SQL Server - Select distinct with most recent date plus other results

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Having the registers above, how can I get the code (taking into account that the first 3 codes are the same) that has most recent date, and still show the other results?

id  |  agency   |  code     |   date
1   |  11111    |  12345    |   2018-09-25 00:01:10.000
2   |  11111    |  12345    |   2018-09-25 00:01:20.000
3   |  11111    |  12345    |   2018-09-25 00:01:30.000
4   |  22222    |  23456    |   2018-09-25 00:02:00.000
7   |  33333    |  54321    |   2018-09-25 00:02:10.000

What I would like to have is:

id  |  agency   |  code     |   date
3   |  11111    |  12345    |   2018-09-25 00:01:30.000
4   |  22222    |  23456    |   2018-09-25 00:02:00.000
7   |  33333    |  54321    |   2018-09-25 00:02:10.000

Thanks in advance for any further help!

Think "filtering". In this case, with a correlated subquery:

select t.*
from t
where t.date = (select max(t2.date) from t t2 where t2.agency = t.agency);

How to Compare Date in SQL Server Query? Finding , How do I select a record without duplicates in one column in SQL? If you apply the DISTINCT clause to a column that has NULL, the DISTINCT clause will keep only one NULL and eliminates the other. In other words, the DISTINCT clause treats all NULL “values” as the same value. SQL Server SELECT DISTINCT examples. For the demonstration, we will use the customers table from the sample database.

You have two situations to deal with. (1) Get max date of each agency from youTable. This can be done by using aggregate function(max()) and group by agency.

(2) Select all record from yourTable and inner join with the results from (1).

select t1.id, t1.agency,t1.code,t1.date 
from yourTable t1 
    inner join 
    (
        --only most recent of each agency
        select max(date) date,agency from yourTable group by agency
    ) t2 on t1.[date]=t2.[date] and t1.agency=t2.agency

SQL Server SELECT DISTINCT, How to find the oldest or most recent record associated with a This is straightforward in SQL. (other than the fact that it has a timestamp column called created_at ): to display a list of users next to the date of their most recent order. This adds a bit of complexity, but with a JOIN and a sub-select the  Some of the data may look like this: I'd like to run a query that pulls the most recent value of the AttributeValue column for each distinct ForeignKeyId andAttributeName, using the Created column to determine the most recent value. Example output would be: How can I do this using SQL Server 2005? Shouldn't the value be 3, not 1, for the

Use ROW_NUMBER value


This will help you.

You can get the ROW_NUMBER value for each row by your distinct columns. Set it in order by of your DATE column.

SELECT  *
FROM  (
        SELECT  *,
            ROW_NUMBER() OVER(PARTITION BY AGENCY, CODE ORDER BY date_column) AS ROW_NUMBER
        FROM  table_name
    ) AS ROWS
WHERE ROW_NUMBER = 1

Sample SQL Fiddle

SQL DISTINCT: Removing Duplicates In a Result Set Examples, How do the SQL Distinct and SQL TOP SELECT modifiers Work Together in the same SELECT statement to create a new result set? on Microsoft SQL Server Management Studio and the AdventureWorks2012 database. I say direct, as you could get a distinct list, and then use a INNER JOIN to pull in other columns. The SQL SELECT DISTINCT Statement. The SELECT DISTINCT statement is used to return only distinct (different) values. Inside a table, a column often contains many duplicate values; and sometimes you only want to list the different (distinct) values. SELECT DISTINCT column1, column2, FROM table_name;

Finding the Oldest/Youngest Records Within a Group, Like every other website we use cookies. i.e. my result should look like this: Column1)as Column1 , Column2 from table a inner join table b on a. .com/​questions/16966415/sql-server-select-distinct-latest-values[^] A INNER JOIN TABLE T on A.Column1 = T.Column1 AND A.Column2 = T.Column2. DISTINCT. The DISTINCT predicate is similar to the UNIQUE predicate, except in the way it treats nulls. If all the values in a result table are UNIQUE, then they’re also DISTINCT from each other.

SQL DISTINCT and TOP in Same Query, Select BOTH the home and its max date time, then join back to the top table on BOTH the fields: Want to learn SQL from basics! Here's the right  Introduction to SQL DISTINCT operator. The primary key ensures that the table has no duplicate rows. However, when you use the SELECT statement to query a portion of the columns in a table, you may get duplicates. To remove duplicates from a result set, you use the DISTINCT operator in the SELECT clause as follows: SELECT DISTINCT column1, column2,

[Solved] SQL Select Query for distinct latest record, This tutorial shows you how to use the SQL Server SELECT DISTINCT clause to retrieve the only distinct values in a specified list of columns. In other words, it removes the duplicate values in the column from the result set. a column that has NULL, the DISTINCT clause will keep only one NULL and eliminates the other. A common query that crops up in web apps is finding the oldest or the most recent record in a single table. This is straightforward in SQL. You can even write the relevant part of the query without knowing anything about the table (other than the fact that it has a timestamp column called created_at ): ORDER BY created_at LIMIT 1.

Comments
  • What's the relationship between agency and code? Can an agency be related to more than one code?
  • @Anderson: Is it mandatory to have ID as MAX_VALUE??
  • This answer could be improved by providing some discussion on why it solves the issue.