## Finding missing elements in a List

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find missing number in sorted array

Hello I have a List with a lot of element in it. These are numbers and ordered but some numbers are missing.

Example: `L =[1,2,3,4,6,7,10]`

Missing: `M = [5,8,9]`

How can I find missing numbers in Python?

This function should do the trick

def missing_elements(L): s, e = L[0], L[-1] return sorted(set(range(s, e + 1)).difference(L)) miss = missing_elements(L)

**Python,** To find the additional elements in list1, calculate the difference of list1 from list2. Insert the list1 and list2 to set and then use difference function in sets to get the Hello I have a List with a lot of element in it. These are numbers and ordered but some numbers are missing. Example: L =[1,2,3,4,6,7,10] Missing: M = [5,8,9] How can I find missing numbers in P

Take the difference between the sets:

set(range(min(L),max(L))) - set(L)

If you are really crunched for time and `L`

is truly sorted, then

set(range(L[0], L[-1])) - set(L)

**Find the Missing Number,** Approach: The length of the array is n-1. So the sum of all n elements, i.e sum of numbers from 1 Duration: 7:47
Posted: Jan 12, 2014 By your definition of what a missing-positive integer is, this can be found through some math. def solution(A): n = len(A) + 1 list_sum = (n * (n+1)) / 2 a_sum = sum(A) missing = list_sum - a_sum if missing != n: return missing Take the length of the list and add one and define it as n.

Here you are:

L =[1,2,3,4,6,7,10] M = [i for i in range(1, max(L)) if i not in L] # If 0 shall be included replace range(1, max(L)) to range(max(L))

**How to find missing elements in a list?,** target_list=['one', 'two', 'three','four', 'five'] output_list=['two','three','four', 'five'] l = [x for x in target_list if x not in output_list] print("Number of Find missing elements of a range Given an array arr[0..n-1] of distinct elements and a range [low, high], find all numbers that are in range, but not in array. The missing elements should be printed in sorted order.

With a comprehension it would look like this:

L = [1,2,3,4,6,7,10] M = [i for i in range(min(L), max(L)+1) if i not in L] M #[5,8,9]

And a fun one, just to add to the bunch:

[i for a, b in zip(L, L[1:]) for i in range(a + 1, b) if b - a > 1]

**How to find a missing number from a list?,** Simple solution for the above problem, it also finds multiple missing elements. a = [1,2,3, Similarly while finding missing elements of list1, calculate the difference of list2 from list1. To find the additional elements in list1, calculate the difference of list1 from list2. Insert the list1 and list2 to set and then use difference function in sets to get the required answer.

L =[1,2,3,4,6,7,10] R = range(1, max(L) + 1) > [1,2,3,4,5,6,7,8,9,10] M = list(set(R) - set(L)) > [5,8,9]

Note that M will not necessarily be ordered, but can easily be sorted.

**Quickest way to find missing number in an array of numbers,** How do you find the missing number in a list Python? Find the Missing Number. You are given a list of n-1 integers and these integers are in the range of 1 to n. There are no duplicates in the list. One of the integers is missing in the list. Write an efficient code to find the missing integer. Example : Input: arr[] = {1, 2, 4,, 6, 3, 7, 8}. Output: 5.

**Python: Find missing numbers from a list,** How do you find the missing number in an array of 1 to 100? z contains a list of integers. I want to compare item to z and print out the numbers that are not in z when compared to item. I can print the elements that are in z when compared not item, but when I try and do the opposite using the code above nothing prints. Your code is not doing what I think you think it is doing.

**Python program to find missing and additional values in two lists?,** Python Exercises, Practice and Solution: Write a Python program to find missing numbers from a list. Check if element exist in list based on custom logic Python any() function checks if any Element of given Iterable is True. Let’s use it to check if any string element in list is of length 5 i.e.

**How to find the missing number in a sorted array,** Step 5 : Same procedure apply for Second list also. Example Code. #To find the missing and additional elements A=list() B Here, we have an array and finding an element which is missing in the list. Given an array of integers (in a series) and we have to find its missing elements (there will be a missing element) using java program. Example: Program to find missing element in an array in java.

##### Comments

- what did you try?
- Or equivalent and not needing to build another set...
`set(L).difference(range(min(L), max(L)))`

? - Indeed @JonClements, although I still believe this will hash all the elements in the iterable passed to difference under the hood.
- For
`L =[1,2,3,4,6,7,10]`

, your code gives the output as`{10}`

. That's not what the OP wants. Change the order of subtraction - good call @Bazingaa. Or we can just include the last element.
- You again got it wrong. Your edited version with
`+1`

returns an empty set for`L =[1,2,3,4,6,7,10]`

. The required output is`[5,8,9]`

so plz edit your answer with the correct subtraction order. I would also convert the final set into list as the OP wants list as an output.