Using return within for iterator

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I am writing a code that takes in a tuple of integer as intervals and outputs a range of alphabets. I could use some help on return statement.

>>> arrangement((5, 3, 11, 7))
'A-E F-H I-S T-Z'

Below is what I have written so far. The return statement seems to return only the last iteration of the loop:

def arrangement(numerical_representation):
    interval = ''
    step = 65
    for integer in numerical_representation:
        interval = chr(step) + '-' + chr(step + integer - 1)
        step += integer
    return interval

>>> arrangement((5, 3, 11, 7))
'T-Z'

With print statements I am able to go through all the iteration, but I can't seem to make them print in a single line with quotation marks on both ends.

def arrangement(numerical_representation):
    interval = ''
    step = 65
    for integer in numerical_representation:
        interval = chr(step) + '-' + chr(step + integer - 1)
        step += integer
        print(interval)

>>> arrangement((5, 3, 11, 7))
A-E
F-H
I-S
T-Z

How should I proceed?

Try it like this:

def arrangement(numerical_representation):
    start = 65
    result = []
    for n in numerical_representation:
        result.append('{}-{}'.format(chr(start), chr(start+n-1)))
        start += n
    return ' '.join(result)

print(arrangement((5, 3, 11, 7)))
#A-E F-H I-S T-Z

Python return statement, Can you have a return statement in a for loop? The built-in function iter () can be called with two arguments where the first argument must be a callable object (function) and second is the sentinel. The iterator calls this function until the returned value is equal to the sentinel. >>> int () 0 >>> inf = iter (int,1) >>> next (inf) 0 >>> next (inf) 0.

You need to use += instead of =:

def arrangement(numerical_representation):
    interval = ''
    step = 65
    for integer in numerical_representation:
        interval += chr(step) + '-' + chr(step + integer - 1)
        step += integer
    return interval

>>> arrangement((5, 3, 7, 11))
'A-EF-HI-OP-Z'

An alternative, what about using yield?

def arrangement(numerical_representation):
    interval = ''
    step = 65
    for integer in numerical_representation:
        interval = chr(step) + '-' + chr(step + integer - 1)
        step += integer
        yield interval

>>> ''.join([x for x in arrangement((5, 3, 7, 11))])
'A-EF-HI-OP-Z'

Using return within for iterator, How do you return a value from a while loop in Java? Instead, they return a special type of iterator, called a Generator. When a value is consumed by calling the generator's next method, the Generator function executes until it encounters the yield keyword. The function can be called as many times as desired, and returns a new Generator each time.

You could have a list and append each interval to it. And at the end return the list

def arrangement(numerical_representation):
    interval = ''
    step = 65
    l=[]
    for integer in numerical_representation:
        interval = chr(step) + '-' + chr(step + integer - 1)
        step += integer
        l.append(interval)
    return " ".join(l)


arrangement((5, 3, 11, 7))
A-E F-H I-S T-Z

How return works in for loop? - Python, Try it like this: def arrangement(numerical_representation): start = 65 result = [] for n in numerical_representation:  The simplest solution would be to make the wrapper method an iterator as well, like this: public static IEnumerable<Animal> GetAllAnimals() { using (AnimalDataContext dataContext = new AnimalDataContext()) { foreach (var animalName in dataContext.GetAllAnimals()) { yield return GetAnimal(animalName); } } }

instead of using chr, why not use string.ascii_uppercase and string indexing? You can use itertools.accumulate to generate the cumulative sum of the indices

from itertools import accumulate
from string import ascii_uppercase


def generate_indices(groups):
    begin = 0
    for end in accumulate(groups):
        yield begin, end-1
        begin = end


groups = (5, 3, 11, 7)
result = " ".join(
    (f"{ascii_uppercase[begin]}-{ascii_uppercase[end]}")
    for begin, end in generate_indices(groups)
)
'A-E F-H I-S T-Z'

Python "for" Loops (Definite Iteration) – Real Python, def digit_sum(n): n = str(n) x=0 for y in n: x += int(y) return x print Hence, on step 3 of first iteration, the return statement causes exit from the  The purpose of the iter method is to return an iterator for the specified object. For iterators, that usually just means returning itself, which seems odd at first. For iterators, that usually just means returning itself, which seems odd at first.

7. Iteration, In Python, indefinite iteration is performed with a while loop. Each of the objects in the following example is an iterable and returns some type of iterator when  An iterator can be used to step through collections such as lists and arrays. An iterator method or get accessor performs a custom iteration over a collection. An iterator method uses the yield return statement to return each element one at a time. When a yield return statement is reached, the current location in code is remembered. Execution is restarted from that location the next time the iterator function is called.

Loops and iteration, Within the body, each time, increment v. When v passes n, return your accumulated sum. More formally, here is precise flow of execution for a while statement  The loop isn't terminated until Iterator::valid() returns false or the body of the loop executes a break statement. The only two methods that are always executed are Iterator::rewind() and Iterator::valid() (unless rewind throws an exception). The Iterator::next() method need not return anything. It is defined as returning void.

Iterators and generators, Although it may be tempting to use this as a way to iterate over Array elements, the forin statement will return the name of your  java.util package has public interface Iterator and contains three methods: boolean hasNext(): It returns true if Iterator has more element to iterate. Object next(): It returns the next element in the collection until the hasNext()method return true. This method throws ‘NoSuchElementException’ if there is no next element.

Comments
  • print(interval, end='') would do the trick. Or in your case, it looks like you want print(interval, end=' ')
  • You are assigning/overwriting the value of interval in each iteration.