## random return not matching outcome requirements

simple randomization

block randomization example

python returns none instead of value

computer generated randomization

python check if function returns true

block randomization generator

matched cohort study vs case-control

python3.7

I am trying to use a simple "dice" code to (originally) allow for a 50/50 chance between two outcomes. However I have noticed that this code does not consistently match the outcome I expect with the number rolled. For example, I can roll a 1 and get "This should be 3 or less" and then roll a 1 again directly after and get "This should be 4 or more". Can anyone see what is causing this?

import random def dice(): roll = random.randint(1,6) return roll def count(): print(dice()) if dice() <= 3: print("This should be 3 or less") else: print("This should be 4 or more") count()

edit: I realized that I may be calling dice() separately and tried this, which worked.

import random def dice(): roll = random.randint(1,6) return roll def count(): x = dice() print(x) if x <= 3: print("This should be 3 or less") else: print("This should be 4 or more") count()

This line of code calls the dice function:

print(dice())

And then this code calls the dice function again:

if dice() <= 3: print("This should be 3 or less") else: print("This should be 4 or more")

The two calls are not related. The first call might return 1, while the next one might return 6.

If you want the same value to be used in both places, call the dice function only once and save its result in a separate variable:

result = dice() print(result) if result <= 3: print("This should be 3 or less") else: print("This should be 4 or more")

**python - random return not matching outcome requirements,** This line of code calls the dice function: print(dice()). And then this code calls the dice function again: if dice() <= 3: print("This should be 3 or i a scalar outcome variable. In observational data, the process by which values of T are assigned is not necessarily random, controlled by the researcher, or known. 2.1Causal Quantities of Interest Denote Y i(1) and Y i(0) as the “potential outcomes,” the values Y iwould take on if treat-ment or control were applied, respectively. Only one

You are generating two different random numbers, because you're calling dice() twice. Once for printing then another time for the condition.

Store the return value of dice, as in rolled_number = dice()

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You're calling the function `dice`

twice (this is what `dice()`

, with the parentheses afterwards, does). The first time when you print the result, the second time when you print the text description of the outcome. To make sure they're referring to the same thing, just call the function once but assign its value to a variable - eg:

def count(): result = dice() print(result) if result <= 3: print("This should be 3 or less") else: print("This should be 4 or more")

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##### Comments

- Yes, you roll twice: once for printing and once for the if statement - and it's 50/50 that these two fit. Do it in
`count`

the same way like in`dice`

: roll once, save the result in a variable and go on with that value.