## Creating a list of random numbers without duplicates in python

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so what I am trying to do is create a list of 5 numbers for the game mastermind, and I would like to eliminate all duplicates! The issue is that the code sometimes creates a list with 3 numbers, or 4, or sometimes 5, it seems to be random.

I should also mention we are not allowed to be usin grandom.sample, or random.shuffle

import random def generatePassword() : lis = [] for i in range(5) : #This checks to see if there are duplicate numbers r = random.randint(1,9) if r not in lis : lis.append(r) i+=1 return lis def main() : print(generatePassword()) main()

Try using a while loop with a condition that checks for the length of lis

while len(lis) < 5:

instead of your for loop

**Creating a list of random numbers without duplicates in python ,** Try using a while loop with a condition that checks for the length of lis while len(lis) < 5: instead of your for loop. Python can generate such random numbers by using the random module. In the below examples we will first see how to generate a single random number and then extend it to generate a list of random numbers. Generating a Single Random Number. The random() method in random module generates a float number between 0 and 1. Example

The function `random.sample`

does what you want:

import random def generatePassword(): numbers = range(0, 9) return random.sample(numbers, 5) def main() : print(generatePassword()) main()

**How to generate non-repeating random numbers in Python?,** It generates a random integer in the given interval and adds it in a list if it is not previously added. >>> import random >>> list=[] >>> for i in If the list of N numbers from 1 to N is randomly generated, then yes, there is a possibility that some numbers may be repeated. If you want a list of numbers from 1 to N in a random order, fill an array with integers from 1 to N, and then use a Fisher-Yates shuffle or Python's random.shuffle (). share.

Use `numpy.random.permutation`

if you are looking for method that works and is faster:

import numpy as np your_list = list(np.random.permutation(np.arange(0,10))[:5]) >>> your_list [6, 9, 0, 1, 4]

Alternatively, you can use `np.random.choice`

with `replace=False`

:

your_list = list(np.random.choice(np.arange(0,10), 5, replace=False)

**How to generate a random number in Python without it repeating ,** In the strictest sense, you don't. If you constrain the numbers to non-repeating values, they are no longer truly random. However, the problem as asked in your Unfortunately, there is no function built into Excel that will create a list of unique random whole numbers (see update below). We can use the RANDBETWEEN function to create random numbers between a certain range, say 1 and 100, but there is nothing in the function to prevent duplicate numbers from being created in the range.

You don't want to add random, unique integers 5 times; you want to add random, unique integers until your list contains 5 elements. This'll do it:

import random def generatePassword() : lis = [] while len(lis) < 5: #This checks to see if there are duplicate numbers r = random.randint(1,9) if r not in lis : lis.append(r) return lis

**PYTHON Fill list with random numbers (no repeat),** As @AlexandreNeto mentioned, you could create a custom python function in the Field Calculator which creates a range list of values based on Generate a list of random numbers 10-30 with no duplicates As we can see in Figure 3, column B has numbers 10-30 with duplicates, because only the RANDBETWEEN function is used. In column C, we have same numbers 10-30, but without duplicates using the RANK.EQ and COUNTIF functions.

So your problem:
It won't add the same number twice. But since you use a `for i in range(5):`

it will only repeat 5 times, regardless of if it added a unique number or not.

You need to measure the length of the list, so it will always add 5 random, unique numbers to the list.

You have the code mostly right, but all you need to do is replace:
`for i in range(5):`

with: `while len(lis) < 5:`

Make sure to delete the `i += 1`

though. It will cause an error if you don't.

Here's the code:

import random def generatePassword() : lis = [] while len(lis) < 5: #This checks to see if there are duplicate numbers r = random.randint(1,9) if r not in lis : lis.append(r) return lis def main() : print(generatePassword()) main()

**Expression for random numbers without duplicates,** Python random randrange() and randint() to generate random integer number within a Create a list of random numbers without duplicates. mylist = list ( dict.fromkeys (mylist) ) print(mylist) Now we have a List without any duplicates, and it has the same order as the original List. Print the List to demonstrate the result.

**Python random randrange() & randint() to get Random Integer,** sample() to create a list of random numbers without duplicates. We need to use the combination of range() function and random.sample() . Let's Python Remove Duplicates From List : 4 Ways Of Removing Duplicates From List. Python provides various ways to remove duplicates from list. You can use set() function or write the user-defined function that can remove the duplicate items and gives the unique items list.

**Python random.sample() to choose multiple items from any sequence,** Python | Remove random element from list · Generating random number list in Python · Python - Random Numbers Summation · Python | Generate successive Aside from getting your own lottery balls, throwing them around and picking up the "lucky" numbers, Excel can also let you create your own quick pick random numbers. P.S. Feel free to provide a

**Python,** For sequences, uniform selection of a random element, a function to generate a random of a list in-place, and a function for random sampling without replacement. If the population contains repeats, then each occurrence is a possible The original list is : [1, 3, 5, 6, 3, 5, 6, 1] The list after removing duplicates : [1, 3, 5, 6] Method 2 : Using list comprehension This method has working similar to the above method, but this is just a one-liner shorthand of longer method done with the help of list comprehension.

##### Comments

- If you want to use that approach, you need to keep going until the list has 5 elements, not just try to add a value 5 times. (Also,
`i+=1`

doesn’t do anything –`range(5)`

is already taking care of providing the values 0, 1, 2, 3, 4 in sequence. Also also,`random.sample`

.) - It's because you only append when the randomly selected integer isn't in the list. In addition to appending the unique integers, you should also have some condition for when the randomly generated integer is already in the list.
- Ahhh yeah of course, thanks! Changed to a while loop instead
- Bless your soul. This worked. Totally didn't think of len(list)
- This works but could be slow; it has to keep running this code till it gets 5, which (theoretically) could take forever.
- Yeah, "theoretically". But it won't. Python modules are extremely fast, and can run a loop hundreds of thousands of times a second. If he wanted to add 999,999 unique numbers to a list out of 1,000,000, it could take forever, but since he is just needs 5 out of 10, it won't take long at all.
- @SanguineL: Good point. It makes no sense worrying for speed when it takes only couple of microseconds to finish the task like this
- I should have mentioned we're not allowed to use random.sample, thanks though!
- @SpencerVreugdenhil-Beauclerc While homework/classwork questions are allowed, please make it clear that that is what they are, as well as restrictions.
- @ArtemisFowl I am sorry! I should have mentioned that in my post, for sure will next time!
- numpy is a bit overkill for
`random.sample(range(1, 10), 5)`

.