How to round a floating point number up to a certain decimal place?
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Suppose I have
8.8333333333333339, and I want to convert it to
8.84. How can I accomplish this in Python?
round(8.8333333333333339, 2) gives
8.83 and not
8.84. I am new to Python or programming in general.
I don't want to print it as a string, and the result will be further used. For more information on the problem, please check Tim Wilson's Python Programming Tips: Loan and payment calculator.
8.833333333333334, the result of
106.00/12) properly rounded to two decimal places is
8.83. Mathematically it sounds like what you want is a ceiling function. The one in Python's
math module is named
import math v = 8.8333333333333339 print(math.ceil(v*100)/100) # -> 8.84
Respectively, the floor and ceiling functions generally map a real number to the largest previous or smallest following integer which has zero decimal places — so to use them for 2 decimal places the number is first multiplied by 102 (or 100) to shift the decimal point and is then divided by it afterwards to compensate.
If you don't want to use the
math module for some reason, you can use this (minimally tested) implementation I just wrote:
def ceiling(x): n = int(x) return n if n-1 < x <= n else n+1
How this applies to the linked loan and payment calculator problem
From the sample output it appears that they rounded up the monthly payment, which is what many call the effect of the ceiling function. This means that each month a little more than 1⁄12 of the total amount is being paid. That made the final payment a little smaller than usual — leaving a remaining unpaid balance of only
It would have been equally valid to use normal rounding producing a monthly payment of
8.83 and a slightly higher final payment of
8.87. However, in the real world people generally don't like to have their payments go up, so rounding up each payment is the common practice — it also returns the money to the lender more quickly.
Limiting floats to two decimal points, The floating point type in Python uses double precision to store the values. This produces a float number as a string rounded to two decimal points. the display to a certain precision, then don't even use round and just format it as that string. Rounding Floating Point Number To two Decimal Places in C and C++. How to round off a floatig point value to two places. For example, 5.567 should become 5.57 and 5.534 should become 5.53. First Method:- Using Float precision. #include <iostream>. using namespace std;
This is normal (and has nothing to do with Python) because 8.83 cannot be represented exactly as a binary float, just as 1/3 cannot be represented exactly in decimal (0.333333... ad infinitum).
If you want to ensure absolute precision, you need the
>>> import decimal >>> a = decimal.Decimal("8.833333333339") >>> print(round(a,2)) 8.83
Rounding Floating Point Number To two Decimal Places in C and C++, Rounding Floating Point Number To two Decimal Places in C and C++. How to round off a floatig point value to two places. Setting decimal precision in C · Program for Sum of the digits of a given number · What is the best way in C to convert The f format lets you specify a particular number of decimal places to round its argument to. Perl looks at the following digit, rounds up if it is 5 or greater, and rounds down otherwise. Perl looks at the following digit, rounds up if it is 5 or greater, and rounds down otherwise.
You want to use the decimal module but you also need to specify the rounding mode. Here's an example:
>>> import decimal >>> decimal.Decimal('8.333333').quantize(decimal.Decimal('.01'), rounding=decimal.ROUND_UP) Decimal('8.34') >>> decimal.Decimal('8.333333').quantize(decimal.Decimal('.01'), rounding=decimal.ROUND_DOWN) Decimal('8.33') >>>
How to Round Numbers in Python – Real Python, Round the number n to p decimal places by first shifting the decimal point in n by p This strategy always rounds a number up to a specified number of digits. The Python docs have a section called Floating Point Arithmetic: Issues and How to round a floating point number up to 0 votes Suppose I am having 8.8333333333333339 and I want to convert it to 8.84, how can I accomplish this in python? round(8.8333333333333339, 2) gives 8.83 and not 8.84.
A much simpler way is to simply use the round() function. Here is an example.
total_price = float() price_1 = 2.99 price_2 = 0.99 total_price = price_1 + price_2
If you were to print out total_price right now you would get
But if you enclose it in a round() function like so
The output equals
The round() function works by accepting two parameters. The first is the number you want to round. The second is the number of decimal places to round to.
Python round(), The round() function returns a floating-point number rounded to the specified number of decimals. In this tutorial, we will learn about Python round() in detail with the help of If ndigits is given, round() returns the number rounded off to the ndigits digits. Example 2: Round a number to the given number of decimal places. Example 1: Round a Number using format. When you run the program, the output will be: In the above program, we've used format() method to print the given floating point number num to 4 decimal places. The 4 decimal places is given by the format .4f.
If you round 8.8333333333339 to 2 decimals, the correct answer is 8.83, not 8.84. The reason you got 8.83000000001 is because 8.83 is a number that cannot be correctly reprecented in binary, and it gives you the closest one. If you want to print it without all the zeros, do as VGE says:
print "%.2f" % 8.833333333339 #(Replace number with the variable?)
How to round a floating point number up to certain decimal place in , Suppose I am having 8.8333333333333339 and I want to convert it to 8.84, how can I Wilson's Python Programming Tips: Loan and payment As a first parameter, we are passing our number we would like to round, as a second parameter the number of decimal places, we would like to keep. We have to use negative values at this point in order to round to decimal places. Positive values can be used to round, for example, to hundreds or thousands: RoundTo(12345, 2) = 12300.
Round to nearest decimal or integer - MATLAB round, Round to Specified Number of Decimal Digits whether round considers digits in relation to the decimal point or the overall number of significant digits. N must Summary: Use Windows PowerShell to round numbers to a specific decimal place. continue to have a number instead of converting it to a string. Use the Round static method from the System.Math class. By default, it does not display decimal places, but you can easily change that behavior. The following code illustrates this procedure:
How to Round a Number to N Decimal Places in Java, How to Round a Number to N Decimal Places in Java two primitive types that can be used for storing decimal numbers: float and double. If we just want to print a decimal number with n digits after decimal point, we can From the above code, we can further deduce that the format() function can also be used to convert a specific number of decimal points. round() function to print floats to a specific number of decimal points in Python. The method can be best explained with an example given below: Example:
Round a number to the decimal places I want, On the Home tab, click Increase Decimal or Decrease Decimal to show more or fewer digits after the decimal point. By applying a built-in number format: On the Y = round(X) rounds each element of X to the nearest integer. In the case of a tie, where an element has a fractional part of exactly 0.5, the round function rounds away from zero to the integer with larger magnitude.
- round(8.8333333333333339 , 2) will give 8.83 never 8.84 it seems.
- Why 8.84? 8.8333333... should be rounded to 8.83 when aiming for two decimal places.
- duplicate: stackoverflow.com/questions/56820/…
- if you want to print the value use a format such as print "%.2f"%8.8333333333333339. this will print the value with 2 digit
- I edited the title because this comes up as an early result for "python round float," and it's probably not what most people are looking for. Hopefully, the new title makes things more clear.
- Not if you use the
>>> 106.00/12 => 8.833333333333334
- The format answer was given in 2010 here. You could have updated that answer instead.
- >>> decimal.getcontext().prec = 3 >>> decimal.Decimal(106)/decimal.Decimal(12) Decimal('8.83') this is what I got, and not 8.84