Fall-through if default is in middle of switch case?

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I have a question. In a switch statement, is default tested for last even if it isn't last?

If so, in the following code snippet:

int i = 6;
int a=0, b=0, c=0;
switch (i) 
{
    case 1: 
    a++; 
    case 2: 
    default: 
    case 3: 
    b++; 
    case 6:
    c++; 
}
System.out.println(a + " " + b + " " + c); 

After matching with case 6, and incrementing the value of c, since there is no break, will it go back to default?

I did try this code and it didn't seemly go to default and a fall-through did not occur. I just wanted to know?

switch is evaluated from matching case to either break or end of switch statement. If you pass 6 it will enter case for 6 and do only one increment. But if you enter 7 it will start from default and fall through to the end of switch doing two increments.

Break on default case in switch, Does a break is required by default case in switch statement? About Fall Through Switch Statements In Java : It is not necessary for every case in the switch Statement In Java to have a break. Some times we might have a situation where we have the same or similar handling for multiple cases.

Currently, all of your cases will fall through, as no case has a break; as well, your switch is conditionally based on i, so if you want to see each case, you need to change i.

Utilizing break; should not have any effect on where your cases reside in your switch state, this is also the "case" for default

Edit: As @Ivan mentioned, if fall through is intended, then the placement of your cases will matter

switch Statement (C), out at the end of its last branch has the same result. If no break appears, the flow of control will fall through to subsequent cases until a break is reached. A switch statement can have an optional default case, which must appear at the end of the switch. The default case can be used for performing a task when none of the cases is true. No break is needed in the default case. Flow Diagram Example

There is no additional testing of case labels beyond the initial testing at the beginning of the switch statement. Once i has been evaluated by the switch statement, control transfers to the case 6: label because that matches i. Statements are then executed in order until the end of the switch statement, or until a break statement is encountered. This means that only c is incremented.

A break statement will only end the execution of the entire switch statement; whether a break statement is present has no effect on retesting the switch expression, because retesting the switch expression will not occur either way.

If you want default to be the case label entered, then i must not match any case label at the start of the switch statement. If i is 99 at the start of the switch statement, then both b and c are incremented (fallthrough occurs).

There is no restriction on where in the order of case labels a default label appears, only that at most one default occurs in a switch statement.

What is the use of a switch case and break statement in the C , What is the reason for using break statement at the end of each case in case control block? The default case. The default case specifies the switch section to execute if the match expression doesn't match any other case label. If a default case is not present and the match expression doesn't match any other case label, program flow falls through the switch statement. The default case can appear in any order in the switch statement.

OCAJP - How to use a switch statement?, char, byte, short, int, and String(starting from Java version 7). A fallthrough statement may only be used in a switch statement, where the next statement to be executed is a statement with a case or default label for that switch statement. If the fallthrough statement is inside a loop, the next (labeled) statement must be part of the same iteration of that loop.

The switch Statement, statement to conditionally perform statements based on an integer expression break; case 12: System.out.println("December"); break; default: Deciding whether to use an if statement or a switch statement is a judgment call. The break statements are necessary because without them, the case statements fall through. Following rules govern the fall through the behavior of switch statement. When the variable being switched on is equal to a case, the statements following that case will execute until a break statement is reached. When a break statement is reached, the switch terminates, and the flow of control jumps to the next line following the switch statement.

JavaScript: Is Fallthrough From Switch Statement A Troublemaker , A fallthrough from switch statement is handly for many cases. says, “if default comes in a middle of the switch block, break default as well.”. It performs a case-insensitive match for the value. If the value is a collection, each element is evaluated in the order in which it appears. The Switch statement must include at least one condition statement. The Default clause is triggered when the value does not match any of the

Comments
  • ...and that I suggest most people will do a double-take if default isn't last, so unusual is it to be found elsewhere.