## counting special characters with recursion

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I'm trying to code this one up,but I don't get an expected result: Given a string, compute recursively (no loops) the number of lowercase 'x' chars in the string. ```countX("xxhixx") → 4 countX("xhixhix") → 3 countX("hi") → 0```

Here is my method:

```public int countX(String str) {
int count = 0;

if(str.length() >= 1 ) {
if(str.substring(0, 1).equals("x")) {
str = str.substring(1, str.length());
count = count + 1 + countX(str);
}
}
else {
str = str.substring(1, str.length());
count = count + countX(str);
}

return count;
}
```

You had the right idea, but I think you over complicated things. Just check explicitly if the first character is `x` (as you have), and only increment `count` in that case. Regardless of whether it was or wasn't, continue recursing on:

```public static int countX(String str) {
int count = 0;

if (str.length() > 0) {
if (str.substring(0, 1).equals("x")) {
++count;
}

str = str.substring(1, str.length());
count += countX(str);

}

return count;
}
```

Example: number of occurrences of a character in a string, You had the right idea, but I think you over complicated things. Just check explicitly if the first character is x (as you have), and only increment count in that case. Count consonants in a string (Iterative and recursive methods) Program to reverse a string (Iterative and Recursive) C program to count number of vowels and consonants in a String; Python program to count number of vowels using sets in given string; Program to count vowels, consonant, digits and special characters in string.

Suppose you have a string "axbxcx". The code below looks only at the first character in the string and determines if it is an x. If so, then return 1 in addition to the number of x's found in the rest of the string. If the first character is not an x, then the number of x's in the string is equal to the number of x's in the string not including the first character, so that is what is returned.

```int count(String s)
{
if (s.length() == 0)   // base case
{
return 0;
}

if (s.charAt(0) == 'x')
{
return 1 + count(s.substring(1));
}
else
{
return count(s.substring(1));
}
}
```

Count occurrences of a substring recursively, Recursive characterization of the operation of counting the occurrences of the character c in the string s: if s is the empty string "", then return 0;; otherwise, if the​  Count special palindromes in a String Given a String s, count all special palindromic substrings of size greater than 1. A Substring is called special palindromic substring if all the characters in the substring are same or only the middle character is different for odd length.

```public static int countX(String str) {

if (str.length() == 0) {
return 0;

}

if (str.substring(0, 1).equals("x")) {
return 1 + countX(str.substring(1));
}

return countX(str.substring(1));
}
```

Count Occurrences of a Char in a String, Recursive C++ program for counting number of substrings Length of the largest substring which have character with frequency greater than or equal to half of  Count of e in GeeksforGeeks is : 4. Method #4 : Using lambda + sum () + map () Lambda functions, along with sum () and map () can achieve this particular task of counting the total occurrences of particular element in a string. This uses sum () to sum up all the occurrences obtained using map (). # Python3 code to demonstrate.

You should try this (it assumes you are testing outside the method that initial str value is not null and has a length greater than 0).

```    public int countX(String str) {
if ( str.length() == 1 ) {
return ("x".equalsTo(str) ? 1 : 0);
} else {
return (str.charAt(0) =='x' ? 1 : 0) + countX(str.substring(1,str.length())
}

}
```

Count characters in cells with Excel for Mac, Learn how to count characters with the core Java library and with libraries and remove special chars, validate, trim, collapse, replace and count among other A less obvious, but still interesting solution is to use recursion: ? Given an array of integers, find sum of array elements using recursion. We have discussed iterative solution in below post. In this post, recursive solution is discussed. // elements using recursion. // elements using recursion. # elements using recursion. // elements using recursion. // A [0..N-1] using recursion.

Here is a simple way to do it.

First, check if the string is empty. This is the terminating condition of the recursion.

Then your result is simply the count for the first character (`1` or `0`), added to the count for the rest of the string (calculated by calling your function on `substring(1)`).

```public static int countX(String str) {
if (str.isEmpty()) {
return 0;
}
return (str.charAt(0)=='x' ? 1 : 0) + countX(str.substring(1));
}
```

C# Sharp programming exercises: String, In this example, the LEN function counts the characters in each cell and the SUM function adds the counts. To count certain, specific characters within cells, use the  Select the TOOLS menu and then WORD COUNT. A dialogue box will appear containing the character count. Character counting tools many times will provide additional information, such as the character count with and without spaces. In addition, many of the programs will perform a character count of a selected text. To do this, select the text requiring a character count and simply open the character count tool.

C++ Program to Count the Number of Vowels/Consonants/Numbers , Write a program in C# Sharp to count a total number of alphabets, digits and special characters in a string. Go to the editor. Test Data : Input the  Count Uppercase, Lowercase, special character and numeric values Given a string, write a program to count the occurrence of Lowercase characters, Uppercase characters, Special characters and Numeric values.

7.2. re — Regular expression operations, Variables 'v', 'c', 'n', 's' are initialized to count vowels, consonants, numbers and special characters respectively. 3. Using nested if else condition, if any of the  Absolutely I need a function that takes a search character and a string and uses recursion to return a number of times that character appears in the string. Then I need a function that takes a search character and a file name ie a text file containing multiple lines of text and use a for loop to print the lines containing the letter and the

C Program To Count Occurrences Of A Character In String, Regular expressions can contain both special and ordinary characters. of pattern occurrences to be replaced; count must be a non-negative integer. _compile(pattern, flags).match(string) RuntimeError: maximum recursion limit exceeded. Write a Python Program to Count Number of Digits in a Number using While Loop, Functions, and Recursion. This python program allows the user to enter any positive integer. Then it divides the given number into individual digits and counts those individual digits using Python While Loop. This Python program allows the user to enter any positive