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I am trying to use a simple "dice" code to (originally) allow for a 50/50 chance between two outcomes. However I have noticed that this code does not consistently match the outcome I expect with the number rolled. For example, I can roll a 1 and get "This should be 3 or less" and then roll a 1 again directly after and get "This should be 4 or more". Can anyone see what is causing this?
import random def dice(): roll = random.randint(1,6) return roll def count(): print(dice()) if dice() <= 3: print("This should be 3 or less") else: print("This should be 4 or more") count()
edit: I realized that I may be calling dice() separately and tried this, which worked.
import random def dice(): roll = random.randint(1,6) return roll def count(): x = dice() print(x) if x <= 3: print("This should be 3 or less") else: print("This should be 4 or more") count()
This line of code calls the dice function:
And then this code calls the dice function again:
if dice() <= 3: print("This should be 3 or less") else: print("This should be 4 or more")
The two calls are not related. The first call might return 1, while the next one might return 6.
If you want the same value to be used in both places, call the dice function only once and save its result in a separate variable:
result = dice() print(result) if result <= 3: print("This should be 3 or less") else: print("This should be 4 or more")
python - random return not matching outcome requirements, This line of code calls the dice function: print(dice()). And then this code calls the dice function again: if dice() <= 3: print("This should be 3 or i a scalar outcome variable. In observational data, the process by which values of T are assigned is not necessarily random, controlled by the researcher, or known. 2.1Causal Quantities of Interest Denote Y i(1) and Y i(0) as the “potential outcomes,” the values Y iwould take on if treat-ment or control were applied, respectively. Only one
You are generating two different random numbers, because you're calling dice() twice. Once for printing then another time for the condition.
Store the return value of dice, as in rolled_number = dice()
Value Averaging: The Safe and Easy Strategy for Higher Investment , The Safe and Easy Strategy for Higher Investment Returns Michael E. Edleson Suppose the market really followed a random walk, almost like a series of coin flips. First, it is important to note that the "market coin" is not a "fair" coin, because the Outcomes 1 and 4 are classified as a period-to-period MATCH (as the good Matching Procedures 3 Matching 4 not selected selection process 2 Pool of Potential Matches: Clients not considered or not selected for the New Program Compare Outcome Measures Outcome Measures Control Group, Traditional Program Experimental Group, New Program This kind of matching involves the following process. 1. Determine the common
You're calling the function
dice twice (this is what
dice(), with the parentheses afterwards, does). The first time when you print the result, the second time when you print the text description of the outcome. To make sure they're referring to the same thing, just call the function once but assign its value to a variable - eg:
def count(): result = dice() print(result) if result <= 3: print("This should be 3 or less") else: print("This should be 4 or more")
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Modern Probability Theory and Its Applications, P[Y = 1] = if and P[Y = -1] = The mean E[Y] of the random variable Y is then The amount one can expect to win at roulette by betting on an odd outcome long been encountered by physicists in connection with problems of return to equilibrium. Solution: It is clear that the game of matching pennies with fair coins is not In this article, we will see how to match two columns in Excel and return a third. In Excel, there are many find and match functions like FIND, MATCH, INDEX, VLOOKUP, HLOOKUP etc. Here in this article, we are going to use some of these. We will see some Excel formula to compare two columns and return a value.
- Yes, you roll twice: once for printing and once for the if statement - and it's 50/50 that these two fit. Do it in
countthe same way like in
dice: roll once, save the result in a variable and go on with that value.