Find last two characters in a list of words

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I wonder how I could make a function that returns the last to characters of each of the words in a list of words. Here's what I am thinking:

mylist = ["Hello","there","people"]

def two(s):
    for element in s:
        letters = element[2:-1]
    return(letters)


print(two(mylist))

What I want printed out is "lorele"

You can do it with a list comprehension or a generator expression, and using join:

mylist = ["Hello","there","people"]

def two(s):
    return ''.join(i[-2:] for i in s)

>>> two(mylist)
'lorele'

Alternatively, to fix your code, which is almost working:

def two(s):
    # Initialize letters as an empty string:
    letters = ''
    # Append last two letters for each element:
    for element in s:
        # Proper indexing is [-2:], which takes from the second to last character to the end of each element
        letters += element[-2:]
    return(letters)

Note: Don't use list as a variable name, as it masks python's built-in type. I changed it to mylist in the example above, and edited your question to reflect that too.

I wonder how I could make a function that returns the last to characters of each of the words in a list of words. Here's what I am thinking: mylist = ["Hello","there"  In Spanish, conjugation depends on the verb ending, among other factors. Verbs end in either -ar, -er or -ir. So the program must be able to isolate these two letters and then use conditional structures to determine how to proceed. But here is the problem: if verb is 'amar', verb [-2:-1] will return 'a', not 'ar'.

List comprehension is your friend

>>> a=["hello",'world','how','are','you!']
>>> '12345'[-2:]
'45'
>>> b=[mine[-2:] for mine in a]
>>> b
['lo', 'ld', 'ow', 're', 'u!']
>>> "".join(b)
'loldowreu!'

Approach: Append a space i.e. ” “ at the end of the given string so that the last word in the string is also followed by a space just like all the other words in the  A vocabulary list featuring The Vocabulary.com Top 1000. The top 1,000 vocabulary words have been carefully chosen to represent difficult but common words that appear in everyday academic and business writing.

Firstly, you cannot use the reserved words as variable names.

With your code:

l = ["Hello","there","people"]

def two(s):
    letters = ''
    for element in s:
        letters += element[-2:]
    return letters

print(two(l))

With list comprehension:

print(''.join([s[-2:] for s in ["Hello","there","people"]]))

Use Negative indexing to get the last character of a string in python. Apart from 2. 3. 4. # Get last character of string i.e. char at index position -1. last_char Python: How to create an empty list and append items to it? Fundamental » All languages » English » Terms by lexical property » Terms by orthographic property » Character counts » Two-letter words. English individual words composed of exactly two letters. They have meaning(s) beyond their component letters that are neither names nor abbreviations.

Simply replace '4' with desired number. For example, to get last two characters of a string, using method substring(input.length() - 2) . How to extract first/last n characters from string in Excel? For instance, there is a list with long strings in each cell, and you want to extract the first n characters from each string only, like the first 3 characters of each string, and now you can use the following methods to solve it in Excel.

To get the last letter of a string, you might be tempted to try something like this: Abecedarian refers to a series or list in which the elements appear in Other comparison operations are useful for putting words in lexigraphical order: if word​  > text<-"some text in a string" # we want to have only the last word "string" with 6 letter > n<-5 #as the last character will be counted with nchar(), here we discount 1 > substr(x=text,start=nchar(text)-n,stop=nchar(text)) This will bring the last characters as desired.

To get the last letter of a string, you might be tempted to try something like this: The word in is a boolean operator that takes two strings and returns True if the first Python has a function called dir that lists the methods available for an object. There I was faffing around with len(str(p)) - str(p[len(str(reversed(str(p))).split(' ', 1))[0])], len(str(p)), 2) to get the last n letters of p based on the first space. Useless and doesn't even work.

Comments
  • Thank you very much! I usually use my native language name for "list" and forgot about it when I translated it into english, but thanks for the heads up anyway :)