How can I have is null condition in typeorm find options?

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I'm using typeorm find options for my queries How can I have IS NULL condition in the where clause?

Another way is you can use IsNull() function, for example:

import { IsNull } from "typeorm";
return await getRepository(User).findOne({
    where: { 
      username: IsNull()
    }
});

How to use isNull and isNotNull with querybuilder? · Issue #4000 , TypeORM version: [x] latest [ ] @next [ ] 0.x.x (or put your version here). I have been searching for a long time but I don't find how to use isNull  TypeORM version: [x] latest [ ] @next I have been searching for a long time but I don't find how to use isNull and isNotNull with queryBuilder:. IMO the post also contains "enough rope" to hang static typing with. Connor and Chris don't just spend all day on AskTOM. In standard SQL, a Boolean value can be TRUE, FALSE, or NULL.

You can use QueryBuilder for this purpose:

const users = await userRepository.createQueryBuilder("user")
     .where("user.name IS NULL")
     .getMany();

Feature Request, Now simple condition can only use equivalence match(=), but in actual Additional findOptions - range and where OR #1208 Of course for sql keywords we have to define new shortcut operators like Passing array object in find Method (TypeORM) #1385 Added IsNull AND Not(IsNull()) examples  I tried the variant with the costumRepository as in your documentation (typeorm.io) too, with the same unsatisfying result. When I do the same with a queryBuilder it works! But refactoring all the find/findOne methods with conditions/options to queryBuilder is no option as I would have to do it several hundred times manually. this is an example

In addition to hungneox answer you should know that you have a lot of predefined operators.

This is from the file that defines it:

export declare type FindOperatorType = "not" | 
"lessThan" | 
"lessThanOrEqual" | 
"moreThan" | 
"moreThanOrEqual" | 
"equal" | 
"between" | 
"in" | 
"any" | 
"isNull" | 
"like" | 
"raw";

Each of the above can be set in the "Operator" part here:

{ 
  where: { 
    propertyToCheck: <Operator>
  }
}

You just import it from the @typeorm package and use it like a function e.g LessThan():

import { Repository, Between, IsNull, LessThan } from 'typeorm';

{ 
  where: { 
    age: LessThan(50)
  }
}

This is really strong and important tool to know if you want to master typeorm :) Good luck!

Both null and undefined find option value should generate IS NULL , I found that when use find function with option. Using null in TypeScript requires checking for more conditions and being more explicit because Here is what I am seeing with postgresql backend currently (typeorm-0.2.7):. Both null and undefined find option value can generate IS NULL query #738 Closed yujiahaol68 wants to merge 1 commit into typeorm : master from yujiahaol68 : tecker-fix

I really don't like to have to use the QueryBuilder from TypeORM for this as this should, in my opinion, be treated as expected when using FindConditions.

Unfortunately, with something like the following code:

async articleRequests(
  accepted?: ArticleRequestAcceptance,
): Promise<ArticleRequest[]> {
  const where: FindConditions<ArticleRequest>[] | FindConditions<ArticleRequest> = {};

  if (accepted !== undefined) {
    switch (accepted) {
      case ArticleRequestAcceptance.Accepted:
        where.accepted = true;
        break;
      case ArticleRequestAcceptance.Rejected:
        where.accepted = false;
        break;
      case ArticleRequestAcceptance.NotReviewedYet:
        where.accepted = undefined;
        break;
    }
  }

  return await ArticleRequest.find({ where }).catch(reason => {
    throw reason.message;
  });
}

TypeORM gets you a SQL query that looks like this:

SELECT '...' WHERE "ArticleRequest"."accepted" = NULL

because, as can be seen from TypeORM log output, ... WHERE "ArticleRequest"."accepted" = @0 -- PARAMETERS: [null], properties with undefined values (accepted in this case) get converted to nulls inside the parameters array and then they are simply injected into the SQL string.

The SQL standard says that any comparison with null results in null so for comparison operators, like = or <>, in SQL this should make no sense, but the reasoning is that comparing to null means "unknown" so that why such queries don't return any results. If you ask me, SQL is broken here.

So yeah, as @hungneox said, the solution is to use IsNull() which returns a special FindOperator for that specific column you need to be queried as IS NULL and not = NULL.

Like this:

  if (accepted !== undefined) {
    switch (accepted) {
      case ArticleRequestAcceptance.Accepted:
        where.accepted = true;
        break;
      case ArticleRequestAcceptance.Rejected:
        where.accepted = false;
        break;
      case ArticleRequestAcceptance.NotReviewedYet:
        where.accepted = IsNull();
        break;
    }
  }

Find options nested where · Issue #3902 · typeorm/typeorm · GitHub, @Kononnable Kononnable added the comp: find options label on Apr 6, 2019 I have the same issue const deleteResult = await ListMembership.delete({ list: { id: Not(IsNull()), owner: { id: user.id } }, user: { id: user.id }, });. When you create a primary key constraint, none of the columns included in the primary key can have NULL constraints; that is, they must not permit NULL values. You need to update the row with a null value in the demo_text column with a valid value before you re-add the not null constraint.

Find Options, All repository and manager find methods accept special options you can use to query data you need without using QueryBuilder : where - simple conditions by which entity should be queried. If you are using typeorm with MSSQL, and want to use take or limit , you need SELECT * FROM "post" WHERE "title" IS NULL. I'm using typeorm find options for my queries How can I have IS NULL condition in the where clause? sql where-clause typeorm typeorm-activerecord asked Oct 22 '17 at 22:38

Entity Manager and Repository - Find Options, ```typescript userRepository.find({ take: 10 }); ``` ** If you are using typeorm with MSSQL, and want to use `take` or `limit`, you need to use the following error: `'​Invalid usage of the option NEXT in the FETCH statement. "title" IS NULL ``` * `​Raw` ```ts import {Raw} from "typeorm"; const loadedPosts = await connection. to be honest, the syntax of using an array form of where implies or condition is pretty bad design, as well as the key-value form of where means and condition. Don't make people guess . From a person using SQLAlchemy in Python, it has helper functions like and_ and or_ where each accepts a list of conditions, so you can nest them all together

Find Options * [Basic options](#basic-options) * [Advanced options , @felipesabino Yeah, about NULL option in docs This clause is only provided for compatibility with Too specific requirement Help, for some reason i give the connection a User class but whe asking for the Repository i get error: But my needed is to filter result with a deep where clause by the find (or findMany) method in a generic service (model agnostic) where conditions are given from HTTP query parameters. So, I don't have any doubt about your solution with the query builder, but if it's possible, I prefer a solution where I don't need to make an ORM over an ORM.

Comments
  • That is the manual way of doing it, but if you see this typeorm code it can do it for you - I'm just not sure how.
  • Maybe it helps somebody if you need not null values use: .where("user.name IS NOT NULL")