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I try to find address of this pointer, but this code is showing a strange error:

#include <iostream>
using namespace std;
class Base
{
    public:
        void test()
        {
            void *address_of_this =&this;
            cout<<address_of_this<<endl;
        }
};

int main()
{   Base k;
    k.test();

    return 0;
}   //error non-lvalue in unary'&'   

Can you explain this error ? Also point that what is illegal in taking address of this?

this is a pointer containing the address to the "current object". It is not a variable that is stored somewhere (or could even be changed), it is a special keyword with these properties.

As such, taking its address makes no sense. If you want to know the address of the "current object" you can simply output:

std::cout << this;

or store as

void* a = this;

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Quoting the 2003 C++ standard:

5.1 [expr.prim] The keyword this names a pointer to the object for which a nonstatic member function (9.3.2) is invoked. ... The type of the expression is a pointer to the function’s class (9.3.2), ... The expression is an rvalue.

5.3.1 [expr.unary.op] The result of the unary & operator is a pointer to its operand. The operand shall be an lvalue or a qualified_id.

To put it simply, & requires an lvalue. this is an rvalue, not an lvalue, just as the error message indicates.

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Comments
  • Try adding a space after the = sign
  • Finally.. the voice of reason.
  • In standardese: this is an rvalue (and not of class type), so it doesn't have an address.
  • In Standardese again, this is prvalue - pure-rvalue.