Newtonsoft JSON Deserialize

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My JSON is as follows:

{"t":"1339886","a":true,"data":[],"Type":[['Ants','Biz','Tro']]}

I found the Newtonsoft JSON.NET deserialize library for C#. I tried to use it as follow:

object JsonDe = JsonConvert.DeserializeObject(Json); 

How can I access to the JsonDe object to get all the "Type" Data? I tried it with a loop but it is not working because the object does not have an enumerator.

You can implement a class that holds the fields you have in your JSON

class MyData
{
    public string t;
    public bool a;
    public object[] data;
    public string[][] type;
}

and then use the generic version of DeserializeObject:

MyData tmp = JsonConvert.DeserializeObject<MyData>(json);
foreach (string typeStr in tmp.type[0])
{
    // Do something with typeStr
}

Documentation: Serializing and Deserializing JSON

Serializing and Deserializing JSON, string json = @"['Starcraft','Halo','Legend of Zelda']"; List<string> videogames = JsonConvert.DeserializeObject<List<string>>(json); Console.WriteLine(string. Serializing and Deserializing JSON The quickest method of converting between JSON text and a.NET object is using the JsonSerializer. The JsonSerializer converts.NET objects into their JSON equivalent and back again by mapping the.NET object property names to the JSON property names and copies the values for you.

A much easier solution: Using a dynamic type

As of Json.NET 4.0 Release 1, there is native dynamic support. You don't need to declare a class, just use dynamic :

dynamic jsonDe = JsonConvert.DeserializeObject(json);

All the fields will be available:

foreach (string typeStr in jsonDe.Type[0])
{
    // Do something with typeStr
} 

string t = jsonDe.t;
bool a = jsonDe.a;
object[] data = jsonDe.data;
string[][] type = jsonDe.Type;

With dynamic you don't need to create a specific class to hold your data.

Deserialize a Collection, If you just need to get a few items from the JSON object, I would use Json.NET's LINQ to JSON JObject class. For example: JToken token = JObject. Using JsonConvert.DeserializeObject to deserialize Json to a C# POCO class 1 Cannot deserialize the current JSON object (e.g. {“name”:“value”}) into type 'System.Collections.Generic.List

As per the Newtonsoft Documentation you can also deserialize to an anonymous object like this:

var definition = new { Name = "" };

string json1 = @"{'Name':'James'}";
var customer1 = JsonConvert.DeserializeAnonymousType(json1, definition);

Console.WriteLine(customer1.Name);
// James

Deserializing JSON to .NET object using Newtonsoft (or LINQ to , You can implement a class that holds the fields you have in your JSON class MyData { public string t; public bool a; public object[] data; public  This sample creates a class that inherits from T:Newtonsoft.Json.Converters.CustomCreationConverter`1 that instantiates Employee instances for the Person type.

Newtonsoft JSON Deserialize, Json namespace to serialize and deserialize to and from JavaScript Object Notation (JSON). If you're porting existing code from Newtonsoft.Json , see How to  During deserialization, Newtonsoft.Json accepts property names surrounded by double quotes, single quotes, or without quotes. It accepts string values surrounded by double quotes or single quotes. For example, Newtonsoft.Json accepts the following JSON:

How to serialize and deserialize JSON using C#, In this article you will learn how to serialize and deserialize JSON object where we need to put the following command to install Newtonsoft. Serialize and deserialize any .NET object with Json.NET's powerful JSON serializer. LINQ to JSON Create, parse, query and modify JSON using Json.NET's JObject, JArray and JValue objects.

JSON Serialization And Deserialization Using JSON.NET Library In C#, This article is about Newtonsoft JSON deserializing with a C# example. The Newtonsoft.JSON namespace provides classes that are used to  This sample uses T:Newtonsoft.Json.JsonPropertyAttribute to change the names of properties when they are serialized to JSON.

Comments
  • possible duplicate of Using JsonConvert.DeserializeObject to deserialize Json to a C# POCO class
  • You should have a look at the answer to this question: stackoverflow.com/questions/11126242/…
  • I just added an example that should be useful. It is a mystery to me why the "type" is a list of lists (array array) - but this should align with the json string you gave.
  • Thanks a lot for your answer. It helped me to resolve my issue :)
  • I was using a cast which was failing MyData tmp = (MyData)JsonConvert.DeserializeObject(json);. The generic version of deserialize works much better, thanks. :-)
  • Ok, I write it here: dotnet add package Newtonsoft.Json and using Newtonsoft.Json;.
  • nice answer, thanks for introducing me to dynamic : )
  • It's definitely easy. But it has the disadvantage of not being able to easily check if a property exists (you should use exception handling).
  • @Jowen To check if a property exists without exception handling have a look at those answers
  • thank you very much 1!! simplest solution ive been looking for so long
  • Now that's smart! ;-) But it gets clumsy when the definition isn't as straight-forward as your example.
  • I don't know anything about definition, how should I use DeserializeAnonymousType in this case?
  • This is a worthless example, as most JSON isn't anywhere near that simplistic. I'd like to see a definition that more closely resembles a JSON string with nested properties...