How can I set text the array 0 or fname in JSONobject I'm new in using JSON

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My JSON file looks like the following.

{
  "data": [{
      "fname": "Ralph",
      "lname": "Rojas",
      "pid": "444"
  }]
}

I've got a little problem with parsing JSON into my android app. This is what I have tried so far.

JSONArray arr;
try {
    arr = new JSONArray(json_string);
    JSONObject jObj = arr.getJSONObject(0);
    fname = jObj.getString("fname");
} catch (JSONException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}
runOnUiThread(new Runnable(){
    public void run() {
       Toast.makeText(getApplicationContext(),fname,Toast.LENGTH_LONG).show();
    }
});

Toast.makeText(getApplicationContext(), fname, Toast.LENGTH_LONG).show();
name = (TextView)findViewById(R.id.name);
name.setText(fname);

Try this

JSONObject obj;
    try {
        obj = new JSONObject(json_string);
        JSONArray arr = obj.getJSONArray("data");
        JSONObject obj1 = arr.getJSONObject(0);
        fname = obj1.getString("fname");
    } catch (JSONException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    runOnUiThread(new Runnable(){
        public void run() {
           Toast.makeText(getApplicationContext(),fname,Toast.LENGTH_LONG).show();
        }
        });


    Toast.makeText(getApplicationContext(), fname, Toast.LENGTH_LONG).show();
    name = (TextView)findViewById(R.id.name);
    name.setText(fname);

org.json.JSONArray.getJSONObject java code examples, int id; String name; JSONArray array = new JSONArray(string_of_json_array); for (int i = 0; JSONArray. JSONArray array; for(int n = 0; n < array.length(); n++) { JSONObject object = array. getJSONObject(0); firstNameRef.set(jsonObject. This article shows how to use the System.Text.Json namespace to serialize and deserialize to and from JavaScript Object Notation (JSON). If you're porting existing code from Newtonsoft.Json, see How to migrate to System.Text.Json. The directions and sample code use the library directly, not through

Use Gson for easy JSON parsing.

You just have to add the following dependency in your build.gradle file.

implementation 'com.google.code.gson:gson:2.8.5'

And then in your code, create the following classes first.

public class Data {
    public People[] data;
}

public class People {
    public String fname;
    public String lname;
    public String ppid;
}

Now parse the JSON like the following.

Gson gson = new Gson();
Data data = gson.fromJson(yourJSONString);

You will find the values parsed in your data variable.

Hope that helps!

org.json.JSONObject.getString java code examples, int id; String name; JSONArray array = new JSONArray(string_of_json_array); for (int i = 0; i < array.length(); getJSONObject(0); firstNameRef.set(jsonObject. Strings that can be coerced using Double#valueOf(String) will be, and then cast to int. When the requested type is a long, other Number types will be coerced using Number#longValue(). Strings that can be coerced using Double#valueOf(String) will be, and then cast to long. This two-step conversion is lossy for very large values.

You need to create JSONObject before you retrieve JSONArray from it. Here is example code.

 try {
    JSONObject jsonObject = new JSONObject(json_string);
    arr = jsonObject.getJSONArray("data");
    JSONObject jObj = arr.getJSONObject(0);
    fname = jObj.getString("fname");
} catch (JSONException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}

JSONSetElement, json - any text expression or field that contains a JSON object or array. keyOrIndexOrPath - any text expression or field that specifies a JSON object name (key), an array index, or a path. See Working This function returns json with value set at the specified keyOrIndexOrPath. [ "bakery.product[0].stock" ; 0 ; JSONNumber ] Yes, as others have stated, the JSON is actually an Array (of a single Object). So you will need to reference an index. Interestingly enough (to me), your result string does validate successfully as JSON. I assumed until now, that to be valid JSON, it had to be an Object (ie, {}).

You could do like this:

    JSONArray arr;
    JSONObject obj = null;
    try {
        obj = new JSONObject(json_string);
        arr = obj.getJSONArray("data");//Firstly get outer most json array
        JSONObject rlt = arr.getJSONObject(0);//then get item in json array
        fname = rlt.getString("fname");
    } catch (JSONException e) {
        e.printStackTrace();
    }

JSONObject, json - any text expression or field that contains a JSON object or array. any text expression or field that specifies a JSON object name (key), an array index, or a path. This function returns json with value set at the specified keyOrIndexOrPath . For JSONBoolean , if value is true or a non-zero number, it is treated as true;  The square brackets [ ] are used to declare JSON array. JSON array are ordered list of values. JSON array can store multiple value types. JSON array can store string, number, boolean, object or other array inside JSON array. In JSON array, values must be separated by comma. Arrays in JSON are almost the same as arrays in JavaScript. e.g.

you must first capture a JSONObject and in it get the JSONArray, this code worked for me. I hope it works and good luck !!

String json = "{\"data\": [{\"fname\": \"Ralph\",\"lname\": \"Rojas\",\"pid\": \"444\"}]}";

    JSONObject obj;
    JSONArray arr;
    try {
        obj = new JSONObject(json);

        arr = obj.getJSONArray("data");
        fname=arr.getJSONObject(0).getString("fname");
    } catch (JSONException e) {
        e.printStackTrace();
    }
    runOnUiThread(new Runnable(){
        public void run() {
            Toast.makeText(getApplicationContext(),fname,Toast.LENGTH_LONG).show();
        }
    });


    Toast.makeText(getApplicationContext(), fname, Toast.LENGTH_LONG).show();

JSON Arrays, Equivalent to put(name, value) when both parameters are non-null; does nothing otherwise. Parameters. name, String. value, Object  The following are Jave code examples for showing how to use entrySet() of the org.json.simple.JSONObject class. You can vote up the examples you like. Your votes will be used in our system to get more good examples.

JSONObject (Oracle Commerce Assembler 11.0.0 API), Character Sets. HTML Character In JSON, array values must be of type string, number, object, array, boolean or null. In JavaScript, array Example. for (i = 0; i < myObj.cars.length; i++) { Values in an array can also be another array, or even another JSON object: x += "<h1>" + myObj.cars[i].name + "</h1>"; for (j in​  Class that handles converting Json objects to and from UStructs

JSONObject::getJSONArray() \ Language (API) \ Processing 3+, A JSONObject is an unordered collection of name/value pairs. A JSONObject constructor can be used to convert an external form JSON text into an Put a key​/value pair in the JSONObject, where the value will be a JSONArray which is  Hi, is there any example on how to add json objects to a json array? From the API this seems possible, but I'm not getting how to do it correctly. I create the root object, then create an array on it like in the examples, but then how ca

Documentation: 9.6: JSON Functions and Operators, Class. JSONObject. Name void setup() { json = loadJSONObject("data.json"); JSONArray values = json.getJSONArray("animals"); for (int i = 0; i < values.size(); i++) { JSONObject getString("species"); String name = animal. The tutorial uses what I'm calling a named array, but all of the JSON i'm going to be using in my android project will use simple table rows with no named array. Examples of the JSON i'm using and the earthquake json from the tutorial are below.

Comments
  • your JSON is not JSONArray. It is a JSONObject with a JSONArray in it. You are trying to create JSONArray from it. You need one more step - to get data JSONArray from the JSONObject
  • I'm using Android Eclipse
  • WHY are you still using Eclipse? Who tells you to use Eclipse??????
  • Android Studio is too complicated for me.
  • If I want to get lname is this right lname=arr.getJSONObject(1).getString("lname");
  • will be lname = arr.getJSONObject(0).getString("lname"); remember that is a one item in the array.