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I have a list of tuples with some xml information and want to create a dictionary instead so as to make accesses faster. Need to asign an id as the key I'm storing in the first item for each tuple of the list, and as value all the remaining information but not sure if that is even possible on python.

The code I actually have to generate the list:

for node in root.findall('n:graph/n:node', ns):
        id = node.get('id')
        nodes.append((id, *(data.text for data in node if \
        (data.get('key') == keys[2] or data.get('key') == keys[3]))))

Which get me the following output:

nodes = [('id1', 'x', 'y'), ('id2', 'x', 'y') ... ]

What I want is something like:

nodes = {'id1' : ('x', 'y'), 'id2' : ('x', 'y') ... ]

So that I can then use if id in nodes to check if an element exists or not. Thank you.

Start with nodes as a dictionary and not a list.

nodes = {}
for node in root.findall('n:graph/n:node', ns):
        id = node.get('id')
        nodes[id] = tuple([data.text for data in node if \
        (data.get('key') == keys[2] or data.get('key') == keys[3])])

Python : How to add / append key value pairs in dictionary using dict , It accepts in iterable sequence of key value pairs that can be single key value pair or list of tuples or an another dictionary. For each entry in  Python | Add dictionary to tuple Sometimes, while working with data, we can have a problem in which we need to append to a tuple a new record which is of form of Python dictionary. This kind of application can come in web development domain in case of composite attributes.

You can just use a dict comprehension:

{x[0]: x[1:] for x in nodes}

Python, Using the append function we just added the values to the dictionary. Example 1: filter_none. edit close. play_arrow. link brightness_4 code  Append multiple key value pair in dictionary. As update() accepts an iterable sequence of key value pairs, so we can pass a dictionary or list of tuples of new key value pairs to update(). It will all add the given key value pairs in the dictionary, if any key already exists then it will update its value.

nodes = {}
for node in root.findall('n:graph/n:node', ns):
    id = node.get('id')
    nodes[id] = (data.text for data in node if data.get('key') in [keys[2],keys[3]])

This will work as long as the ids are guaranteed to be unique, otherwise they will overwrite the older data.

Python, In this, we add dictionary to different tuple and then add the old tuple to this tuple into dictionary value list · Python | Test if key exists in tuple keys dictionary  Overwrites an existing string value in the dictionary with a tuple value. Adds a new key:value pair where the key is a tuple containing immutable objects. Attempts unsuccessfully to add a new key:value pair where the key is a tuple containing a mutable list. I will break this program down and discuss it in fragments. Use of boldface

Lesson 6, You can add, remove, and modify the values in dictionaries. Example: telephone book. Tuples. Tuples are pretty easy to make. You give your tuple a name, then  The items method also returns a view, which promises a list of tuples — one tuple for each key:value pair: Restrictions on Dictionary Keys. Almost any type of value can be used as a dictionary

Adding tuples to a dictionary - Python, prev_clk = new_clk. The difference is that instead of single values, tuples are added to the dictionary instead. When the program is run again: It is best to think of a dictionary as an unordered set of key: value pairs, with the requirement that the keys are unique (within one dictionary) and must be of an immutable types, such as a Python string, a number, or a tuple. The value can be of any type including collection of types hence it is possible to create nested data structures.

Tuples, The values stored in a tuple can be any type, and they are indexed by integers. the dictionary by value lst = list() for key, val in counts.items(): lst.append( (val,  Dictionary<string, List<Tuple<string, int>>> dict_Info_A = new Dictionary<string,List<Tuple<string,int>>>(); Ask Question. Asked 6 years, 8 months ago. Active 6 years, 8 months ago. Viewed 10k times. 1. I am using Dictionary with tuple as a parameter.

  • thank u very much, that's what i was looking for never used a dictionary before and didn't know even if what I wanted was possible plus also quite a noob in python.
  • FYI, (data.text for data in node if data.get('key') in [keys[2],keys[3]]) will produce a generator in Python 3 so you will need to convert it to a tuple