!@#$%])[0-9a-zA-Z!@#$%]{8,}

(?=(.*\d){2}) - uses lookahead (?=) and says the password must contain at least 2 digits

(?=.*[a-zA-Z]) - uses lookahead and says the password must contain an alpha

(?=.*[!@#$%]) - uses lookahead and says the password must contain 1 or more special characters which are defined

[0-9a-zA-Z!@#$%] - dictates the allowed characters

{8,} - says the password must be at least 8 characters long

It might need a little tweaking e.g. specifying exactly which special characters you need but it should do the trick.

Password, Password must be between 4 and 8 digits long and include at least one numeric digit. Matches at least 1 upper case character 2.) at least at least 1 special character It also enforces a min and max length and works for .Net and� Given a password, the task is to validate the password with the help of Regular Expression. A password is considered valid if all the following constraints are satisfied: It contains at least 8 characters and at most 20 characters. It contains at least one digit. It contains at least one upper case alphabet. It contains at least one lower case

There is no reason, whatsoever, to implement all rules in a single regex. Consider doing it like thus:

Pattern[] pwdrules = new Pattern[] {
    Pattern.compile("........"),   // at least 8 chars
    Pattern.compile("\d.*\d"),     // 2 digits
    Pattern.compile("[-!"§$%&/()=?+*~#'_:.,;]") // 1 special char
  }

String password = ......;
boolean passed = true;

for (Pattern p : pwdrules) {
    Matcher m = p.matcher(password);
    if (m.find()) continue;
    System.err.println("Rule " + p + " violated.");
    passed = false;
}

if (passed) { .. ok case.. }
else { .. not ok case ... }

This has the added benefit that passwort rules can be added, removed or changed without effort. They can even reside in some ressource file.

In addition, it is just more readable.

RegExLib.com, Password must be between 4 and 8 digits long and include at least one numeric at least 1 special character It also enforces a min and max length and works for . Password must contain at least 2 digits and at least 2 letters. THE Complex Password Filter Matching 3 of 4 Character catagories: 1.) at least 1 upper case character 2.) at least 1 lower case character 3.) at least 1 numerical character 4.) at least 1 special character It also enforces a min and max length and works for .Net and script Regex implimentations.

Try this regex. It uses lookahead to verified there is a least two digits and one of the special character listed by you.

^(?=.*?[0-9].*?[0-9])(?=.*[!@#$%])[0-9a-zA-Z!@#$%0-9]{8,}$ 

EXPLANATION

^ #Match start of line.

(?=.*?[0-9].*?[0-9]) #Look ahead and see if you can find at least two digits. Expression will fail if not.

(?=.*[!@#$%]) #Look ahead and see if you can find at least one of the character in bracket []. Expression will fail if not.

[0-9a-zA-Z!@#$%0-9]{8,} #Match at least 8 of the characters inside bracket [] to be successful.

$ # Match end of line. 

Regular Expressions, regex documentation: A password containing at least 2 uppercase, 1 lowercase, 2 digits and is of length of at least 10. Regex for password must contain at least eight characters, at least one number and both lower and uppercase letters and special characters . Posted by: admin November 19, 2017 Leave a comment

Regular Expressions, regex documentation: A password containing at least 1 uppercase, 1 lowercase, 1 digit, 1 special character and have a length of at least of 10. Whole combination is means, 6 to 20 characters string with at least one digit, one upper case letter, one lower case letter and one special symbol (“@#$%”). This regular expression pattern is very useful to implement a strong and complex password. P.S The grouping formula order is doesn’t matter. 1. Java Regular Expression Example

Try this : ^.*(?=.{8,15})(?=.*\d)(?=.*\d)[a-zA-Z0-9!@#$%]+$

Please read below link for making password regular expression policy:-

Regex expression for password rules

Password Regular Expression, At least one digit [0-9]; At least one lowercase character [a-z]; At least one uppercase character [A-Z]; At least one special character� Questions: I want a regular expression to check that a password must be eight characters including one uppercase letter, one special character and alphanumeric characters. And here is my validation expression which is for eight characters including one uppercase letter, one lowercase letter, and one number or special character.

⛺ 🎾 🧀 Regular expression for password (at least 2 digits and one , Regular expression for password (at least 2 digits and one special character and minimum length 8) I was looking for a regular expression that take I want a regular expression to check that a password must be eight characters including one uppercase letter, one special character and alphanumeric characters. And here is my validation expre

JavaScript : Password validation, Check a password between 8 to 15 characters which contain at least one lowercase letter, one uppercase letter, one numeric digit, and one special character. To validate the said format we use the regular expression ^(?=.*\d)(? =. <title>JavaScript form validation - Password Checking - 2</title> <link� Related: Setting a minimum/maximum character count for any character using a regular expression – Stevoisiak May 25 '18 at 19:01 Are you sure you need a regex? In most programming languages, you can just look at myString.length or so to determine that. – uliwitness Mar 26 at 11:11

Create regular expressions to check the complexity of passwords!, must contains one special symbols in this list $ and @. (?!.*[iIoO]) match any charcuter except i I o and O. \S{6,12} length at least 6 characters and a maximum of 12. combination is means: 6 to 12 characters string with at least one digit and one upper case /^(1[8-9]|2[0-4])$/ : the value must be 18 and 24. Need regular expression to check the password policy and the password policy should : length of password :minimum 6 letters 2 digits 1 Special sign

Comments
  • possible duplicate of Regular expressions for password validation
  • This was very useful and detailed and for others that come around here I will leave this guide that help me customise your answer a little more.
  • In case you need grouping, like "at least combination of Alpha + Special", then something like that should help (((?=.*?[a-z])(?=.*?[!@#$%]))|...), where ... is another group
  • "There is no reason, whatsoever, to implement all rules in a single regex." How do you know that?
  • @drowa What would be a reason?
  • Imagine a CMS system that only accepts regular expressions for password field validation, and changing this CMS system is not an option.
  • @drowa All right. Then my remark is for people implementing such a system. They should make it so that a password validation rule is a set of alternatives, and each alternative is a conjunction of simple conditions (expressed by regular expressions) or negations thereof. It is, in particular, the conjunctions and negations that make regexes complicated, while alternatives are already built in. - In fact, the expectation that the verbal formulation of the companies PW policy could only be expressed in 1 sentence without the words "and" or "not" (or synonyms thereof) would be considered insane.
  • Looks like 0-9 is declared twice in your list of characters: [0-9a-zA-Z!@#$%0-9]
  • This will match 2 digits only if they are consecutive, which I don't think is the case with password.
  • @justhalf, yes, you're right. Part with digits should look like this (?=(.*\d){2,}). And regexp like this ^(?=(.*\d){2,})(?=.*[$-\/:-?{-~!"^_'\[\]]{1,})(?=.*\w).{8,}$. Thanks for a note.