## checking an array if sum of any elements in array equal to given value

find all subsets of an int array whose sums equal a given target
find a pair of elements from an array whose sum equals a given number
find sum of all pairs in an array
count number of distinct pairs whose sum exists in the given array
find pairs in array java
find a pair of elements from an array whose product equals a given number
determine if any two integers in array sum to given integer
find all the elements in the stack whose sum is equal to k where k is given from user
```[1,2,3,6], 3 = True <== 1+2=3
[1,2,3,6], 9 = True <== 3+6=9
[1,2,3,6], 5 = True <== 2+3=5
[1,2,3,6], 10 = False <== 1+2, 2+3, 3+6, 6+1 not equal to 10
[6,2,3,1], 10 = False <== 6+2, 2+3, 3+1, 1+6 not equal to 10
[6,3,3,1], 6 = True <== 3+3=6
```

JavaScript is preferred if given sum is equal to sum of any two elements in the array, function need to return true; otherwise function need to return false.

Your going to have to iterate through the array of values. Not familiar with javascript so here is the code in a java function:

```public boolean checkSum(){
int sumValue = 10; //value you want to check, could be passed in as a parameter
int arr = {1,2,4,6};
for (int n = 0; n < arr.length; n++){
for (int x = 0; x < arr.length; x++){
if ( (arr[n] + arr[x] == sumValue) && (n != x) ){ //need to ensure same slot is being added
return true;
}
}
}
return false;
}
```

Hope this helps!

Given an array A[] and a number x, check for pair in A[] with sum as x , Now, traverse through the whole array and make all possible values as 1. C++. Objective: Given an array and an integer, find the Subarray whose sum is equal to the given integer. Examples:. int[] arrA = { 25, 12, 14, 22, 19, 15, 10, 23 }; Integer = 55 Output: 55 is found between indexes 2 and 4 And Elements are : 14 22 19

You can use the function `some` to check that at least one operation is `true`.

This approach follows your use cases

```let check = (sum, arr) => arr.concat(arr).some((n, i, a) => (n + a[i+1]) === sum);

console.log(check(3, [1,2,3,6]));
console.log(check(9, [1,2,3,6]));
console.log(check(5, [1,2,3,6]));
console.log(check(10, [1,2,3,6]));
console.log(check(10, [6,2,3,1]));
console.log(check(6, [6,3,3,1]));
console.log(check(7, [3,1,2,4]));
console.log(check(7, []));```
`.as-console-wrapper { max-height: 100% !important; top: 0; }`

Check if is possible to get given sum from a given set of elements , Naive solution would be to consider every pair in given array and return if desired We compare sum of elements present at index low and high with desired sum and We also checks if difference (arr[i], sum-arr[i]) already exists in the map or not. is that the Map solution does not take into account any duplicate values. Check if the array has an element which is equal to sum of all the remaining elements. Check if the array has an element which is equal to XOR of remaining elements. Maximum difference between group of k-elements and rest of the array. Check if the array has an element which is equal to product of remaining elements.

Here's a very simple way that will check if two numbers in an array equal a value. Note, this only allows distinct sums (a number summed with itself doesn't count).

```function test(n, arr){
return arr.some((item, i) => arr.slice(i+1).includes(n-item))
}

let arr = [1, 2, 3, 6]

console.log(test(5, arr))   // true 2+3
console.log(test(4, arr))   // true 1+3
console.log(test(12, arr))  // false because 6 + 6 doesn't count
console.log(test(10, arr))  // false no sums```

Find pair with given sum in an array, This is a special case of the knapsack problem, known as the subset sum problem . The "pair of elements in an array" problem is a very simple variation on it. How do you check if reversing a subarray makes an array sorted? Given an integer array such that every element occurs 3 times except one element, which  This is a special case of the knapsack problem, known as the subset sum problem . The "pair of elements in an array" problem is a very simple variation on it.

What can be an algorithm to determine if sum of some elements of , Given a set of non-negative integers, and a value sum, determine if there is a subset of the given set with sum equal to given sum. do you check if it is possible to obtain a sum of S, by choosing some (or zero) elements of the array and adding them? If any of the above the above subproblems return true, then return true. Find sum of elements in a given array | GeeksforGeeks. If playback doesn't begin shortly, try restarting your device. Videos you watch may be added to the TV's watch history and influence TV recommendations. To avoid this, cancel and sign in to YouTube on your computer.

Given an array (N) of integers, how do you check if it is possible to , Likewise, the number to be found is stored in toFind . Now, we use a foreach loop to iterate through all elements of num and check individually if toFind is equal to  Given an array of integers, find any one combination of four elements in the array whose sum is equal to a given value X. For example, if the given array is {10, 2, 3, 4, 5, 9, 7, 8} and X = 23, then your function should print “3 5 7 8” (3 + 5 + 7 + 8 = 23).

Java Program to Check if An Array Contains a Given Value, Write python sum is equal to the sum of the entire array. 0: return False sum = sum / 2 # For each element arr[i], see if # there is another element with # value sum - arr[i] for i in range(n): val 11, 5, 1, 4, 7] n = len(a) if checkPair(a, n) == False: print("No pair found") can you give an example using a . 4. If the sum is less than, add the element pointed by j. 5. If the sum is equal to X then return the subarray pointed by i and j as start and end. C++ Program

• `check(4, [1,2,3,6])` returns false.
• I read: `if given sum is equal to sum of **any** two elements in the array, function need to return true` The given sum: 4 is equal to the sum of two element [1, 3] in the array.