## Using DEC2BIN() with large numbers

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I'm trying to convert `4503599627370495` into binary in Excel. DEC2BIN() returns #NUM! error because DEC2BIN cannot handle such a large number.

Any thoughts on how I might be able to make it work?

Thanx JustinDavies - that was just what I needed, but it went into an endless loop if passed a -ve number. My modification:

```Function DecToBin(ByVal DecimalIn As Variant, Optional NumberOfBits As Variant) As String
DecToBin = ""
DecimalIn = CDec(DecimalIn)
If DecimalIn < 0 Then
DecToBin = "Error - Number negative"
Exit Function
End If
Do While DecimalIn <> 0
DecToBin = Trim\$(Str\$(DecimalIn - 2 * Int(DecimalIn / 2))) & DecToBin
DecimalIn = Int(DecimalIn / 2)
Loop
If Not IsMissing(NumberOfBits) Then
If Len(DecToBin) > NumberOfBits Then
DecToBin = "Error - Number too large for bit size"
Else
DecToBin = Right\$(String\$(NumberOfBits, "0") & _
DecToBin, NumberOfBits)
End If
End If
End Function
```

Decimal to binary conversion for large numbers in Excel, NOTE: =DEC2BIN() function cannot handle numbers larger than 511 so as you see my formula breaks your number into four 8-bit chunks, converts them to binary format and then concatenates the results. Well, theoretically you can extend this formula up to six 8-bit chunks. How could the number broken down into blocks of 512, converted, and concatenated to generate the final result?

See VBA posted here

```' The DecimalIn argument is limited to 79228162514264337593543950245
' (approximately 96-bits) - large numerical values must be entered
' as a String value to prevent conversion to scientific notation. Then
' optional NumberOfBits allows you to zero-fill the front of smaller
' values in order to return values up to a desired bit level.
Function DecToBin(ByVal DecimalIn As Variant, Optional NumberOfBits As Variant) As String
DecToBin = ""
DecimalIn = CDec(DecimalIn)
Do While DecimalIn <> 0
DecToBin = Trim\$(Str\$(DecimalIn - 2 * Int(DecimalIn / 2))) & DecToBin
DecimalIn = Int(DecimalIn / 2)
Loop
If Not IsMissing(NumberOfBits) Then
If Len(DecToBin) > NumberOfBits Then
DecToBin = "Error - Number too large for bit size"
Else
DecToBin = Right\$(String\$(NumberOfBits, "0") & _
DecToBin, NumberOfBits)
End If
End If
End Function
```

🥚 Using DEC2BIN () with large numbers, Thanx JustinDavies - this was exactly what I needed, but it got into an endless loop if the -ve number was accepted. My change: Function  binStr = dec2bin(D) returns the binary, or base-2, representation of the number D. The output argument binStr is a character vector that represents binary digits using the characters '0' and '1'. If D is a numeric vector, matrix, or multidimensional array, then binStr is a two-dimensional character array.

```=DEC2BIN(MOD(QUOTIENT(\$A\$1,256^3),256),8)&DEC2BIN(MOD(QUOTIENT(\$A\$1,256^2),256),8)&DEC2BIN(MOD(QUOTIENT(\$A\$1,256^1),256),8)&DEC2BIN(MOD(QUOTIENT(\$A\$1,256^0),256),8)
```

courtesy of Taosique who answered the duplicate Decimal to binary conversion for large numbers in Excel .

Excel: Using DEC2BIN() with large numbers : excel, Excel: Using DEC2BIN() with large numbers When I've done this in the past, I'​ve either created my own VBA function to do it, or did it with helper columns. no, for large numbers DEC2BIN functions dont work. Any other suggestions? "Barb Reinhardt" wrote: > Will the DEC2BIN function get you what you want? > > "Himu" <Himu@discussions.microsoft.com> wrote in message > news:E40F29E6-4C74-438F-86FF-E01895D4EE1D@microsoft.com > >i want a column which will contain numbers from 0~65536. Then I want to

This is super simple and how the dec2bin should work

=BASE(CELL, 2)

Convert decimal number to character array representing binary , Starting in R2020a, the dec2bin function converts negative numbers using their If D is so large that it must be represented with more than minDigits digits, then  You cannot format a 20 digit number using the TEXT function since Excel's precision is limited to 15 digits. Anything longer will become a zero. You need to use string functions to obtain your desired formatting, but you just need to split your string in C into small enough (less than 15 digit) strings.

I needed a VBA function to convert Excel decimal integers to binary since MS failed me, yet again. I came up with the following, but I had to accept a string of ones & zeros as output, which was OK for me. It uses log base 2 which may be unique (or not?) and works for all positive integers as-is.

```Function Dec_Bin(dx As Integer) As String
Dim x As Integer
Dim y As Long
Dim z As Integer
Dim zz As Double
Dim ch As String
Dim str As String, s1 As String

ch = String(15, "0")
'    Stop
zz = Log(dx) / Log(2)
z = Fix(zz)
y = dx - 2 ^ z
z = 15 - z
Mid(ch, z, 1) = "1"
While y > 0
zz = Log(y) / Log(2)
z = Fix(zz)
y = y - 2 ^ z
z = 15 - z
Mid(ch, z, 1) = "1"
Wend

ch = ch & "B"
Dec_Bin = ch
End Function
```

Converting larger number from decimal to binary (video), 0:14and rewrite this in its binary representation. So, if you've got a really huge number of Duration: 4:12 Posted: Jul 27, 2014 Stack Overflow for Teams is a private, secure spot for you and your coworkers to find and share information. Learn more bin2dec for numbers longer than 10 bits in excel

DEC2BIN function - Office Support, Negative numbers are represented using two's-complement notation. Places Optional. The number of characters to use. If places is omitted, DEC2BIN uses the  Value can be any integer decimal number or a cell contained it, small or superbig. Bytes is optional, standard 2, automatic. =Bino(A1,4) The number or bytes and bits presented is automatic based on its value, standard minimum of 2 bytes, but you can pad with extra zero bytes at left, using the optional bytes argument. The example above will show A1 with 4 bytes and 32 bits, even if A1 contains a single numeric digit, or will use more bytes and bits if larger than 4.

How to use the Excel DEC2BIN function, The input number must contain only zeros and ones and be less than 10 characters long, otherwise the function returns the #NUM! error value. Excel Formula  Equations are of the form (x*y + n) - x*y which has the obvious result n. But Matlab gives strange results. I realized that 1812433253*19650218 has more than 53 bits and these results has something to do with the way Matlab handles numbers between 53 bits and 64 bits. But I couldn't find a reliable way to carry out above operations correctly.

BIN2DEC conversion for large binary numbers, I need your help, i want to convert large binary numbers using excel but whenever i use the BIN2DEC function the result is negative which Is there anyway to convert a number to binary Learn more about binary numbers, number of values, bin2dec, binary, floating point, decimal fraction