Dividing integer by all numbers in a range in Python

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I'm trying to write a script that divides an integer by all numbers in a range and have a value of true only if all numbers are to 0 decimal places.

Here is the code I have written so far:

n = int(input("Please enter a number (more than 0) :"))
count = 0


if n < 1 : print("Please enter a positive number")
else:
    if n%2 == 0 : print("Number is not prime")
    else:

        for i in range(3, int(n**0.5)+1):
                if i % n == 0 :
                    count = count + 1
                    count = count + 0

if count > 1 : print("Number is not prime")
else : print("Number is prime")

It prints Number is prime for any odd number.

Any ideas why this doesn't work?

Thanks.

You are wrong on two counts -

        for i in range(3, int(n**0.5)+1):
            if n%i == 0 : # You want to check if n is divisible by i
                count = count + 1
                # No need of count = count + 0 here since it does nothing

if count > 0 : print("Number is not prime") # Prime if count > 0 & not count > 1
else : print("Number is prime")

Also, you can improve the code by running the for loop in steps of 2 rather than 1 i.e. check if n is divisible by all odd numbers from 3 to sqrt(n) instead of all numbers from 3 to sqrt(n).

for i in range(3, int(n**0.5)+1, 2): # The 3rd argument indicates steps

Count elements which divide all numbers in range L-R , The range 2-6 has {4, 2, 2, 4, 6} which has 2 numbers {2, 2} which divides all numbers in the given range. every query and check if the given element at index-i divide all the numbers in the range. count++;. } // answer for every query​. return count;. } // Driver Code. int main() Python 3 program to Count elements which. Divisors of an integer in Python. We will first take user input (say N) of the number we want to find divisors. Then we will run a loop from 1 to (N+1). We do so because if we run the loop from 0(zero) then we will get ‘Division By Zero Error’.

if count > 1 : print("Number is not prime") should be if count >= 1 : print("Number is not prime"). Also, in if n%2 == 0 : print("Number is not prime"), count should be incremented. Better, why even have if n%2 == 0 : print("Number is not prime")? Change 3 in for i in range(3, int(n**0.5)+1): to 2, and that if statement can be removed.

PS: count = count + 0 does nothing, so remove it.

Find if a number is divisible by every number in a list, Given a list and a number task is to find the number which is divided by every element of the list. Examples : bool findNoIsDivisibleOrNot( int a[], int n, int l). {. for ( int i = 0; Python program which check is a number for i in range ( 0 , len (​l)):. First output is fine, but the second one may be surprising if we are coming Java/C++ world. In Python 2.7, the “/” operator works as a floor division for integer arguments. However, the operator / returns a float value if one of the arguments is a float (this is similar to C++)

inp = int(input("Type a number: "))  

isprime = 'true'                

for x in range(2, inp):
    y = (inp % x)
    if y == 0:
        isprime = 'false'

print(isprime)

Python Program to Print all Numbers in a Range Divisible by a , Here is the source code of the Python Program to print all numbers in a range limit:")) n=int(input("Enter the number to be divided by:")) for i in range(lower  Now, divide the number by 10. Finally, check whether the number is a Harshad number-Check whether the number is divisible by the sum or not. If the number is divisible, then the number is a Harshad number. Python program to display Harshad numbers. So, let us see a program to print all Harshad numbers within the range given by the user.

Algorithm for dividing a range into ranges and then finding which , The numbers I work with are integers. Edit: Another example: For min=1, max = 3, number of ranges=2 the ranges would be. a) [  range() (and Python in general) is 0-index based, meaning list indexes start at 0, not 1. eg. The syntax to access the first element of a list is mylist[0] . Therefore the last integer generated by range() is up to, but not including, stop .

Python range for Float Numbers [UPDATED], Use Python Generator to produce a range of float numbers. The main limitation of Python's range() is it works only with integers. The Following code divided into 2 Sections. the first section contains function frange(). Here another small snippet of mathematical nature returning all possible divisors of number. (set is, by the way, needed because of perfect squares. Not possible to edit the snippet part but here the same with less stupid command line interface (not repeating the loop):

3. An Informal Introduction to Python, To do integer division and get an integer result, discarding any Complex numbers are always represented as two floating point numbers, the real and imaginary part. This variable should be treated as read-only by the user. Sequence Types — str, bytes, bytearray, list, tuple, range: Strings are  In this tutorial, we will be finding the sum of natural numbers in the range given by the user. We will be using a for loop to find the same. To calculate the sum of integers in a range in Python we will be using the following concepts: We will be taking the lower bound and upper bound of the range from the user.

Comments
  • I think that removing the line beginning if n%2 == 0... and having your for loop begin at 2 would work just as fine, if not better.
  • Another problem is: 1 is shown as a prime number and it is not. How could this be shown as not a prime number?
  • Thanks for all responses. It was because i % n == 0 was incorrect haha. Much appreciated.
  • If you find that my answer was right & complete, please accept it & close the question.
  • While I'm marking this question as "Looks OK", you should know that code-only answers are looked down upon here. Please try to add some explanation to this answer and other answers you may post later.