Reading a file and then sorting it into 10 columns

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I'm looking to sort a txt file that contains 1199 numbers in 10 columns per row, and I know that the last row will have 10 or fewer columns. However, I'm getting 11 columns on the first row.

Thanks for the help.

#include <stdio.h>

#define t 1024

int main()
{
    int i=0, c;
    char p[t];
    FILE *f;
    f = fopen("CMB.txt", "r");
    while ((c = getc(f)) != EOF)
    {
        fscanf(f, "%s", p);
        if(i%10 == 0 && i > 0)
        {
            printf("\n");
        }
        printf("%s ", p);
        if (c == '\n')
        {
            i++;
        }
    }
    printf("\n %d", i+1);
    fclose(f);
}

When I try your code it prints correctly the 10 columns you are expecting , perhaps you didn't recompile after modifying. This is your code , I only removed the file reading and printing char.

#include <stdio.h>

int main()
    {
        int i=0;
        //, c;
       // char p[t];
       // FILE *f;
       // f = fopen("CMB.txt", "r");
        while (i<30)
        {
          //  fscanf(f, "%s", p);
            if(i%10 == 0 && i > 0)
            {
                printf("\n");
            }
            printf("%d ", i);
           // if (c == '\n')
           // {
                i++;
           // }
        }
        // printf("\n %d", i+1);
       // fclose(f);
    }

Windows 10 For Dummies, Click Size, for example, to reverse the order, placing the largest files at the list's top. (I always add a Date Taken column to my photos, so I can sort my photos by the Then from the desktop, click the taskbar's File Explorer icon and look at the with the disc drives in your computer: » DVD-RW: These drives both read and  I'm looking to sort a txt file that contains 1199 numbers in 10 columns per row, and I know that the last row will have 10 or fewer columns. However, I'm getting 11 columns on the first row.

Continuing from my earlier comment, when reading columns of data from a text file, it is generally better to read a line of input at a time with a line-oriented input function such as fgets or POSIX getline and then to parse the data from the buffer filled with sscanf (or walking a pointer down the buffer picking out what you need)

In your case when dealing with a fixed number of columns (10) where less than all values may be present, sscanf provides a way to determine exactly how many values are present in each row while allowing you to make use of the data if less than 10 are present.

sscanf (as with all scanf functions) returns the number of successful conversions took place based on the format string you provide (or returning EOF if the end of input is encountered before a conversion takes place). If you want to read 10-integer values from each line of data into an integer array names arr, you could use fgets to read the line into a buffer (say buf) and then separate the integer values head in buf with sscanf, e.g.

    ...
    while (fgets (buf, MAXC, fp)) { /* read each line into buf */
        /* parse into integer values with sscanf saving return */
        int rtn = sscanf (buf, "%d %d %d %d %d %d %d %d %d %d",
                        &arr[0], &arr[1], &arr[2], &arr[3], &arr[4],
                        &arr[5], &arr[6], &arr[7], &arr[8], &arr[9]);
    ...

Then you simply validate the return (rtn) using whatever if..else or switch... statements you need. Here we can simply sum the number of values read and output the row number for any row containing less than COL number of values for purposes of this example, e.g.

        ...
        if (rtn > 0)    /* did at least one conversion take place? */
            n += rtn;   /* increment count of values read */

        if (rtn < COL)  /* were less than COL values read? */
            printf ("row[%zu]: %d values read.\n", row + 1, rtn);

        row++;  /* increment row count */
    }

Putting it altogether, you could do something like the following:

#include <stdio.h>

#define COL    10
#define MAXC 1024

int main (int argc, char **argv) {

    char buf[MAXC];
    int arr[COL] = {0};
    size_t n = 0, row = 0;
    /* use filename provided as 1st argument (stdin by default) */
    FILE *fp = argc > 1 ? fopen (argv[1], "r") : stdin;

    if (!fp) {  /* validate file open for reading */
        perror ("file open failed");
        return 1;
    }

    while (fgets (buf, MAXC, fp)) { /* read each line into buf */
        /* parse into integer values with sscanf saving return */
        int rtn = sscanf (buf, "%d %d %d %d %d %d %d %d %d %d",
                        &arr[0], &arr[1], &arr[2], &arr[3], &arr[4],
                        &arr[5], &arr[6], &arr[7], &arr[8], &arr[9]);
        if (rtn > 0)    /* did at least one conversion take place? */
            n += rtn;   /* increment count of values read */

        if (rtn < COL)  /* were less than COL values read? */
            printf ("row[%zu]: %d values read.\n", row + 1, rtn);

        row++;  /* increment row count */
    }
    if (fp != stdin) fclose (fp);   /* close file if not stdin */

    printf ("%zu values read from file.\n", n);
}

Example Input File

Reading a data file with 10-integers per-row for 119 rows and reading a final row with 9-integers as you describe in your question, you could use an input file like:

$ head -n4 dat/1199_10col.txt; echo "<snip>"; tail -n4 dat/1199_10col.txt
    1    2    3    4    5    6    7    8    9   10
   11   12   13   14   15   16   17   18   19   20
   21   22   23   24   25   26   27   28   29   30
   31   32   33   34   35   36   37   38   39   40
<snip>
 1161 1162 1163 1164 1165 1166 1167 1168 1169 1170
 1171 1172 1173 1174 1175 1176 1177 1178 1179 1180
 1181 1182 1183 1184 1185 1186 1187 1188 1189 1190
 1191 1192 1193 1194 1195 1196 1197 1198 1199

Example Use/Output

Running the code against the above file would yield the expected results of reading 1199 values, 10-integers per-row with 9-integers read from the final row with notice of the short row:

$ ./bin/read10col <dat/1199_10col.txt
row[120]: 9 values read.
1199 values read from file.

