## Python - finding intersections

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I am trying to have the below code return True if the letters in secretWord are also in lettersGuessed. Could someone please let me know what is wrong with my code? It is consistently returning False. Thanks so much.

def isWordGuessed(secretWord, lettersGuessed): current = ' ' for c in secretWord: if c in lettersGuessed: current += c if len(current) == len(secretWord): return True else: return False print(isWordGuessed(secretWord, lettersGuessed))

Iterate over each letter in the secret word and check if its in the second word. Store all the common letters in a `out`

. Check the length of `out`

and return True if greater than 0.

def isWordGuessed(s1, s2): out = "" for c in s1: if c in s2 and not c in out: out += c if len(out) > 0: return True return False

Also it looks like your function is doing too many things. Do you also want to check that the length of the guessed word and the length of secret word is the same? What happens if the secret word or guessed word has repeating letters?

**Intersection() function Python,** Input: Let set A = {2, 4, 5, 6} and set B = {4, 6, 7, 8} Output: {4,6} Explanation: Taking the common elements in both the sets, we get {4,6} as the intersection of both� Python Set intersection() The intersection() method returns a new set with elements that are common to all sets. The intersection of two or more sets is the set of elements which are common to all sets.

You are checking `if len(current) == len(secretWord)`

inside of the loop, before you have completed checking the letters in `secretWord`

. Move it outside.
Otherwise, you may want to address this problem using sets as @stackErr suggested.

**How to find list intersection?,** Here's some Python 2 / Python 3 code that generates timing information for both list-based and set-based methods of finding the intersection of� Definition and Usage. The intersection() method returns a set that contains the similarity between two or more sets.. Meaning: The returned set contains only items that exist in both sets, or in all sets if the comparison is done with more than two sets.

Your current variable already has a "space" in it. So You will always have an extra count in your length. Secondly, whey not use current_length = 0 instead and change the line 5 to current += 1. Then you can compare the len() with this count directly instead of calling len for each word. Since your code does not consider duplicates, you can write a much more compact function using sets.

guess = set(lettersGuessed) secret = set(secretWord) if secret.intersection(guess) == secret: return True else: return False >>> a = set("abcdefgh") >>> b = set("efghabcd") >>> a.intersection(b) set(['a', 'c', 'b', 'e', 'd', 'g', 'f', 'h']) >>> a.intersection(b) == a True

Note that this does not consider duplicate characters etc. For that you should consider using a dictionary and keep track of counts of each character.

**Python Set intersection(),** The intersection() method returns a new set with elements that are common to all sets. You can also find the intersection of sets using & operator� How to write a simple python code to find the intersection point between two straight lines ? Find the intersection point xi = (b1-b2) / (m2-m1) yi = m1 * xi + b1 print('(xi,yi)',xi,yi) returns (xi,yi) 1.6666666666666667 3.666666666666667: Plot the intersection point

There are two issues here. One is to get the code working as is. Remove the additional space between ''. Now, the if len(..) statement should be indented below the 'for' statement since we want all the letters in the secretword to be checked i.e the entire for loop needs to finish before checking the length.

def isWordGuessed(secretWord, lettersGuessed): current = '' for c in secretWord: if c in lettersGuessed: current += c if len(current) == len(secretWord): return True else: return False

The other issue to address is what is required from the code. Is it supposed to return True only when all letters in secretWord appear in lettersGuessed. For example, 'newd' and 'ne4wd'. Are repetitions allowed? Just something to keep in mind.

**How to find the intersection and union of two lists in Python ,** However I hadn't found opportunity to use them until now. Here are three functions using set s to remove duplicate entries from a list, find the� Python examples to find common items between 2 or more dictionaries i.e. dictionary intersection items. 1. Dictionary intersection using ‘&’ operator. Simplest method is to find intersections of keys, values or items is to use & operator between two dictionaries.

You can compare the lengths of `secretWord`

and `current`

inside the `for`

loop but once comparison is successful you need to `break`

out of it to then compare if both are indeed the same strings:

def isWordGuessed(secretWord, lettersGuessed): current = '' for i in secretWord: if i in lettersGuessed: current = current + i if len(secretWord) == len(current): break if secretWord == current: return True return False

**How to find the intersection of two lists in Python,** Kite is a free autocomplete for Python developers. Code faster with the Kite plugin for your code editor, featuring Line-of-Code Completions and cloudless� Python list doesn’t have any inbuilt method to do the intersection, so we are converting the list to a set. After the list is converted to a set, we can easily calculate the intersection by using the & operator. Then, we can convert the final set to a list by using list() method. Python program :

**Python Set intersection() Method,** The other set to search for equal items in. You can compare as many sets you like. Separate the sets with a comma. More Examples. Example. Compare 3� Python counter and dictionary intersection example (Make a string using deletion and rearrangement) Python | Find common elements in three sorted arrays by dictionary intersection Python set operations (union, intersection, difference and symmetric difference)

**List Intersection in Python – Linux Hint,** Finding common data from the multiple lists is called list intersection, but there is no operator or built-in function for lists like sets to find the common data items� Python | Find common elements in three sorted arrays by dictionary intersection Python counter and dictionary intersection example (Make a string using deletion and rearrangement) Python set operations (union, intersection, difference and symmetric difference)

**Find the Intersection of Two Sets of Coordinates and Sort By Colors ,** This article is about some programming exercises. If you are a learner and learning Data Stricture and OOP in Python, it may be helpful for you. A collection of sloppy snippets for scientific computing and data visualization in Python. Tuesday, May 10, 2011. How to find the intersection of two functions

##### Comments

- What are each of them, strings? lists?
- If you do
`set(secretWord).intersection(lettersGuessed)`

, it will output all the letters that are in both strings. Check the length of that output and return True if greater than 0 - Apologies for not specifying - they are strings. I am trying to figure out the iterative way to run it as opposed to using sets!
- As far as first questions go, this is really good; have my upvote. Looks like you're making a hangman game, and this is the check-if-they-found-the-word step?