SQL Order By Count

sql group by count greater than 1
sql count columns with specific value
sql-order by count in related table
sql count(distinct)
sql-order by count distinct
count of blood groups sql
order by count mysql
sum(count sql)

If I have a table and data like this:

ID |  Name  |  Group   

1    Apple     A    

2    Boy       A

3    Cat       B

4    Dog       C

5    Elep      C

6    Fish      C

and I wish to order it according to the total of Group from smallest to largest value, such as : A - 2 records , B - 1 record , C - 3 records , so it will become:

3    Cat       B

1    Apple     A    

2    Boy       A

4    Dog       C

5    Elep      C

6    Fish      C

I tried

    $sql = "SELECT ID,Name FROM table ORDER BY COUNT(Group)";

but it just returns one result for me.

Are there any hints? Thank you.

You need to aggregate the data first, this can be done using the GROUP BY clause:

SELECT Group, COUNT(*)
FROM table
GROUP BY Group
ORDER BY COUNT(*) DESC

The DESC keyword allows you to show the highest count first, ORDER BY by default orders in ascending order which would show the lowest count first.

SQL COUNT() with GROUP by, The utility of ORDER BY clause is, to arrange the value of a column ascending or descending, whatever it may the column type is numeric or  eTour.com is the newest place to search, delivering top results from across the web. Content updated daily for how to learn sql.

SELECT group, COUNT(*) FROM table GROUP BY group ORDER BY group

or to order by the count

SELECT group, COUNT(*) AS count FROM table GROUP BY group ORDER BY count DESC

SQL GROUP BY | COUNT, The general syntax with ORDER BY is: SELECT column-names; FROM table-​name; WHERE condition  Search for Free Sql Databases on the New Internetcorkboard.com

...none of the other answers seem to do what the asker asked.

For table named 'things' with column 'group':

SELECT
  things.*, counter.count
FROM
  things
LEFT JOIN (
  SELECT
    things.group, count(things.group) as count
  FROM
    things
  GROUP BY
    things.group
) counter ON counter.group = things.group
ORDER BY
  counter.count ASC;

which gives:

id | name  | group | count 
---------------------------
3  | Cat   | B     | 1
1  | Apple | A     | 2
2  | Boy   | A     | 2
4  | Dog   | C     | 3
5  | Elep  | C     | 3
6  | Fish  | C     | 3

SQL COUNT, SQL COUNT example. The pending order is the order whose shipped date is NULL . To get the number of pending orders, you use the following query:  SQL COUNT ( ) with group by and order by . In this page, we are going to discuss the usage of GROUP BY and ORDER BY along with the SQL COUNT() function. The GROUP BY makes the result set in summary rows by the value of one or more columns. Each same value on the specific column will be treated as an individual group.

Try :

SELECT count(*),group FROM table GROUP BY group ORDER BY group

to order by count descending do

SELECT count(*),group FROM table GROUP BY group ORDER BY count(*) DESC

This will group the results by the group column returning the group and the count and will return the order in group order

SQL question: Select COUNT(*) and then order , SQL question: Select COUNT(*) and then order by COUNT - This works: select product_id, count(*) from order_line group by product_id It  SQL HOME SQL Intro SQL Syntax SQL Select SQL Select Distinct SQL Where SQL And, Or, Not SQL Order By SQL Insert Into SQL Null Values SQL Update SQL Delete SQL Select Top SQL Min and Max SQL Count, Avg, Sum SQL Like SQL Wildcards SQL In SQL Between SQL Aliases SQL Joins SQL Inner Join SQL Left Join SQL Right Join SQL Full Join SQL Self Join SQL

SELECT * FROM table 
group by `Group`
ORDER BY COUNT(Group)

How to Order by Count in SQL?, Operators: COUNT, ORDER BY, ASC, DESC, GROUP BY. Problem: You aggregated data into groups, but you want to sort the records in descending order by  SQL COUNT(*) with ORDER BY clause example. You can use the COUNT(*) function in the ORDER BY clause to sort the number of rows per group. For example, the following statement gets the number of employees for each department and sorts the result set based on the number of employees in descending order.

How to use SQL SELECT, GROUP BY, ORDER BY, and COUNT (all , But just now I was happy to write this little SQL SELECT query that does a GROUP BY, an ORDER BY, and a COUNT, yielding the results  Problem: List the number of customers in each country sorted high to low SELECT COUNT(Id), Country FROM Customer GROUP BY Country ORDER BY COUNT(Id) DESC Results: 21 records.

SQL, The ORDER BY statement in sql is used to sort the fetched data in either ascending or descending according to one or more columns. By default ORDER BY  So I used the SQL Server Replicate function along with the length of the longest number to pad any shorter numbers with a leading space. Now 20 is sorted after 3, and so on. I was working with a view that gave me the minimum and maximum lengths, widths, etc for the item type and class, and here is an example of how I did the text.

LIMIT and ORDER BY in SQL Queries, By default, ORDER BY sorts in ascending order. When it comes to numbers, that means smallest first. If we want to find the rows with the largest count values, we  SQL HOME SQL Intro SQL Syntax SQL Select SQL Select Distinct SQL Where SQL And, Or, Not SQL Order By SQL Insert Into SQL Null Values SQL Update SQL Delete SQL Select Top SQL Min and Max SQL Count, Avg, Sum SQL Like SQL Wildcards SQL In SQL Between SQL Aliases SQL Joins SQL Inner Join SQL Left Join SQL Right Join SQL Full Join SQL Self Join SQL

Comments
  • Thank you so much for your answer , but it return me one result per group only? such as : Cat,B | Apple , A | Dog , C
  • Are you running this code or some other code? Based on the first table you provided the output of this query would be: C 3 A 2 B 1
  • Thanks for your asnwer , I tried it but it return me one result per group ? such as : Cat,B | Apple , A | Dog , C .
  • @IreneLing I didnt include the Name in the select statement - check it
  • Thanks for your answer, but sorry it didn't give me the correct result.