A function that checks the average of dict items

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I'm trying to send a dictionary into a function that caculated the average, I believe my function is good but I'm having trouble with sending the dictionary

my_dict = {"first": 100, "second": 0, "third": 200}

def avg(dict):

    sum=0
    count=0
    for k,v in dict:
        sum = sum+v
        count +=1
    return(sum/count)


result = avg(**my_dict)

print(result)

The output should be 100 that goes into "result"

my_dict = {"first": 100, "second": 0, "third": 200}
def dictavg(your_dict):
    return sum(your_dict.values())/len(your_dict)
print(dictavg(my_dict))

Python, It is used to hash a particular key. A dictionary has multiple key:value pairs. There can be multiple pairs where value corresponding to a key is a list. To check that  Definition and Usage. The items() method returns a view object. The view object contains the key-value pairs of the dictionary, as tuples in a list. The view object will reflect any changes done to the dictionary, see example below.

Drop the asterisks and use .items() on the dict

my_dict = {"first": 100, "second": 0, "third": 200}

def avg(dict):

    sum=0
    count=0
    for k,v in dict.items():
        sum = sum+v
        count +=1
    return(sum/count)


result = avg(my_dict)

print(result)

Need some explaining, i don't really get average and dictionaries , def average(numbers): total = sum(numbers) total = float(total) return total / len(​numbers) where students refers to the list we created below our function. t = average(key[“tests”]) because we are storing value stored in dictionary named  Python | Count number of items in a dictionary value that is a list In Python, dictionary is a collection which is unordered, changeable and indexed. Dictionaries are written with curly brackets, and they have keys and values.

Pass your dictionary directly, not via the ** dictionary unpacking operator. Do the unpacking within your function instead: iterating dict.items gives key-value pairs, but here you can use dict.values.

Also, never shadow built-ins. So don't use dict, sum, etc as variable names.

This would work:

def avg(d):

    val_sum = 0
    count = 0
    for v in d.values():
        val_sum += v
        count += 1
    return(val_sum/count)

result = avg(my_dict)  # 100.0

You can also use the built-ins sum and len:

result = sum(my_dict.values()) / len(my_dict.values())

Or use statistics.mean:

from statistics import mean

result = mean(my_dict.values())  # 100

Finding average in dictionary using for loop, I'm supposed to get the average using a for loop, and I know I'm You could check this out: https://www.w3schools.com/python/python_naries.asp You want the values method, which in your case would just give you the  Method #3 : Using dict.items() items() , in dictionary iterates over all the keys and helps us to access the key-value pair one after the another in the loop and is also a good method to access dictionary keys with value.

You cannot use the following statement with a dictionary:

for k, v in dict:

instead there is a way to receive a list of the keys or the values of the dictionary using the methods keys() or values() respectively. these methods return a list of the dictionary keys or the dictionary values and then you can iterate over them. Also there is a method which returns a list of tuples of key and value - items().

So any of these should work for you:

my_dict = {"first": 100, "second": 0, "third": 200}

def avg(dicti):

    total_sum=0
    count=0
    for key in dicti.keys():
        sum += dicti[key]
        count +=1
    return(sum/count)

result = avg(my_dict)

print(result)

or:

my_dict = {"first": 100, "second": 0, "third": 200}

def avg(dicti):

    total_sum=0
    count=0
    for value in dicti.values():
        sum += value
        count +=1
    return(sum/count)

result = avg(my_dict)

print(result)

Python: Replace dictionary values with their average, Write a Python program to replace dictionary values with their average. Sample Solution:- Python Code: def sum_math_v_vi_average(  We use the code items() method for our Dict. When code was executed, it returns a list of items ( keys and values) from the dictionary; Check if a given key already exists in a dictionary. For a given list, you can also check whether our child dictionary exists in a main dictionary or not. Here we have two sub-dictionaries "Boys" and "Girls

Just try:

my_dict = {'first': 100, 'second': 0, 'third': 200}
avg = sum(my_dict.values()) / len(my_dict)

Associating Multiple Values with Each Key in a Dictionary, You need a dictionary that maps each key to multiple values. Each approach relies on the setdefault method of a dictionary to initialize the entry for a key in For example, you can use it to check if 'freep' is among the values for somekey : Python dictionary method items() returns a list of dict's (key, value) tuple pairs. Syntax. Following is the syntax for items() method − dict.items() Parameters. NA. Return Value. This method returns a list of tuple pairs. Example. The following example shows the usage of items() method.

Python Tutorial: Dictionaries, Tutorial on Dictionaries in Python: Operators and Methods of the Dictionary class. The values of a dictionary can be any type of Python data. popitem() is a method of dict, which doesn't take any parameter and removes and If we check the output, we can see that the title of course2 has been changed not only in the  Dictionary in Python is an unordered collection of data values, used to store data values like a map, which unlike other Data Types that hold only single value as an element, Dictionary holds key : value pair. In Python Dictionary, items() method is used to return the list with all dictionary keys with values. Syntax: dictionary.items()

Python Dictionary Methods, Getting Started Mean Median Mode Standard Deviation Percentile Data Python has a set of built-in methods that you can use on dictionaries. Method, Description fromkeys(), Returns a dictionary with the specified keys and value. Excel VBA Dictionary. Using VBA Dictionary we can group all kinds of data in a dictionary to get access to all the items with a single variable. We can use the dictionary to create a collection of key-value combinations. Once the object is linked to keys, later on, we can call them by just using the key name.

Dictionaries, The function dict creates a new dictionary with no items. can use the in operator as a fast way to check whether a string is in the dictionary. For example, if you are computing the average of a list of numbers, you could check that the result  Original items: dict_values([2, 4, 3]) Updated items: dict_values([4, 3]) The view object values doesn't itself return a list of sales item values but it returns a view of all values of the dictionary. If the list is updated at any time, the changes are reflected on to the view object itself, as shown in the above program.

Comments
  • sum(my_dict.values()) / len(d)
  • The output should be 100, right? Or do you wish to do something else?
  • k is not being used. You can just sum the values with sum(dict.values()).
  • Oh yeah, true.. I only changed the bits it failed on, didn't re-write it (or I would have also changed the poorly chosen variable names)
  • I wonder how to rewrite this if we were to pass as unpacking operator.
  • @YOLO, Unpacking doesn't help you solve your problem. So I advise you don't do it.
  • @jpg actually it is solvable with unpacking, just very superfluous. f = lambda **kwargs: sum(kwargs.values())/len(kwargs) then f(**my_dict)
  • @YOLO see my comment above
  • @DeepSpace, Yes, but that doesn't help. It's an extremely poor use of function arguments.