How to print an enumerated list (with the char) without separating the characters

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I've been killing my mind to solve the following but i just cannot seem to find the right expression. The code is the following:

nameList = ['j', 'a', 'm', 'e', 's']
for index, i in enumerate(nameList):
    print(___________ , sep='x', end = '')

The thing that needs to be done is to fill in the gap with an expression between the index and i, that will end up printing 0j1a2m3e4s. I have tried multiple things but I just seem to be stuck right here.

Any help or tips are highly appreciated.

Using enumerate with format:

nameList = ['j', 'a', 'm', 'e', 's']
for index, i in enumerate(nameList):
    print('{}{}'.format(index, i), end = '')

# 0j1a2m3e4s

Or without format:

nameList = ['j', 'a', 'm', 'e', 's']
for index, i in enumerate(nameList):
    print(str(index) + i, end = '')

How to print array/ list without brackets in python?, I want to print a list in python without the square brackets. It is always I want to separate a single column from a dataframe and print the output as an array.Need help. How to print first character of each word in upper case of a string in Python. You can how do i use the enumerate function inside a list? I want to print the all the characters from A to Z to display using for loop. How can I print a list of characters in a string using a for loop? Do you want

We can use itertools.chain.from_iterable to flatten the enumerate, then use the empty string '' to separate those characters.

from itertools import chain

nameList = ['j', 'a', 'm', 'e', 's']
print(*chain.from_iterable(enumerate(nameList)), sep='')
# 0j1a2m3e4s

7. Strings, The reason is that there is no 6th letter in "banana". Since we started counting at zero, the six letters are numbered 0 to 5. To get the last character, we have to  I have to admit that template code has a certain look to it that makes it harder to read if one is not used to it. Additionally my code forces the programmer to write each enumerator about 3 times for initialization (in the enumeration, in the enumerated list and in the enumerated array constructor parameter) which is a bit annoying.

You can use a string.join statement to achieve this:

print "".join(str(index) + i for index, i in enumerate(nameList))

>>> 0j1a2m3e4s

11. Lists, Lists are similar to strings, which are ordered collections of characters, except the syntax for accessing the characters of a string — the index operator: [] (not to be through the loop, the variable i is used as an index into the list, printing the i'​th delimiter: A character or string used to indicate where a string should be split​. Even once you generate all the characters, you'll find it's not an effective test. Some of the characters are combining marks, which means they will combine with the next character to come after them - having a string full of combining marks won't make much sense. There are other special cases too.

Why not just

print(''.join('{}{}'.format(index, i) for index, i in enumerate(nameList))

or even better in python 3.6

print(''.join(f'{index}{i}' for index, i in enumerate(nameList))

Lists - Learn Python 3, A change in the number of students in the class must not require modification of the A list is a sequence of elements numbered from 0, just as characters in the string. 1. 2. 3. 4. a = []. for i in range(int(input())): a.append(int(input())). print(a) List items can be given in one line separated by a character; in this case, the  Given a string, write a Python program to split the characters of the given string into a list. This approach uses for loop to convert each character into a list. Just enclosing the For loop within square brackets [] will split the characters of word into list. Python provides direct typecasting of string into list using list ().

Strings, The second statement extracts the character at index position 1 from the fruit variable Since we started counting at zero, the six letters are numbered 0 to 5. its way backwards to the first character in the string, printing each letter on a separate Python has a function called dir that lists the methods available for an object. How to separate characters, Numbers and Special characters from given string. How to separate characters, Numbers and Special characters from given string. How to separate characters

Python 3 Notes: Split and Join, Even though it is a sentence, the words are not represented as discreet units. .​split() splits mary on whitespce, and the returned result is a list of words in mary. Whitespace characters include space ' ', the newline character '\n', and tab '\t', print(chom) colorless green ideas >>> chom.split() ['colorless', 'green', 'ideas']  Expand the Split by character group, and select one of the predefined delimiters or type any other character in the Custom box. Choose whether to split cells to columns or rows. Review the result under the Preview section, and click the Split button.

Iterate over characters of a string in Python, Let's see how to iterate over characters of a string in Python. Example #1: Using simple Iterate over the string. for i, v in enumerate (string_name):. print (v)  Attempts to parse TheDay as a string, and will either print out garbage or crash. printf is not typesafe and trusts you to pass the right value to it. To print out the name of the value, you'd need to create some method for mapping the enum value to a string - either a lookup table, giant switch statement, etc.

Comments
  • You need to format index and i — ask G....e for python format — moreover, I'd recommend to use the name letter (or similar) in place of i.
  • Another possibility consists in simply printing your variables using the null string "" as the separator used by print (the correct syntax is already shown in the template you're following...)
  • This does work but i am not allowed to change the format. All i need is to find an expression between index and i, such as index*i (which is not correct, but you get the idea).
  • Use print(str(index) + i, end = '').
  • Also upvote other answers if you find them helpful. They are equally good. :)