Removing first x characters from string?

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How might one remove the first x characters from a string? For example, if one had a string lipsum, how would they remove the first 3 characters and get a result of sum?

>>> text = 'lipsum'
>>> text[3:]
'sum'

See the official documentation on strings for more information and this SO answer for a concise summary of the notation.

Removing the first X number of characters from a string in Excel and , Occasionally you need to convert a specific string to remove some x number of characters at the beginning of the string. There is a very nifty function you can use​  Another way (depending on your actual needs): If you want to pop the first n characters and save both the popped characters and the modified string: s = 'lipsum' n = 3 a, s = s[:n], s[n:] print(a) # lip print(s) # sum

Another way (depending on your actual needs): If you want to pop the first n characters and save both the popped characters and the modified string:

s = 'lipsum'
n = 3
a, s = s[:n], s[n:]
print(a)
# lip
print(s)
# sum

How to Remove First Character [5 Ways] from a Cell/String in Excel, Even I have created a small UDF to make it super easy for him to remove n number of characters from the start of a string. And today in this post, I'd like to share  LEN(B1)returns the length of the string in cell B1: 12 letters. It then subtracts 2, in order to leave out the first 2 characters: 12-2=10. Then RIGHT() takes the last 10 letters from the string and returns: marketsize. In effect, this has removed the first 2 characters of the string. There you go!

>>> x = 'lipsum'
>>> x.replace(x[:3], '')
'sum'

How to remove first or last n characters from a cell or string in Excel?, doc remove first x from the text strings, see  I am writing shell script for embedded Linux in a small industrial box. I have a variable containing the text pid: 1234 and I want to strip first X characters from the line, so only 1234 stays. I have more variables I need to "clean", so I need to cut away X first characters and ${string:5} doesn't work for some reason in my system.

Use del.

Example:

>>> text = 'lipsum'
>>> l = list(text)
>>> del l[3:]
>>> ''.join(l)
'sum'

How To Remove First, Last X Characters Or Certain Position , With these inputs, the REPLACE function replaces the first character in B5 with an empty string and returns the result. Removing N characters. To always remove​  removing first characters: x <- 'hello stackoverflow' substring(x, 2, nchar(x)) Idea is select all characters starting from 2 to number of characters in x. This is important when you have unequal number of characters in word or phrase. Selecting the first letter is trivial as previous answers: substring(x,1,1)

Example to show last 3 digits of account number.

x = '1234567890'   
x.replace(x[:7], '')

o/p: '890'

Excel formula: Remove first character, 1: start_num for text must be one as we are removing from first character. N: upto characters needed to be removed from the start. “” (empty string): replaced  Assuming that you want to remove the first character from the text string in Cell B1, then you can write down the following formula: = RIGHT (B1, LEN (B1)-1) This formula will extract the right-most characters from the text in Cell B1 and the length of the characters that you need to extract is returned by the LEN(B1)-1 formula, so it will remove the first character from the text.

How to Remove first characters from text in Excel, How to delete the last x number of characters from string. Remove First Character​. If you want to remove the first character from the beginning of  The String.TrimEnd method removes characters from the end of a string, creating a new string object. An array of characters is passed to this method to specify the characters to be removed. The order of the elements in the character array does not affect the trim operation.

How to remove first and last characters from text string in Excel , The solution can be easily extended to remove first n characters from the string. 1 ACCEPTED SOLUTION. Re: How to strip out characters from a string. Subscribe to RSS Feed. Email to a Friend. Report Inappropriate Content. ‎05-30-2019 07:47 AM. Thanks, @abhi9255 . This is exactly what I was looking for. All forum topics.

Remove first character from a string in JavaScript, Two strings can be concatenated, and we can also repeat a string n times For example, to remove the first character from the string (its index is 0) take the slice​  3. Save the code and go back to the sheet you use. For example, remove first 3 characters from string in Cell A11, copy and paste this formula. =RemoveFirstC (A11,3) press Enter key. #N#This Remove Characters Tool Boosts Your Efficiency By 90%, Leave Much Time To Enjoy Your Life. Say goodbye to modifying and memorizing formulas, give you a

Comments
  • better example if the number of characters removed wasn't equal to the number of characters to remain. e.g. "lipsumm"[3:] == "summ"
  • I guess it's metaphorically "popped" but actually its just 2 different slices, no real popping
  • Note that this is longer in code and will also take more time since you have to search for the substring before you replace it. Also: >>> x = 'liplip' >>> x.replace(x[:3], '') ''. Sure you could fix this by having the third parameter (count) = 1 but it would still take longer.
  • nah it's related to your answer so it belongs here. You can add count=1 to yours so that it still works btw
  • This doesn't work like you'd think text = 'liplip' >>> text.lstrip(text[:3]) '' because for one str.lstrip([chars]) The chars argument is not a prefix; rather, all combinations of its values are stripped:
  • @jamylak Edited mine
  • Neither of the solutions work eg. for 'liplip'. In the second one TypeError: 'str' object does not support item deletion
  • @jamylak Edited again
  • @jamylak does it work, now , if so do you need to downvote?
  • This has the same issue as the answer by tkbx
  • eg. >>> x = '12345678901234567890' >>> x.replace(x[:7], 'xxxxxxx') 'xxxxxxx890xxxxxxx890'
  • Also this doesn't even answer the question, you are replacing characters with xs instead of deleting them