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What is wrong in my code?

Expected output=1060

I checked with 1000 prime numbers sum. It will show correctly output 3682913

public class PrimeNumber {

      public static void main(String args[]){

            int number = 2;
            int count = 0;
            long sum = 0;
            while(count <100){ 
                if(isPrimeNumber(number)){
                    sum += number;
                    count++;
                }
                number++;
            }
            System.out.println(sum);
        }

        private static boolean isPrimeNumber(int number){

            for(int i=2; i<=number/2; i++){
                if(number % i == 0){
                    return false;
                }
            }
            return true;
        }
    }

Currently, you are counting the first 100 primes, not the primes found in the range 1 - 100. You can lose the count variable entirely here.

Your code can be simplifed as such, using a for loop instead to go from 2 to 100 (1 not included, of course)...

public class PrimeNumber {
    public static void main(String args[]) {
        long sum = 0;
        for (int number = 2; number <= 100; number++) {
            if (isPrimeNumber(number)) {
                sum += number;
            }
        }

        System.out.println(sum);
    }

    private static boolean isPrimeNumber(int number){
        for (int i = 2; i <= number / 2; i++) {
            if (number % i == 0) {
                return false;
            }
        }

        return true;
    }
}

Java program to display prime numbers from 1 to 100 and 1 to n, Here we will see two programs: 1) First program will print the prime numbers between 1 and 100 2) Second It will display all the prime numbers between 1 and n (n is the number, entered by user). import java.util. The person who wrote the logic has written a very good code, I am not expert in java and this would be my  How to write a C Program to Print Prime Numbers from 1 to 100 or Minimum to maximum. Or, prime Numbers within a specific range, and some of the prime numbers within a range using For Loop and While Loop. TIP: We already explained the logic to check whether the given is prime or not in C Program to Find Prime Number article.

You are counting up to 100 primes but not up to 100 numbers.

So your while loop should run up to 100 numbers.

This should be your main method:

int number = 2;
      int count = 0;
      long sum = 0;
      while(number <= 100){ 
          if(isPrimeNumber(number)){
              sum += number;
              count++;
          }
          number++;
      }
      System.out.println(sum);
  }

This would give your output 1060.

C++ Program to display prime numbers from 1 to 100 and 1 to n, This program displays the prime number between 1 and 100. #include <​iostream> using namespace std; int isPrimeNumber(int); int main() { bool isPrime;​  This prime numbers generator is used to generate the list of prime numbers from 1 to a number you specify. Prime Number. A prime number (or a prime) is a natural number that has exactly two distinct natural number divisors: 1 and itself. For example, there are 25 prime numbers from 1 to 100: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43

You can use the below given code to find the sum of first prime numbers between 1 to 100. It will give you correct output.

public class PrimeNumber {
    public static void main(String args[]){
        int number = 2;
        int sum = 0;
        while(number <= 100){ 
            if(isPrimeNumber(number)){
                sum += number;
            }
            number++;
        }
        System.out.println(sum);
    }

    private static boolean isPrimeNumber(int number){
        int sqrt = (int) Math.floor(Math.sqrt(number));
        for(int i = 2; i <= sqrt; i++){
            if(number % i == 0){
                return false;
            }
        }
        return true;
    }
}

C Program to Print Prime Numbers from 1 to 100, This program finds prime numbers from 1 and 100. Next, it is going to add those numbers to find the sum of all prime numbers between 1 and 100 in C. /* C  Here prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself.Here is source code of the C# Program to Display All the Prime Numbers Between 1 to 100.

import java.util.Scanner;
public class Trial{
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        boolean flag = false;
        int max = 1000001;
        long[] a = new long[max];
        a[0] = 2;
        int i = 3,j=0;
        long sum = 2;
        int t = in.nextInt();
        for(int a0 = 0; a0 < t; a0++){
            long sum1 = 0;
            int n = in.nextInt();
            if(n>=i){
            while(i<=n){
                for(int y=0;a[y]<=Math.sqrt(i);y++){
                    if(a[y]==0){
                       break;
                    }
                    else if (i%a[y]==0){
                       flag = true;
                       break;
                    }
                }
                if(!flag){
                   a[++j]=i;
                   sum+=i;
                }
                flag =false;
                i+=2;
            }
            System.out.println(sum);
         }
         else{
            for(int y=0;a[y]<=n&&a[y]!=0;y++){
                sum1+=a[y];
            }
            System.out.println(sum1);
           }
        }
     }
  }

here i stored prime numbers in an array if there is any query for the numbers which are already present in the array first 'if' statement will handle it and simple the sum upto that no. will be printed.This will save a lot time to recalculate the prime numbers and find their sum.

Write a program to print prime numbers between 1 to 100, Write a program to find sum of all prime numbers between 1 to n. Examples: Input : 10 Output : 17 Explanation : Primes between 1 to 10 : 2, 3, 5, 7. Input : 11  Rules to Write a C program − All lines of C statements must end with a semicolon. − C is case-sensitive. That is, uppercase and lowercase characters are different. Usually, the statements are typed in lowercase. − A C Program statement can be split into many lines or can be written in one line

Program to Print All Prime Numbers between 1 to 100 in Java by , Here are all the primes from [math]1[/math] to [math]100[/math] [math]2,3,5,7,11 can write the code such c, c++, java to first find the prime numbers & then add all in most programming languages or quickly done in Excel for limited ranges. Prime numbers from 1 to 100 are : 2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 Program to display prime numbers from 1 to n. It will display all the prime numbers between 1 and n (n is the number, entered by user).

Java Program to Print All Prime Numbers between 1 to 100, If numberToCheck is prime, we return true. In the main method, check isPrime is TRUE and add to primeNumbersFound String; Lastly, print the  How to display prime numbers between 1 to 100 using Java Code Program Logic: The main method contains a loop to check prime numbers one by one. The main method calls the method CheckPrime to determine whether a number is prime; We need to divide an input number, say 17 from values 2 to 17 and check the remainder. If the remainder is 0 number is

Program to find sum of prime numbers between 1 to n , Write a Python Program to print Prime numbers from 1 to 100, or 1 to n, or minimum to maximum with example. In this Python program, we also calculate the sum of prime numbers from 1 to n. TIP: I suggest you refer to the Prime Number article to understand the Python logic. This python program prints the prime numbers from 1 to 100.

Comments
  • I think you're finding the first 100 prime numbers, instead of the primes between 1 and 100.
  • You are finding the first 100 primes, Not primes from 1-100. Change the while to while (number < 100)
  • As a side note, you can stop your for loop at i <= Math.sqrt(i), although you should calculate that once before entering the loop.
  • @bpgeck but when I tried to get know the sum of 1000 prime number it will give correct output?uh quite suprising
  • when compare to for loop while loop is much faster
  • @Ramasamy Any evidence for that assertion? It will iterate through all the numbers regardless, whether it is a while or a for loop. And the requirement ensures that we HAVE TO go through each number from 2 to 100. And a for loop is designed for that purpose. If it could end earlier, then a while loop would be better, but it can't end earlier than the 100 mark.
  • Didn't downvote but it looks like your answer was just what people already commented. Seems like you just copied them.
  • He is not looking for a sum of first 100 prime numbers but of the prime numbers which are less than 100. I did not downvote though.
  • But see your explanation: "find the sum of first 100 prime numbers"
  • Yeah, sorry for that. Edited now.