Creating dynamic nested dictionary of counts

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I have a text file abc.txt:


I need to parse these statements and output should be in nested dictionary as below:


where 1 is 'pass' count.

I'm able to do as much as this:

import re

for line in open('abc.txt'):
    for key in p.findall(line):

Here's an updated version of my answer in which leaves of the tree data-structure are now different from those in rest of it. Instead of the tree being strictly a dict-of-nested-dicts, the "leaves" on each branch are now instances of a different subclass of dict named collections.Counter which are useful for counting the number of times each of their keys occur. I did this because of your response to my question about what should happen if the last part of each line was something other than ":pass" (which was "we have to put new count for that key").

Nested dictionaries are often called Tree data-structures and can be defined recursively — the root is a dictionary as are the branches. The following uses a dict subclass instead of a plain dict because it makes constructing them easier since you don't need to special case the creation of the first branch of next level down (except I still do when adding the "leaves" because they are a different subclass, collections.Counter).

from collections import Counter
from functools import reduce
import re

# (Optional) trick to make Counter subclass print like a regular dict.
class Counter(Counter):
    def __repr__(self):
        return dict(self).__repr__()

# Borrowed from answer @
class Tree(dict):
    def __missing__(self, key):
        value = self[key] = type(self)()
        return value

# Utility functions based on answer @
def nested_dict_get(nested_dict, keys):
    return reduce(lambda d, k: d[k], keys, nested_dict)

def nested_dict_set(nested_dict, keys, value):
    nested_dict_get(nested_dict, keys[:-1])[keys[-1]] = value

def nested_dict_update_count(nested_dict, keys):
    counter = nested_dict_get(nested_dict, keys[:-1])
    if counter:  # Update existing Counter.
    else:  # Create a new  Counter.
        nested_dict_set(nested_dict, keys[:-1], Counter([keys[-1]]))

d = Tree()
pat = re.compile(r'[a-zA-z]+')
with open('abc.txt') as file:
    for line in file:
        nested_dict_update_count(d, [w for w in pat.findall(line.rstrip())])

print(d)  # Prints like a regular dict.

To test the leaf-counting capabilities of the revised code, I used the following test file which includes the same line twice, once ending again with :pass and another ending in :fail.

Expanded abc.txt test file:



{'abc': {'pqr': {'lmn': {'bcd': {'pass': 1}, 'xyz': {'fail': 1, 'pass': 2}}}}}

Python Nested Dictionary, How do you make a nested dictionary dynamically in Python? I am trying to create a nested dictionary dynamically using python. for example I need to create a function that will take the nodes and construct a nested dictionary with these nodes. For example: inputs: 'customers.applicant.individual.first_name' output:

Check out the setdefault method on dictionaries.

d = {}
d.setdefault('pqr', {}).setdefault('lmn', {}).setdefault('xyz', {})['pass'] = 1
d.setdefault('pqr', {}).setdefault('lmn', {}).setdefault('bcd', {})['pass'] = 1


{'pqr': {'lmn': {'bcd': {'pass': 1}, 'xyz': {'pass': 1}}}}

Python, . If it is, make a recursive call to the function with value as its input. This is known as nested dictionary. Nested dictionaries are one of many ways to represent structured information (similar to ‘records’ or ‘structs’ in other languages). Create a Nested Dictionary. A nested dictionary is created the same way a normal dictionary is created. The only difference is that each value is another dictionary.

If i understand your question:

sources = ["abc/pqr/lmn/xyz:pass", "abc/pqr/lmn/bcd:pass", "abc/pqr/lmn/xyz:pass"]

def prepare_source(source):
    path, value = source.split(':')
    elements = path.split('/')
    return elements, value

def add_key(elements, value):
    result = dict()
    if len(elements) > 1:
        result[elements[0]] = add_key(elements[1:], value)

        result[elements[0]] = {value: 1}

    return result

# base merge function get from here:
def merge(a, b, path=None):
    "merges b into a"
    if path is None: path = []
    for key in b:
        if key in a:
            if isinstance(a[key], dict) and isinstance(b[key], dict):
                merge(a[key], b[key], path + [str(key)])
            elif isinstance(a[key], int) and isinstance(b[key], int):
                a[key] += b[key]
                raise Exception('Conflict at %s' % '.'.join(path + [str(key)]))
            a[key] = b[key]
    return a

result = dict()

for source in sources:
    result = merge(result, add_key(*prepare_source(source)))

print result

Output will be:

{'abc': {'pqr': {'lmn': {'bcd': {'pass': 1}, 'xyz': {'pass': 2}}}}}

How to loop through all nested dictionary values using a for-loop in , dicts, their problems could be solved slightly more easily by using a dict with tuples for keys. I want to create a Python dictionary which holds values in a multidimensional accept and it should be able to expand, this is the structure that the values should be stored :- userdata = {'data':[{'

Is nested dictionary in design ok?, To create a nested dictionary, simply pass dictionary key:value pair as keyword arguments to dict() Constructor. You can use dict() function along with the zip() function, to combine separate lists of keys and values obtained dynamically at runtime. Python Nested Dictionary More specifically, you’ll learn to create nested dictionary, access elements, modify them and so on with the help of examples. In Python, a dictionary is an unordered collection of items.

python dynamically create nested dictionary, Creating a Nested Dictionary. In Python, a Nested dictionary can be created by placing the comma-separated dictionaries enclosed withing braces. It is important to remember when using defaultdict and similar nested dict modules such as nested_dict, that looking up a nonexistent key may inadvertently create a new key entry in the dict and cause a lot of havoc. Here is a Python3 example with nested_dict module:

Python Training Nested Dictionary in Python, More specifically, you'll learn to create nested dictionary, access elements, keep this data, where the key will the string word and value is the frequency count. Stack Overflow for Teams is a private, secure spot for you and your coworkers to find and share information. Learn more Creating a complex nested dictionary from multiple lists in Python

  • sorry. i am new to python, but what will be the solution for this output.
  • yes. sorry for that.
  • What if the last part of each line is not ":pass"?
  • we have to put new count for that key
  • Not sure I understand what you mean by that. Anyway, what do you think of the answers you've gotten? Maybe your reactions to them will clarify.
  • I will check. Thanks.
  • is it possible to add keys dynamically instead of hard coding.
  • @sachin27: The hardcoded keys could be replaced with variables or values from your p.findall().