Program in c++ tell if a number is integer or float

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I used function overload to check if an input number is integer or float. However I get this following error: error: call of overloaded 'retNr(double)' is ambiguous|

#include <iostream>
using namespace std;

void retNr(int x)
{
    cout << "The entered number is an integer. " << endl;
}

void retNr(float x)
{
    cout << "The entered number is a float. " << endl;
}

int main()
{
    cout << "Please enter a number: " << endl;
    cin >> nr;
    retNr(nr);
    return 0;
}

Read from cin into a string and then check the string for the presence of a decimal point. If there is a decimal point, call atof() on the string to convert it to a float, otherwise call atoi() to convert it to an integer.

Program to check if input number is int or float in C, Program to check whether an input number is of int datatype or float datatype in C language with output and complete explanation. Alternately, nr could be read as a float every time, and then the program found check whether (nr == floor(nr)). If that equality is true, the number is an integer, even if the user entered something lime "12.0000". – Logicrat Jul 14 '14 at 15:11

Make some small change in:

void retNr(double x)
{
    cout << "The entered number is a double. " << endl;
}

Remember to declare your nr variable.

double d = 1.0;
int i = 1;

retNr(d);
retNr(i);

Write a program to find whether the entered number is an integer or , What is the C program that generates a list of all integers from 0 to 99 in random //Program to check whether number is int or float; //July 17,2018; //Narayan Lal​  If a floating-point value can also be a whole number, why bother using integers in your programs at all? The reason is that floating-point values and integers are handled differently inside the computer. An integer exists inside the computer as a true binary value. For example, the value 123 is stored in modern computers as …

You will have to initialize nr first.

Then you can use integer read & check it with a float if there is dot, ie ch=='.'

Thus, your program will be like this:

#include <iostream>
using namespace std;

int main()
{
    int nr = 0; char ch;
    cout << "Please enter a number: " << endl;
    cin >> nr;
    cin.get(ch);
    if(ch=='.')
    {
        cout << "The entered number is a float. " << endl;
    }
    else
    {
         cout << "The entered number is an integer. " << endl;
    }


    return 0;
}

Program to check if input is an integer or a string, Write a function to check whether a given input is an integer or a string. Check if a given string is a valid number (Integer or Floating Point) in Java · Check if a  C++ Program to Find Size of int, float, double and char in Your System. his program declares 4 variables of type int, float, double and char. Then, the size of each variable is evaluated using sizeof operator. To find the size of variable, sizeof operator is used.

You may use abs() function for this issue.

#include<stdio.h>
#include<math.h>

int main()
{
   double input;
   scanf("%lf",&input);

   int absulate = abs(input);
   printf( (input==absulate)? "It is integer\n" : "It is float");

   return 0;
}

Did you write "if type(a) == int or float" and it's not working? See here , So if you typed: "Not an integer or a float" it would return as an error because 'a' I'm very new to programming and I can't imagine I would have ever figured out on def distance_from_zero(b): c = type(b) if c == int or c == float: return abs(b)  This C program lets the user enter One integer value, character, and a float value. And then we use the printf statement to print them out. Within this program to Print Integer, Char, and Float value example; first, we declared three variable of type Integer, Character, and Float.

The question is wrong in its essence: A number it is not a float or an integer, but could be represented as a float or as an integer ( of course certain representation has some limitations ) So if I wrote '10' why should I say this is an integer? Could be a float too! Just if I want to use it as a float I would represent it as a float.

Finding out if a number is a whole number or a floating point value , Hi, does anyone know a good way to find out if a number is a whole number or a like PHP/C, does not differentiate between integer values and floating-point values. The question I was asking was whether the program needs to distinguish  For a more complete answer, google. If you want to know if a number in a string is a float, and you are sure the number is well formed in the string, convert the string to a float using for example std::stof. Then convert that float to an int and compare to the float. This should work Continue Reading.

C Program to Print an Integer (Entered by the User), In this example, the integer entered by the user is stored in a variable and printed on the screen. To understand this example, you should have the knowledge of  Integer arithmetics. We already know the following operators which may be applied to numbers: +, -, * and **. The division operator / for integers gives a floating-point real number (an object of type float). The exponentiation ** also returns a float when the power is negative:

How to Check Number is Integer Or Float in C, You must name each one of your “bricks” and tell C++ what type of “brick” to use. There is a vast difference between an integer divide and a floating-point  Below code checks, if the variable ‘n’ belongs to any of the str, int or float data type. n =17 isinstance(n, (str, int, float) #True Here is a simple program that takes input from the user and saves in variable var. Based on the data entered by the user, the data type of the var changes.

4. Basic Declarations and Expressions, 1) Using Modulus operator(%) 2) Using Bitwise operator. Program 1: Using Modulus operator. /* Program to check whether the input integer number * is even or  round() function in C returns the nearest integer value of the float/double/long double argument passed to this function. If decimal value is from ”.1 to.5″, it returns integer value less than the argument. If decimal value is from “.6 to.9″, it returns the integer value greater than the argument.

Comments
  • Where is nr declared? Then you'll see the problem with what you're trying to do.
  • it will always call the overloaded function which matches the declared type of nr -- it will not depend on the input (like in javascript)
  • What you need to do, presumably, is read in to a string, and parse that.
  • You can input to a std::string value, and use the std::stof function if a valid float was read.
  • Static typing does not work like you think it does.
  • Note atoi() should be called first, to check if the input was a valid int, if this fails you can check with atof() if the input was a valid float.
  • @πάνταῥεῖ I think you must still check for the dot. "The string can contain additional characters after those that form the integral number, which are ignored and have no effect on the behavior of this function."
  • For completeness I would also check for the presence of the letter 'e', as a number of the form "1e-2" is a valid float.
  • And of course, you wouldn't use atof or atoi, but rather strtod and strtol. Actually, the simplest solution might be to use strtol, then see if the end pointer points to '.', 'E' or 'e', and have another go of it using strtod if it is.
  • Alternately, nr could be read as a float every time, and then the program found check whether (nr == floor(nr)). If that equality is true, the number is an integer, even if the user entered something lime "12.0000".
  • Program in c++ not in C.
  • As a mathematician I would say, all integers are also real numbers, but not all real numbers are integers.