Ascending Numbers in Java

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java program to arrange the digits of a number in ascending order
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I'm trying to get the numbers in ascending order. When I go to console and type a number, the number prints but not in ascending order, just the number i put in.What am I doing wrong?

import java.util.*;
public class BigLittle{
   public static void main(String[]args){
      Scanner in=new Scanner(System.in);

      int a=0;
      int b=0;
      int c=0;

      System.out.print("Enter 3 Numbers");
      a=in.nextInt();
      b=in.nextInt();
      c=in.nextInt();

      if (a>b&&b>c)
         System.out.print(c);
      if (a>c) {
        System.out.print(b);
        System.out.print(a); 
      }

      if (b<a&&b<c)
        System.out.print(b);
      else {
        System.out.print(a);
        System.out.print(c);
      }
      if (c>a&&a<b)
         System.out.print(a);
      if (b<c){
         System.out.print(c+b+a);
      }
   }
}

Put the numbers from input into a List and then sort the List:

    List<Integer> list = new ArrayList<>();

    Scanner in=new Scanner(System.in);

    System.out.print("Enter 3 Numbers: ");
    list.add(in.nextInt());
    list.add(in.nextInt());
    list.add(in.nextInt());

    Collections.sort(list);

    for ( Integer i : list )
    {
        System.out.println(i);
    }

Java Program to Sort an Array in Ascending Order, In this program, user is asked to enter the number of elements that he wish to enter. Based on the input we have declared an int array and then we are accepting  I'm trying to get the numbers in ascending order. When I go to console and type a number, the number prints but not in ascending order, just the number i put in.What am I doing wrong? import java.

First of all, if c = 8, b = 4 and a = 1 if will print 13 with that line System.out.print(c+b+a);

Also, if a=b=c nothing prints, or any combinaisons that a=b, b=c or a=c, there is some printing undefined.

If you want a simple architecture, try to put an array or 3 variables to put the values in it and then print only at the end of the computation.

Ascending and Descending Number Order in java, Three possible solutions come to my mind: 1. Reverse the order: //convert the arr to list first Collections.reverse(listWithNumbers); System.out.print("Numbers in  Ascending order is the order in which the number starts from lowest and move to the greatest, whereas Descending order is the order in which the number start from the greatest and move toward the lowest. Check out the simple java code for ascending and descending of a give set of numbers. Ascending Descending Order Java

For three distinct numbers a, b, c there are 6 possible permutations:

1 2 3
1 3 2
2 1 3
2 3 1
3 1 2
3 2 1

Let's start by using the relationship between a & b to partition these into 2 sets

a < b 
    1 2 3
    1 3 2
    2 3 1    
a > b
    2 1 3
    3 1 2
    3 2 1

Now let's further divide these 2 sets by considering the relationship between b & c:

a < b 
  b < c
    1 2 3
  b > c
    1 3 2
    2 3 1    
a > b
  b < c
    2 1 3
    3 1 2
  b > c
    3 2 1

We see that in cases where (a < b and b < c) and (a > b and b > c) we can uniquely determine the ordering. For the remaining cases we need to consider the relationship between a & c

a < b 
  b < c
    1 2 3
  b > c
    a < c
      1 3 2
    a > c
      2 3 1    
a > b
  b < c
    a < c
      2 1 3
    a > c
      3 1 2        
  b > c
    3 2 1

From this we can develop the following pseudocode:

if a < b
  if b < c
    order: a b c
  else 
    if a < c
      order: a c b
    else
      order: c a b
else
  if b < c
    if a < c
      order: b a c
    else
      order: b c a
  else
    order: c b a

Which you should be able to turn into Java code.

How to sort Java array elements in ascending order?, To sort an array in Java, you need to compare each element of the array to all the the size of the array that is to be created::"); int size = sc. Enter How Many Inputs: 5 Enter Value #1:3 Enter Value #2:5 Enter Value #3:6 Enter Value #4:11 Enter Value #5:2 Numbers in Ascending Order: 2 3 5 6 11 Numbers in Descending Order: So, the Arrays.sort(arr) call seems to work - but I'm looking for a similarly simple way to provide the descending sort, and can't find it in the documentation.

Java Program to sort the elements of an array in ascending order , int [] arr = new int [] {5, 2, 8, 7, 1};; int temp = 0;; //Displaying elements of original array  java program for displaying numbers in ascending order No comments. java program for displaying numbers in increasing order

Arrays.sort() in Java with examples, ascending order. import java.util.Arrays;. public class SortExample. {. public static void main(String[] args). {. // Our arr contains 8 elements. int [] arr = { 13 , 7 , 6  // Sorting List in Java in ascending order in Java List < Integer > list = Arrays. asList (1, 2, 5, 9, 3, 6, 4, 7, 8); System. out. println ("Unsorted List in Java: "+ list); // Sorting List into Java now, Collections.sort() method will sort

Print number in ascending order which contains 1, 2 and 3 in their , Given an array of numbers, the task is to print those numbers in ascending order separated by commas which Java program to print all number containing. 3. Java 8. Sorting a List became even easier with an introduction of Stream API in Java 8 and above. The idea is to get a stream consisting of the elements of the list, sort it in natural order using Stream.sorted() method and finally collect all sorted elements in a List using Stream.collect() with Collectors.toList().

Java program to sort an array in ascending order, In this java program, we are reading total number of elements (N) first, and then according the user input (value of N)/total number of elements,  $ javac Ascending _Order.java $ java Ascending _Order Enter no. of elements you want in array:5 Enter all the elements: 4 3 2 6 1 Ascending Order:1,2,3,4,6 Sanfoundry Global Education & Learning Series – 1000 Java Programs.

Comments
  • What numbers are you putting in?
  • The user puts in the number. I just tried random numbers but it didnt work
  • What numbers did you put in, when it didn't work?
  • Rather than use complicated if/else statements that wouldn't scale beyond a few numbers you should add the numbers to a collection like an ArrayList and sort it using Collections.sort() then iterate through the list and print the numbers.
  • Please format your code properly.
  • @DawoodibnKareem: thank you, after midnight is definitely to late to work ;)