While there are many ways to do this, and arguably using fgets with strtol provides opportunity for finer grained error detection, this is probably one of the more simple and straight-forward approaches.

Look things over and let me know if you have further questions.

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Why do you read a character before the first number? Why do you only increment i if this character is a newline?

If the file contains just numbers, you can simplify the code this way:

#include <stdio.h>

int main() {
    int i, n;
    FILE *f = fopen("CMB.txt", "r");
    if (f != NULL) {
        for (i = 0; fscanf(f, "%d", &n) == 1; i++) {
            /* output the number followed by a tab, or by a newline every 10 numbers */
            printf("%d%c", n, "\t\n"[i % 10 == 9]);
        }
        if (i % 10 != 0) {
            printf("\n");
        }
        fclose(f);
    }
    return 0;
}

Understanding Computers: Today and Tomorrow, Comprehensive, While the database tables in a column database appear to the COLUMN needs to read only three columns of data in order to access the symbol, price, and date on the storage medium (by columns instead of by rows) is different than the way it As shown in the figure, indexes are sorted in order by the primary key field  I have a file which I am trying to read and then sort by column A and then by column C. The text file is attached and has 3 columns. This is what I have tried but it will not let me use the sort function after reading it in this way:

#include <stdio.h>
#include <stdlib.h>

int main()
{
  FILE * fp;
  char *line;
  int i;
  size_t len = 0;
  fp = fopen("CMB.txt", "r");

  while (getline(&line, &len, fp) != -1)
  {
    fscanf(fp, "%s", line);
    if(i%10 == 0 && i > 0)
    {
      printf("\n");
    }
    printf("%s\t ", line);
    i++;
  }
  printf("\n\n%d", i);
  fclose(fp);
  return 0;
}

So now the numbers from the file are sorted in 10 columns, but the last line only have 8 columns when it should have 9. When I count (i) to see how many lines the while loop reads it only reads 1198, but i should read 1199. So I'm guessing it's skipping the first line? Appreciate the help :D

How To Sort A Text File In Java?, Java program to sort a text file containing records in single column or Step 1 : Create BufferedReader object to read the input text file. 10. 11. 12. 13. 14. 15. 16. 17. 18. 19. 20. 21. 22. 23. 24. 25. 26. 27. 28. 29 when I am running the 1st program with try with resources than the text file is getting empty. (b) Read the whole file into memory with one fread. (c) Run through the memory image of the text and count the rows. (d) Malloc space for an array of structs containing just the key and a pointer for each row. (e) Fill that array by running through the file image in memory, converting each key and saving it with the pointer to the start of the row.

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Java: Read a File into an ArrayList, If, for an example, our file contains a long list that we want to sort, we'll have to read it into an adequate data structure, perform operations, and then persist it once again - in Since Java 7, it's possible to load all lines of a file into an ArrayList in a very simple way: 12 some data we want to read as a string in one line 10. Hi, I have a requirement whereby I have to sort a flat file based on Multiple Columns (similar to ORDER BY Clause of Oracle). I am getting 10 columns in the flat file and I want the file to be sorted on 1st, 3rd, 4th, 7th and 9th columns in ascending order. The flat file is pipe seperated. Any (15 Replies)

Linux sort Command Examples, sort is a very useful command line utility used to sort the lines of a file or input stream. sort can be used to sort input by entire #sorting a CSV by the values in column 2 then column 6 10. If we sort on text values based on text values we will get: Shell With no FILE, or when FILE is -, read standard input. For the avid Pythonistas looking for a challenge with sorting, try using more complex data types in sorting: nested iterables. Also, feel free to dive into the open source Python code implementations for the built-ins and read about the sort algorithm used in Python called Timsort.

Comments
  • Print c inside the loop, before the fscanf()
  • do you mean to put printf("%s ", p) before scanf ? if so it didn't help ;/
  • I meant printf("c is %d (%c)\n", c, c);
  • ok, now it prints the numbers 10 at a time but not in columns
  • When I try your code it prints correctly the 10 columns you are expecting , perhaps you didn't recompile after modifying.#include <stdio.h> int main() { int i=0; //, c; // char p[t]; // FILE *f; // f = fopen("CMB.txt", "r"); while (i<30) { // fscanf(f, "%s", p); if(i%10 == 0 && i > 0) { printf("\n"); } printf("%d ", i); // if (c == '\n') // { i++; // } } // printf("\n %d", i+1); // fclose(f); }
  • Sorry, but i dont get what im supposed to change? do i change the while loop or what? thanks for the help btw
  • I didn't change anything to your code, except commenting out the file related stuff. I compiled and it displays 10 columns. Is there a chance you call the wrong executable ? Try delete your object files , executable file, rebuild and run again.
  • No the i did it for me aswell but for some reson the fscanf onley reads 1198 insted of 1199
  • Hi BURITOS, I was commenting on your question : "However, I'm getting 11 columns on the first row." , the code above prints 0 to 9 and that is 10 columns on first column.
  • Could you send me the exakt one you build ?