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Given a list of numbers, you have to print those numbers which are not multiples of 3 in python 3
The first line contains the list of numbers separated by a space.
Print the numbers in a single line separated by a space which are not multiples of 3.
1 2 3 4 5 6
1 2 4 5
Here the elements are 1,2,3,4,5,6 and since 3,6 are multiples of 3, removing them the list leaves 1,2,4,5.
Please don't ask by just copying your nptel assignment questions and ask for a solution, first try to solve and find where the bug is, how the input is given and what is the desired output. I also got stuck on this assignments before. Anyways here's the solution that should work fine, if it gets the job done, don't forget to accept the solution by clicking the tick on the left of this post.
x = input() num = list(map(int, x.split())) l = for i in num: if i%3 != 0: l.append(i) print(*l, sep = " ")
Python Exercise: Find numbers which are divisible by 7 and multiple , A Simple Solution is to iterate over all numbers from 1 to n and increment count whenever a number is a multiple of 3 or 7 or both. C++; Java; Python3; C#; PHP. C� In this tutorial, we are going to write a program to find out m multiples of a number n without using loops. For example, we have a number n = 4 and m = 3, the output should be 4, 8, 12.
There are any number of one-liner solutions. How about:
print(*(item for item in map(int, input().split()) if item % 3))
Multiples of 3 or 7, Given a positive number n, write a function isMultipleof5(int n) that returns true if n is Output : 19 is not a multiple of 5. Method 2 (Convert to string and check the last character) Method 3 (Set last digit as 0 and use floating point trick) Median of sliding window in an array | Set 2 � Check if the given array is same as its� This is a python program to print all the numbers which are divisible by 3 and 5 from a given interger N. There are numerous ways we can write this program except that we need to check if the number is fully divisble by both 3 and 5. Below is my code to write a python program to print all the numbers divisible by 3 and 5 −
Use the modulo operator. (%) This operator will yield the remainder from the division of the first argument with the second. So when you are wanting numbers that are not multiples of 3, another way to say that is you are looking for numbers whose remainder is not 0 when divided by 3.
x % 3 != 0.
Check if a number is multiple of 5 without using / and % operators , Finding the multiple of 3 and 5 � python fizzbuzz. Write a program that prints the numbers from 1 to 100. But for multiples of three print “Fizz”� Output: 1 2 3 4 5 Without using loops: * symbol is use to print the list elements in a single line with space. To print all elements in new lines or separated by
The Logic is really simple, You need to remove all the number from the list that is divisible by 3.
Since list is used list.remove(item) method can be used.
and the output should be space separated so the list of the item can be joined together using space in between them,
Following code does the trick
numbers = input() list = numbers.split() for item in list: if int(item)%3==0: list.remove(item) print(' '.join(list))
Input: 1 2 3 4 5 6
Output: 1 2 4 5
Finding the multiple of 3 and 5, What is the condition to add numbers from two lists in Python using a nested for loop? In Python 3, it's just. print(*a). This trick uses unpacking to pass the list items to If that's not there, it will print in next line which is equivalent to end=\n . Given n and m, print first m multiples of a m number without using any loops in Python. Examples: Input : n = 2, m = 3 Output : 2 4 6 Input : n = 3, m = 4 Output : 3 6 9 12
list(filter(lambda x: x%3 != 0 , yourlist))
How to output a list of numbers as numbers separated by space in , Python Program to Find Those Numbers which are Divisible by 7 and Multiple of 5 3. Then find the numbers which are divisible by both 5 and 7. 4. Print those� Write a Python program to compute the sum of all the multiples of 3 or 5 below 500. All the natural numbers below 12 that are multiples of 3 or 5, we get 3, 5, 6, 9 and 10. The sum of these multiples is 33. Sample Solution:- Python Code: n = 0 for i in range(1,500): if not i % 5 or not i % 3: n = n + i print(n) Sample Output: 57918
Python Program to Find Those Numbers which are Divisible by 7 , If you try to read or write an element that does not exist, you get a runtime error: Lists that contain consecutive integers are common, so Python provides a simple way to create The first example prints all the multiples of 3 between 0 and 19. For numbers which are multiples of both 3 and 5, print “Multiple of 3. Multiple of 5.” instead of the number. Examples: Input : 15 Output : 1 2 Multiple of 3. 4 Multiple of 5. Multiple of 3. 7 8 Multiple of 3. Multiple of 5. 11 Multiple of 3. 13 14 Multiple of 3.
9. Lists — How to Think Like a Computer Scientist: Learning with , 72 PureBasic; 73 Python; 74 Q; 75 R; 76 Racket; 77 Raku; 78 REXX PROC sum of multiples of 3 and 5 below = ( LONG LONG INT n )LONG LONG INT: Net 4 and upwards) is not itself efficient because calculations take place in Also a method for calculating sum of multiples of any list of numbers. range(1, 500) will generate a Python list of 499 integers in memory. So It will use high memory and increased execution speed; xrange(1, 500) function doesn’t generate all numbers at once. It produces number one by one as for loop moves to the next number. Use of range() in Python 3. Python 3’s range() function returns the range object, i.e
Sum multiples of 3 and 5, But for multiples of three print “Fizz” instead of the number and for the Bottom- line: if you're new to programming and FizzBuzz confuses you: no big deal, lots of in that file, then executing it with the command-line Python interpreter, i.e.: Thus, 9 and 99 are multiples, because dividing them by 3 yields a remainder of 0 . Write a program that prints the numbers from 1 to 100. But for multiples of three print “Fizz” instead of the number and for the multiples of five print “Buzz”. For numbers which are multiples of both three and five print “FizzBuzz”. Is this the best way of doing this?
- You should try solving the problem by yourself and adding your attempt(s) to the question.
- Nice one! That one would fit as 4th in my answer.
- This code won't work correctly. Try running it with "1 3 6 8 9 12"
- Your third and final example doesn't run as the assignment to
newListisn't needed nor legal syntax, and gets interpreted as an unknown keyword argument to
- sorry, typo. I fixed it.