Trying to convert a method from a string into an integer

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I'm writing a program that will count the amount of commas a string the user wrote contains.

I'm doing this by using another method in which the written string gets analyzed and the amount of commas are returned.

The problem I'm having is that I'm using a string, which needs to be converted into an integer while sitting in a method, if that makes sense.

I know this can be done easier by just removing the method and writing the code in the 'main', but I don't want to since I will be expanding the program to also analyze the amount of full stops and the amount of semicolons in the written string.

Here's my code:

static void Main(string[] args)
    {
        Console.WriteLine("Enter a text:");
        string text = Console.ReadLine();
        int count = 0;
        count = NumberOfCommas(text);
        int kommaCount = count;


        int NumberOfCommas(int text1)
        {
            foreach (char letter in text)
            {
                if (letter == ',' )
                {
                    count++;
                }
            }
            return count;
        }
        Console.WriteLine("There's {0} comma(s) in your text.", kommaCount);
        Console.ReadKey();
    }

The error code I'm getting is "cannot convert from 'string' to 'int'. (the code is referencing to the 'text' part of this line: count = NumberOfCommas(text);)

I hope I explained it well, so my question is: how do I fix this?

This is because of your method signature. int NumberOfCommas(int text1) is looking for int text1 and it should be string text1.

Also, I'd like to point out two things. First, you're using a local function. There's nothing wrong with that and for what you're doing here it's fine. I might suggest pulling it out since it really doesn't have any variables that require it to stay scoped to the method.

Another thing is your point about thinking others would prefer you to place it all in main but you said

I will be expanding the program

so you decided against it... This is a good thing and the correct way of thinking / development so if someone tells you to put it in main for simplicity I tell you stick to your guns. You're logic is right.

Java Convert String to int, How do I convert an int to a string in Java? There are two methods of converting a string to an integer. Which one you should use depends on the version of your C++: whether it’s C++11 and above, or an earlier version of the language. C++03 and Earlier For the earlier versions of C++, we’re going to use the stringstream class to perform input-output operations on the strings.

static void Main(string[] args)
{
    Console.WriteLine("Enter a text:");
    string text = Console.ReadLine();
    int count = 0;
    count = NumberOfCommas(text);

    Console.WriteLine("There's {0} comma(s) in your text.", count);
    Console.ReadKey();
}

int NumberOfCommas(String text1)
{
    int count;

        foreach (char letter in text1)
        {
            if (letter == ',' )
            {
                count++;
            }
        }
        return count;
}

There were several errors. Parameter data type to the function should be String, text in foreach loop should be text1. And you do not need to count variables.

Best way to Convert Integer to String in Java with Example, String myString = "1234"; int foo = Integer.parseInt(myString);. If you look at the Java Documentation you'll notice the "catch" is that this function can throw a  The TryParse() methods are available for all the primitive types to convert string to the calling data type. It is the recommended way to convert string to an integer. The TryParse() method converts the string representation of a number to its 16, 32, and 64-bit signed integer equivalent. It returns boolean which indicates whether the conversion succeeded or failed and so it never throws exceptions.

Change the function signature to

 int NumberOfCommas(string text1) { ...

Also move this function out of the main function.

parseInt(), trim()) method is used to change from the string s to the integer i in this line of code: int i = Integer.parseInt(s.trim());. If the change attempt fails – in  Example 1: Convert String to Integer using Integer.parseInt() Syntax of parseInt method as follows: int <IntVariableName> = Integer.parseInt(<StringVariableName>); Pass the string variable as the argument. This will convert the Java String to java Integer and store it into the specified integer variable. Check the below code snippet-

For position or negative number in String , the convert is the same. 1.1 Review the JDK source code of the Integer class, both method signatures tries to use Java 8 Optional and Stream to convert a String into an Integer . Convert it into an string (with to_s) then convert it back to an integer (with to_i). For example: You can convert the Integer 1 to the String “1”. Then you can use methods from the new class, which helps you do something that wasn’t possible before. Remember that in Ruby…

Java convert string to int: In this tutorial we will see two ways to convert a String to int in Java using Integer.parseInt and Integer.valueOf methods. The most direct solution to convert a string to an integer is to use the parseInt method of the Java Integer class. parseInt converts the String to an int , and throws a NumberFormatException if the string can’t be converted to an int type.

For converting String to Integer or int, there are four built-in approaches. The wrapper class Integer provides a few methods specifically for this use - parseInt() ,  In Java, you can use Integer.parseInt () to convert a String to int. Example to convert a String “10” to an primitive int. Alternatively, you can use Integer.valueOf (), it will returns an Integer object. In summary, parseInt (String) returns a primitive int, whereas valueOf (String) returns a new Integer () object. NumberFormatException.

Comments
  • Hello there your method parameter is int but you pass a string as parameter.
  • This helped! Thank you very much.